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  • 7/31/2019 Garis Netral

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    PORTAL TENGAH MEMANJANG L.1 PROFIL INP

    fc' = 24 Mpa L = 560 cm

    E. Baja = Mpa bo= 670 cm

    E. Beton = 4700 fc' = Mpa

    be = 140 cm

    Data profil INP -

    Ix = cm4 ts = 12 cm ts = 12 cm

    h = cm (tebal plat)

    As = cm2 h = 17.3 cm

    bf = cm

    garis netral

    h = 42.5 cm 27.3 cm

    1/2h cm

    bf = 16.3 cm

    - Lebar effektif (be)

    be= 1/4.L

    = 1/4 . 560

    = 140 cm

    be = bo(jarak antar balok) = 670 cm

    Be = bf + 16.ts = cm

    diambil beff = 140 cm

    n =

    =

    = 8.69 ------

    Ac = be . Ts Ac

    = 140 x 12 n

    = cm2 = cm2

    At = As + be

    = 132 + 140= cm2

    dt = 1/2. h + 1/2.ts Ic = 1/12 . (beff/n) . 10^3

    = 1/2 x 42.5 + 1/2x 12 = 1 140 10 ^3

    = cm 12 9

    dc = = cm4

    = It = Ic + (Ac . dc^2) + Ix + (As . ds^2)

    = cm4

    = cm

    ds = (beff/At) . Dt

    =

    = x 10^-6

    = cm

    =E

    7/10/2012 3:35

    200000

    23025

    42 1/2

    E. Baja

    E. Beton

    200000

    23025

    1680

    208.3

    42 1/2

    36970

    42.5

    132

    16.3

    Ac(eq) =

    21.3

    272.0

    27.25

    9.0

    x

    =1680

    9

    186.7

    272.0x 27.25

    14.03

    x

    1296.2963

    358033.88

    358033.88

    560

    272.0x 27.25

    13.22

    140

    132

    (As/At) . dt

    10^-4

    6.393

    =K = 639.34621 cm3

    639.34621

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    PORTAL TEPI B &c MEMANJANG L.2 (ATAP DAG) PROFIL INP

    fc' = 24 Mpa L = 560 cm

    E. Baja = Mpa bo= 540 cm

    E. Beton = 4700 fc' = Mpa

    be = 46.67 cm

    Data profil INP -

    Ix = cm4 ts = 10 cm ts = 10 cm

    h = cm (tebal plat)

    As = cm2 h = 21.2 cm

    bf = cm

    garis netral

    h = 38.0 cm 24.0 cm

    1/2h cm

    bf = 14.9 cm

    - Lebar effektif (be)

    be= 1/12.L

    = 1/12 . 560

    = 46.7 cm

    be = bo(jarak antar balok) = 540 cm

    Be = bf + 16.ts = cm

    diambil beff = 47 cm

    n =

    =

    = 8.69 ------

    Ac = be . Ts Ac

    = 46.7 x 10 n

    = cm2 = cm2

    At = As + be

    = 107 + 46.7

    = cm2

    dt = 1/2. h + 1/2.ts Ic = 1/12 . (beff/n) . 10^3

    = 1/2 x 38.0 + 1/2x 10 = 1 46.7 10 ^3

    = cm 12 9

    dc = = cm4

    = It = Ic + (Ac . dc^2) + Ix + (As . ds^2)

    = cm4

    = cm

    ds = (beff/At) . dt

    =

    = x 10^-6

    = cm= E

    38

    200000

    23025

    7/10/2012 3:3538

    38

    24010

    107

    14.9

    19.0

    174.9

    E. Baja

    200000

    23025

    Ac(eq) ==

    466.666667

    9

    466.666667 51.9

    x x

    2.865

    9.0

    16.71

    K =160454.11

    = 286.5251946.6666667

    x 24560

    (As/At) . dt 432.09877

    107x 24

    153.7 286.52519

    7.29 10^-4

    cm3

    153.7 160454.11

    153.7

    24

    E. Beton