Tugas BAJA I
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Transcript of Tugas BAJA I
MAWARDI
“Berbagi ilmu demi kemajuan Indonesia”
Soal:
Menghitung Luas Penampang Kotor (Bruto):
Abr = Atot = L . t
Abr = Atot = (320 mm) . (12 mm).
Abr = Atot = 3.840 mm2.
Menghitung 85% ×××× Luas Penampang Kotor (Bruto):
85% . Abr = 85% . (3.840 mm2).
85% . Abr = 3.264 mm2.
Menghitung Luas Penampang Bersih (Netto):
Potongan I-I atau II-II
Anet = Abr – (n1 . dlob . t)
Anet = (3.840 mm2) – [1 . (25 mm) . (12 mm)].
Anet = (3.840 mm2) – (300 mm2).
Anet = 3.540 mm2.
I
I II
II
MAWARDI
“Berbagi ilmu demi kemajuan Indonesia”
Potongan AC atau DE
Anet = Abr – (n1 . dlob . t)
Anet = (3.840 mm2) – [2 . (25 mm) . (12 mm)].
Anet = (3.840 mm2) – (600 mm2).
Anet = 3.240 mm2.
Potongan ABE atau CBD
Anet = Abr – (n1 . dlob . t) + ΣΣΣΣ[(n2 . S2 . t) / (4 . u)]
Anet = (3.840 mm2) – [3.(25 mm).(12 mm)] + [(1.(90 mm)2.(12 mm))/(4.(100 mm))]
Anet = + [(1.(80 mm)2.(12 mm))/(4.(100 mm))].
Anet = (3.840 mm2) – (900 mm2) + (243 mm2) + (192 mm2).
Anet = 3.375 mm2.
Potongan ABC atau DFE
Anet = Abr – (n1 . dlob . t) + ΣΣΣΣ[(n2 . S2 . t) / (4 . u)]
Anet = (3.840 mm2) – [3.(25 mm).(12 mm)] + [(2.(90 mm)2.(12 mm))/(4.(100 mm))].
Anet = (3.840 mm2) – (900 mm2) + (486 mm2).
Anet = 3.426 mm2.
Potongan DBE
Anet = Abr – (n1 . dlob . t) + ΣΣΣΣ[(n2 . S2 . t) / (4 . u)]
Anet = (3.840 mm2) – [3.(25 mm).(12 mm)] + [(2.(80 mm)2.(12 mm))/(4.(100 mm))].
Anet = (3.840 mm2) – (900 mm2) + (384 mm2).
Anet = 3.324 mm2.
Jadi Luas Penampang Netto yang efektif adalah pada Potongan AC atau
Potongan DE, besarnya Anet = 3.240 mm2.
Syarat:
Anet ≥≥≥≥ (85% . Abr)
3.240 mm2 < 3.264 mm2 � Tidak memenuhi syarat.