Hasil Pengamatan Dan Analisis Data Tekanan Hidro

7/25/2019 Hasil Pengamatan Dan Analisis Data Tekanan Hidro

1/22

HASIL PENGAMATAN DAN ANALISIS DATA

Tabel hasil pengamatan

Tabel 1. Massa jenis zat cair

No. Jenis zat cair Massa (gram) Volume (ml)123

AirMinya!liserin

|97,400,05|

|85,400,05|

|125,400,05|

|1002,5|

|1002,5|

|1002,5|

"egiatan 1. #engaruh e$alaman terha$ap teanan hi$rostati

Jenis zat cair % air

Tabel 2. Hubungan antara keala!an zat cair engan tekanan "ir#statik

No. "e$alaman (cm) #erbe$aan etinggian zat cair pa$a pipa & (cm)1

2

3

'

*

|1,800,05|

|2,0000,05|

|2,500,05|

|3,000,05|

|3,5000,05|

|4,000,05|

|1,500,05|

|1,600,05|

|1,600,05|

|1,800,05|

|1,700,05|

|1,800,05|

|2,400,05|

|2,300,05|

|2,400,05|

|2,600,05|

|2,700,05|

|2,700,05|

|2,900,05|


2/22

|4,500,05|

|3,000,05|

|3,000,05|

|3,200,05|

|3,300,05|

|3,300,05|

|3,400,05|

|3,400,05|

|3,500,05|

"egiatan 2. #engaruh massa +enis zat cair $engan teanan hi$rostati

"e$alaman % |3,000,05| cm

Tabel $. Hubungan antara !assa jenis zat cair engan tekanan "ir#statik

No.Massa +enis zat cair

(gr,ml)#erbe$aan etinggian zat cair pa$a pipa & (cm)

1

2

3

Air |0,974|

Minya |0,854|

!liserin |1,254|

|2,600,05|

|2,700,05|

|2,700,05|

|2,300,05|

|2,200,05|

|2,300,05|

|3,000,05|


3/22

|3,100,05|

|3,000,05|

ANALISIS DATA

1. Analisis #erhitungana. Massa %enis Air

=m

v

mv1

=m

v=

97,40g

100cm3=0,974 g /cm

3

d=| m|dm+| v|dv d=v

1dm+m v

2dv

d

=

v1

mv1dm+

mv2

mv1dv

d=|dmm + dv

v|

=| mm + vv|

=| 0,05gram97,40gram+ 12,5 cm3

100cm3 |0,974 g /cm3

=|0,00051+0,125|0,974 g/cm3


4/22

=0,12551x 0,974g /cm3

=0,12225g /cm3

KR=

X100

KR=0,12225 g /cm3

0,974 g/cm3 X100

KR=12,551 2 Anga -erarti

"% 1//0 1210 % *''40

=| |

=|0,970,12| g,cm3

b. Massa %enis Min&ak

=m

v

mv1

=m

v=

85,40g

100cm3=0,854 g /cm

3

=| mm + vv|

=| 0,05gram85,40gram+ 12,5 cm3

100cm3 |0,854 g /cm3

=|0,0006+0,125|0,854g /cm3

=0,1256x0,854 g /cm3

=0,10726g /cm3

KR=

X100


5/22

KR=0,10726 g /cm3

0,854 g/cm3 X100


"% 1//0 120 % *''0

=| |

=|0,850,10| g,cm3

c. Massa %enis Gliserin

=mv

mv1

=m

v=

125,40 g

100cm3=1,254 g /cm

3

=| mm + vv|

=

| 0,05

gram125,40 gram+12,5

cm

3

100cm3

|1,254 g/cm

3

=|0,0004+0,125|1,254g /cm3

=0,1254x1,254 g /cm3

=0,15725g /cm3

KR=

X100

KR=0,15725 g /cm3

1,254g /cm3 X100


"% 1//0 12'0 % *'0

=| |


6/22

=|1,250,15| g,cm3

'egiatan 1

1. 5ata rata etinggian

(ntuk keala!an |1,800,05|cm

h=(1,50+1,60+1,60 )cm

3=1,57cm

h1 |1,501,57|cm=0 ,07 cm

h2 |1,601,57|cm=0,03 cm

h3 |1,601,57|cm=0 ,03c m

KR= h

h X100

KR=0,07 cm

1,57 cmX100


"% 1//0 ''40 % 4'1 0

h=|h h|

h=|1,570,07| c!

