Report - pembahasan SBMPTN 2014 OK · 2015-05-18 · Bahasan : x 2 + x2 1 ≤ 2 x – 4 2x2 + 1 ≤ 0 (x2– 1) ≤ 0 x – 2 1 = 0 x 1 = 1 menyediakan x 2 = -1 {-1, 1} 08. Jawaban : D Bahasan

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