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    JEMBATAN KOMPOSIT

    profil IWFdiafragma

    trotoir beton K-300 t = 0.20 maspal tebal 0.05 m

    1,200,75 1,20 1,20 1,20 1,20 1,20 1,20 0,75

    POTONGAN MELINTANG

    bo bo bo bo bo bo bo

    D E N A H

    diafragma

    IWF-900.300.15.23

    8.4

    0m

    9.4

    0m

    1.20

    1.20

    1.20

    1.20

    1.20

    1.20

    trotoir

    trotoir

    B

    diafragma sambngan

    POTONGAN MEMANJANG

    18.00 m

    -3 8

    L

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    nk

    AcAce

    .=

    Ac : luas beton

    Ace : luas beton ekivalen

    As : luas profl baja

    n : EsEck : !aktor pe"bebanan

    k" # $ k% # &

    Ac # be ' tc

    At # As ( Ace

    )t # )s ( )c

    GARI* NETRAL K+,-+*IT

    ds = dt dc

    Yc = dc + tc Ys = ds +

    Momen Inersia Komposit :

    It = Ie!s"# $o%&os"tIs = Ie!s"# &!o' b##

    dtAt

    Asdc =

    22.

    .. dcAce

    nk

    IcdsAsIsIt +++=

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    ANALI*A BEBAN

    &. /EA/ L+A/

    a. -ri"er1* e!#t sed"!" &!o'/,e#,#!/b#o-2* e!#t beto/#t#" -ed#!##.* e!#t s#%b,# d (d"#%b" +0 be!#t ,e#,#!)

    b. *ekun)er

    Satuan (kg/m)

    1* 3o%e %#-s"%%4 (tengah bentang)2* 5 %#-s"%%4 (tumpuan)

    1*e!#t &e!-e!#s#/#s (teb# +7%)2* e!#t #"! h# (teb# +8%).* L#"92 (b"# #d#)

    Satuan (kg/m)

    1* 3o%e %#-s"%%4 (tengah bentang)

    2* 5 %#-s"%%4 (tumpuan)

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    $. BEBAN ANGIN

    a b b b perletakan

    h2

    h1

    Beban angin W = 100 kg/m2

    Tinggi bidang angin untuk lalulintas diasumsikan sebesar 2,00 m daripermukaan trotoir

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    R = R1+ R2h# = 2 + h1

    ..2/1!2 2

    haRXi

    Xiqa

    =

    1*3o%e %#-s"%%4 (tengah bentang)2*5 %#-s"%%4 (tumpuan)

    eb# #," d# ,e#,#! te!#!:

    h#

    2%

    h1

    x1

    b bR1

    R2

    R

    6a

    b

    x2

    x.

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    TEGANGAN GE*ERTEGANGAN GE*ER

    Ixt

    SxD

    .

    .=

    *ebelu" Ko"posit(3#t": beto b##)

    *etela% Ko"posit(3#t" : As #"! h#)

    *etela% Ko"posit(eb# h"d& LL : P < ;)

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    7N-R+--E/7N-R+--E/*ebelu" Ko"posit(3#t": beto b##)

    *etela% Ko"posit(3#t" : As #"! h#)

    *etela% Ko"posit(eb# h"d& LL : P < ;)

    gms

    gmp

    A B

    +9

    ,%&L

    ,%&L

    +

    9 ,%sL

    ,%sL

    -q

    +9

    ; L

    P+ ; L

    -q

    X L-X

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    7N-R+--E/7N-R+--E/

    1. "emasangan gelagar pro#il ba$a A BT

    M1= 1/8 gs. L2s

    SW

    M11 = 01 = L

    +

    gnc

    gnkmgns

    gnkh=

    +

    +

    2. Beton lantai kendaraan

    M2= 1/8 g. L2

    A BT

    02 =

    s

    SW

    M2

    2 =

    %. Lapisan perkerasanA B

    TM!= 1/8 ga. L

    2

    k"

    S"S

    I

    #M .%

    %=

    k""

    "

    Ink

    #M

    ..

    .%

    % =

    +

    &. Beban lalu lintas kendaraan, muatan '

    M$= 1/8 q . L2% 1/$ . &.L

    A BT

    kh

    ShS

    I#M .&& =

    khh

    h

    Ink#M...&& =

    + =

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    1. "ro#il ba$a ( beton lantai kendaraan !keras

    ( perkerasan dipikul komposit mati

    -R+--E/-R+--E/

    M1= 1/8 'gs % gc% ga( . L2

    k"

    S"S

    I

    #M .11 =

    k""

    "

    Ink

    #M

    ..

    .1

    1 =

    A BT

    gnc

    gnkmgns

    gnkh=

    +

    9

    2. Beban lalu lintas kendaraan, muatan '

    M2= 1/8 q . L2% 1/$ . &.L

    A BT

    kh

    ShS

    I

    #M .2

    2 =khh

    h

    Ink

    #M

    ..

    .2

    2 =

    +

    +

    9

    =

    +

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    G#># ,ese! ho!"sot# >#, t"%b #t#!# t(slab) beto d# b#o- b## h#!s d"t#h# #,#!&e#%, -o%&os"t be-e!# sec#!# %oo"t*

    ?t- %e#%" #d#># e-#t# #t#!# s#bbeto d# b#o- b## %#-# h#!s d"s#, ##t&e>#%b, ,ese! (shear connector) d"#t#sb#o- b## >#, be!hb,# de,# s#b

    beto*5"s#%&", "t f,s" d#!" shear connector

    #d##h t- %e#h#/ %e,h"d#!"te!#,-#t># s#b beto -et"-# d"beb#"*

    ALAT -EN8A,B7NG GE*ER

    (SHEAR CONNECTOR)

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    9ENI* -EN8A,B7NG GE*ER9ENI* -EN8A,B7NG GE*ER

    a/ )ngker diagonal

    b/ *tud/ paku

    +/ "asak kanal

    d/ *piral

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    d ) = A . t

    Dengan*

    ) = ga+a gese, ik ntk 1'sat( anke, 'kg(

    A = as ena"ang anke, 'c"2(

    t = tegangan i0in ta,ik anke, 'kg/c"2(

    hd

    ....&,0 2

    12d) =

    Dengan*

    ) = ga+a gese, ik ntk 1'sat( std '3s(d = dia"ete, std 'inch(

    h = tinggi std 'inch(

    4c = kat tekan 3et5n 'si(

    c = "5ds eastisitas 3et5n 'si(

    a/ Angker diagonal

    b/ Stud/ paku

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    hd

    c/ Pasak kanal = 3/t) ...%0

    Dengan*

    ) = ga+a gese, ik ntk asak 'kg(

    t = te3a ,5i kana 'c"(

    3= tegangan i0in 3et5n 'kg/c"2(

    h = 67 d = 97 ) = 1:;2< t5nh = $7 d = 7 ) = 8;:< t5n

    h = !7 d = !/87 ) = 6;

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    diafragma sambngan

    POTONGAN MEMANJANG

    18.00 m

    -3 8

    L

    p r o f i l I W Fd i a f r a g m a

    t r o t o i r b e t o n K - 3 0 0 t = 0 . 2 0 ma s p a l t e b a l 0 . 0 5 m

    1 , 2 00 , 7 5 1 , 2 0

    1 , 2 0 1 , 2 0 1 , 2 0

    1 , 2 0 1 , 2 0 0 , 7 5

    e

    N OZ

    e

    bo

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