P= gh

P=(0,974 g

cm3 )(980

cm

s2 ) (1,57 cm)

P= 1'44 g,c m s2

dP=| P |d+| P h|dh


7/22

dP

P=|g h d gh|+|g dhgh|

dP

P=|d|+|dhh|

P=| + hh|P

P=|0,12225 g/c m3

0,974 g /c m3 +

0,07 cm

1,57 cm| 1'44 g,c m s2 P=|0,12551+0,04459| 1'44 g,c m s2

P=0,1701 6 1'44 g,c m s2

P=254,91 g,c m s2 % 2'41 kg /ms2

P= 1498,59 g,c m s2 % 1'44 kg /ms2

KR= P

P x 100

KR=25,491kg/ms

2

149,859 kg/ms2x 100


DK=10017,01=82,99

P=

|P P|

P=|1,490,25|102 kg/ms2


h=(1,80+1,70+1,80 )cm

3=1,76 cm


8/22

h1 |1,801,76|cm=0 ,04cm

h2 |1,701,76|cm=0 ,06 cm

h3 |1,801,76|cm=0 ,04cm

KR= h

hX100

KR=0,06 cm

1,76 cmX100


"% 1//0 3'0 % 4 0

h=|h h|

h=|1,760 ,06| c!

P= gh

P=(0,974 g

cm3 )(980

cm

s2 ) (1,76 cm)

P=1679,95 g,c m s2

P=| + hh|P

P=

|0,12225 g/c m

3

0,974 g /c m3 +

0,06cm

1,76cm

| 1679,95

g,c

m

s

2

P=|0,12551+0,03409| 1679,95 g,c m s2

P=0,1596 6 1679,95 g,c m s2

P=268,12 g,c m s2 % 212 g, ms2

P= 1679,95g /c m s2=167,995kg/ms2


9/22

KR= P

P x 100

KR= 26,812 kg/ms2

167,995 kg/ms2x 100


DK=10015,96=84,04

P=|P P|

P=|1,670,26|102 kg/ms2

(ntuk keala!an)2*+, - ,*,+)

h=(2,40+2,30+2,40 ) cm

3=2,36 cm

h1 |2,402,36|cm=0,04 cm

h2 |2,302,36|cm=0 ,06cm

h3 |2,402,36|cm=0,04 cm

h= hmas% // cm

KR= h

h X100

KR=0,06 cm

2,36 cmX100


"% 1//0 2' 0 % 4*' 0

h=|2,360,06| c!

P= gh


10/22

P=(0,974 gcm3 )(980cm

s2 ) (2,36 cm)

P= 222 g,c m s2

P=| + hh|P

P=|0,12225 g/c m3

0,974 g /c m3 +

0,06cm

2,36cm| 222g,c m s2

P=|0,12551+0,02542| 222g,c m s2

P=0,15093 6 222 g,c m s2

P=339,99 g,c m s2 % 33444 g, ms2

P= 2252,66g /c ms 2=225,266 kg /ms2

KR= P

P x 100

KR= 33,999 kg/ms

2

225,266 kg/ms2x 100


DK=10015,09=84,91

P=|P P|

P=|2,250,33|10 2 kg /ms2


h=(2,60+2,70+2,70 ) cm

3=2,66cm

h1|2,602,66|cm=0 ,06cm


11/22

h2 |2,702,66|cm=0 ,04 cm

h3 |2,702,66|cm=0 ,04 cm

h= //

KR= h

h X100

KR=0,06 cm

2,66 cmX100

K R=2 ,25 2 Anga -erarti

"% 1//0 220 % 4** 0

h=|h h|

h=|2,660,06| c!

