kalkukus lanjutt
2
TUGAS KLASIBER KALKULUS 2, Sabtu 29 Maret 2014 Pec ahka nlah siste m pers amaan linear (CAR I HARGA KOEFISI EN) dari pers amaan linear berikt ini ! " #$ % #" & ' #' " #$ & ' #" % #' $$ " #$ % " #" & #' ' *a+ab! 2 - 1 3 2 1 3 -1 = 11 2 -2 5 3 • = ((2.3.5)+(-1.-1.2)+(3.1.-2))-((2.3. 3)+(-2.-1.2)+(5.1.-1)) = ((30+2-6)-(18+4-5)) = 9 2 -1 3 11 3 -1 3 -2 5 1 = ((2.3.5)+(-1.-1.3)+(3.11.-2))-((3.3.3 )+(-2.-1.2)+(5.11.-1)) =((30+3-66)-(27+4-55)) = -9 2 2 3 1 11 -1 2 3 5 2 = ((2.11.5)+(2.-1.2)+(3.1.3))-((2.11.3)+ (3.-1.2)+(5.1.2)) = ((110-4+9)-(66-6+10)) = 45
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Transcript of kalkukus lanjutt
TUGAS KLASIBER KALKULUS 2, Sabtu 29 Maret 2014Pecahkanlah sistem persamaan linear (CARI HARGA KOEFISIEN) dari persamaan linear berikut ini :
2 x1 x2 + 3 x3 = 2
x1 + 3 x2 x3 = 11
2 x1 2 x2 + 5x3 = 3
Jawab:
2-13
213-1 =
11
2-25
3
= ((2.3.5)+(-1.-1.2)+(3.1.-2))-((2.3.3)+(-2.-1.2)+(5.1.-1))
= ((30+2-6)-(18+4-5))
= 9
2-13
113-1
3-25
1= ((2.3.5)+(-1.-1.3)+(3.11.-2))-((3.3.3)+(-2.-1.2)+(5.11.-1))
=((30+3-66)-(27+4-55))
= -9
223111-1
235
2= ((2.11.5)+(2.-1.2)+(3.1.3))-((2.11.3)+(3.-1.2)+(5.1.2))
= ((110-4+9)-(66-6+10))
= 452-12
1311
2-23
3= ((2.3.3)+(-1.11.2)+(2.1.-2))-((2.3.2)+(-2.11.2)+(3.1.-1))
= ((18-22-4)-(12-44-3))
= 27x1 = 1
x2 = 2
x3 = 3 -9
45 27 = 9
= 9
= 9 =-1
= 5
= 3
CROSS CEK 2 x1 x2 + 3 x3= 2
((2.-1) (5) + (3.3)= 2-2-5+9
= 2 benar
