Lampiran Praktikum Utama

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Perhitungan Data Hasil Praktikum mmolek H 2 O 2 = M . V . val = 0,04 x 5 x 2 = 0,4 mmolek mmolek KI = M . V . val = 0,1 x 10 x 1 = 1 mmolek mmolek Na 2 S 2 O 3 = M . V . val = 0,001 x 1 x 1 = 0,001 mmolek (pereaksi pembatas) mmolek H 2 O 2 yang bereaksi = mmolek Na 2 S 2 O 3 [ ] M [ ] Mencari Nilai ln K [ ] [ ] 1. t = 14,0 s 7,14 x 10 -3 ln K = -4,9417 4. t = 6,5 s 0,015 ln K = -4,1745

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Kimia Fisika

Transcript of Lampiran Praktikum Utama

Page 1: Lampiran Praktikum Utama

Perhitungan Data Hasil Praktikum

mmolek H2O2 = M . V . val

= 0,04 x 5 x 2

= 0,4 mmolek

mmolek KI = M . V . val

= 0,1 x 10 x 1

= 1 mmolek

mmolek Na2S2O3 = M . V . val

= 0,001 x 1 x 1

= 0,001 mmolek (pereaksi pembatas)

mmolek H2O2 yang bereaksi = mmolek Na2S2O3

[ ]

M

[ ]

Mencari Nilai ln K

[ ]

[ ]

1. t = 14,0 s

7,14 x 10

-3

ln K = -4,9417

4. t = 6,5 s

0,015

ln K = -4,1745

Page 2: Lampiran Praktikum Utama

2. t = 12,0 s

8,33 x 10

-3

ln K = -4,7876

5. t = 5,0 s

0,020

ln K = -3,9121

3. t = 9,0 s

0,011

ln K = -4,4999

6. t = 4,0 s

0,025

ln K = -3,6889

Mencari Nilai

1. T = 283,0 K

=

4. T = 298,0 K

2. T = 288,0 K

0,003472

5. T = 303,0 K

= 0

3. T = 293,0 K

3

6. T = 308,0 K

Page 3: Lampiran Praktikum Utama

Persamaan y

y = -4587,1 x + 11,202

y = mx + b

m = -4587,1

Maka m = - Ea/R

Ea = - ( m x R )

= - (-4587,1 x 8,314)

= 38137,1494 J/mol = 38,1371494 kJ/mol

b = intercept = ln A = 11,202

y = -4587.1x + 11.202 R² = 0.9909

-6

-5

-4

-3

-2

-1

0

0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 0.0035 0.00355

ln K

1/T

Hubungan antara 1/T dan ln K