P= gh

P=(0,974 g

cm3 )(

980cms2 ) (

2,66 cm)

P= 234/2 g,c m s2

P=| + hh|P

P=

|

0,12225 g/c m3

0,974 g/

c m

3 +

0,06cm

2,66cm

|234/2 g,c m s2

P=|0,12551+0,02256| 234/2 g,c m s2

P=0,14807 6 234/2 g,c m s2

P=375,95 g,c m s2 % 3*4 kg /ms2

P= 2539,02g /cm s2=253,902kg /ms2


12/22

KR= P

P x 100

KR= 37,595kg/ms2

253,902 kg/ms2x100


DK=10014,80=85,20

P=|P P|

P=|2,530,37|10 2 kg /ms2


h=(2,90+3,00+3,00 ) cm

3=2,96 cm

h1 |2,902,96|cm=0 ,06cm

h2 |3,002,96|cm=0,04 cm

h3 |3,002,96|cm=0 ,04 cm

h= //

KR= h

h X100

KR=

0,06 cm

2,96 cmX100

KR=2 3 Anga -erarti

"% 1//0 2 0 % 4 0

h=|h h|

h=|2,960,06| c!


13/22

P= gh

P=(0,974 g

cm3 )(980

cm

s2 ) (2,96 cm)

P= 223* g,c m s2

P=| + hh|P

P=

|0,12225 g/c m

3

0,974 g /c m3 +

0,06cm

2,96cm

| 223* g,c m

s2

P=|0,12551+0,02027| 223*g,c m s2

P=0,14578 6 223* g,c m s2

P=411,88 g,c m s2 % '11 kg /ms2

P= 2825,37g /c m s2=282,537 kg/ms2

KR= P

P x 100

KR= 41,188kg /ms2

282,537 kg /ms2x 100


DK=10014,57=85,43

P=|P P|

P=|2,820,41|10 2 kg /ms2

(ntuk keala!an |4 ,000,05|cm

h=(3,20+3,30+3,30 )cm

3=3,26 cm


14/22

h1 |3,203,26|cm=0 ,06cm

h2 |3,303,26|cm=0 ,04 cm

h3 |3,303,26|cm=0 ,04cm

h= //

KR= h

h X100

KR=

0,06 cm

3,26 cmX100

KR=1 3 Anga -erarti

"% 1//0 10 % 440

h=|h h|

h=|3,260,06| c!

P= gh

P=(0,974 gcm3 )(980cm

s2 ) (3,26 cm)

P= 3111*3 g,c m s2

P=| + hh|P

P=|0,12225 g/c m3

0,974 g /c m3 +

0,06cm

3,26cm| 3111*3 g,c m s2 P=|0,12551+0,0184| 3111*3 g,c m s2

P=0,14391 6 3111*3 g,c m s2

P=447,80 g,c m s2% ''*/ kg /ms2


15/22

P= 3111*3 g,c m s2 311,173kg /ms2

KR= PP

x 100

KR= 44,780kg/ms2

311,173kg /ms2x100


DK=10014,39=85,61

P=|P P|

P=|3,110 ,44| 1,2 kg /ms2

(ntuk keala!an |4 ,500,05|cm

h=(3,40+3,40+3,50 )cm

3=3,43 cm

h1 |3,403,43|cm=0,03 cm

h2 |3,403,43|cm=0,03 cm

h3 |3,503,43|cm=0,07 cm

h= hmas% //* cm

KR=

h

h X100

KR=0,07 cm

3,43 cmX100

KR=2 3 Anga -erarti

"% 1//0 2 0 % 4 0

h=|h h|


16/22

h=|3,430,07| c!

P= gh

P=(0,974 gcm3 )(980cm

s2 ) (3,43 cm )

P= 32*' g,c m s2

P=| + hh|P

P=|0,12225 g/c m3

0,974 g /c m3 +

0,07 cm

3,43 cm| 32*' g,c m s2 P=|0,12551+0,02041| 32*' g,c m s2

P=0,14592 6 32*'g,c m s2

P=477,74 g,c m s2 % '***' kg /ms2

P= 3274n g/c m s 2% 327,4 kg /ms2

KR= P

P x 100

KR=47,774 kg/ms

2

327,4kg /ms2

x100


DK=10014,59=85,41

P=|P P|

P=|3,270,47|10 2 kg /ms2

"egiatan 2. #engaruh massa +enis zat cair terha$ap teanan hi$rostati

"e$alaman73// 8 //7cm


17/22

Massa jenis air 0,974 gc!$

h= (2,60+2,70+2,70 ) cm3

=2,66 cm

h1 |2,602,66|cm=0,06 cm

h2 |2,702,66|cm=0,04 cm

h3 |2,702,66|cm=0,04 cm

h=

//

KR= h

h X100

KR=0,06 cm

2,66 cmX100

K R=2,25 2 Anga -erarti

"% 1//0 220 % 4** 0

h=|h h|

h=|2,660,06| c!

P= gh

P=(0,974 gcm3 )(980cm

s2 ) (2,66 cm)

P= 234/2 g,c m s2

P=| + hh|P

P=|0,12225 g/c m3

0,974 g /c m3 +

0,06cm

2,66cm| 234/2 g,c m s2 P=|0,12551+0,02256|

234/2 g,c m

s2


18/22

P=0,14807 6 234/2 g,c m s2

P=375,95 g,c m s2 % 3*4 kg /ms2

P= 2539,02g /cm s2=253,902kg /ms2

KR= P

P x 100

KR= 37,595kg/ms2

253,902 kg/ms2x100


DK=10014,80=85,20

P=|P P|

P=|2,530,37|10 2 kg /ms2

Massa jenis !in&ak ,*/+0 gc!$

h=(2,30+2,20+2,30 ) cm

3=2,26 cm

h1 |2,302,26|cm=0,04cm

h2 |2,202,26|cm=0 ,06 cm

h3 |2,302,26|cm=0 ,04 cm

h= //

KR= h

h X100

KR=0,06 cm

2,26 cmX100

KR=2 3 Anga -erarti


19/22

"% 1//0 2 0 % 4 0

h=|h h|

h=|2,260,06| cm

P= gh

P=(0,854 gcm3 )(980cm

s2 ) (2,26 cm)

P= 141'3 g,c m s2

P=| + hh|P

P=|0,10726 g /c m3

0,854 g /c m3 +

0,06cm

2,26cm| 141'3 g,c m s2 P=|0,1256+0,02655| 141'3 g,c m s2

P=0,15215 6 141'3g,c m s2

P=287,78 g,c m s2 % 2** kg /ms2

P= 141'3 g,c m s2 189,143kg/ms2

KR= P

P x 100,

KR= 28,778 kg/ms

2

189,143 kg/ms2x 100


DK=10015,21=84,79

P=|P P|

P=|1,890,28|10 2 kg /ms2


20/22

Massa jenis gliserin 1*2+0 gc!$

h=

(3,00+3,10+3,00 )cm3 =3,03cm

h1 |3,003,03|cm=0,03 cm

h2 |3,103,03|cm=0,07 cm

h3 |3,003,03|cm=0,03 cm

h= //*

KR= h

h X100

KR=0,07 cm

3,03 cmX100

KR=2 3 Anga -erarti

"% 1//0 20 % 40

h=|h h|

h=|3,030,07| cm

P= gh

P=(1,254 gcm3 )(980cm

s2 )(3,03 cm )

P=

3*232 g,c m s2

P=| + hh|P

=|0,15725g /cm3

1,254 g /cm3 +

0,07 cm

3,03 cm|3723,62g /cm2

=|0,1254+0,0231|3723,62g/cm2


21/22

=0,1485x 3723,62 g /cm2

P=552,95 g,c m s2% 24 kg /ms2

P= 3723,62

g

cms2=372,362 kg /ms

2

K R= P

P x 100

KR= 55,295 kg/ms2

372,362kg /ms2x100


DK=10014,85=85,15

P=|P P|

P=|3,720,55| 1/2 kg /ms2

PEMAHASAN

#a$a egiatan pertama yaitu pengaruh e$alamam zat cair terha$ap teanan hi$rostatia$apun perban$ingan hasil yang $i $apatan saat pratium $engan analisis $ata yaitu9Tabel 0. Hasil analisis ata kegiatan 1 34engaru" keala!an5

No. "e$alaman (cm) Teanan hi$rostati kg /ms2

1 |1,800,05| |1,490,25|102

2 |2,000,05| |1,670,26|102

3 |2,500,05| |2,250,33|10 2

' |3 ,000,05| |2,530,37|10 2

|3,500,05| |2,820,41|10 2

|4 ,000,05| |3,110,44| 1/2

* |4,500,05| |3,270,47|10 2


22/22

:eperti yang terlihat pa$a tabel ' yang menggambaran hasil $ari egiatan 1 $imanatingat e$alamannya itu berbe$a setiapalinya $an hal itu berpengaruh terha$ap

besarnya Teanan ;i$rostati yang ter$apat pa$a corong. ;al ini men+elasan bah

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