Download - Solution to HWP05.01

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Hence we get the x- and y-components of the surface paramtzn fctn as:

05.01-1HWP 05.01Introduction: Constructing the Surface Parameterization Function

05.01-2

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2

05.01-3

2

(a) Infinitesimal increment vectors

2

2

05.01-4(b) Infinitesimal surface area vector

See drawing above, showing -vector in the F -plane, attached to a point on the paraboloid surface. The infinitesimal increment vectors are also shown at the same surface point.

Corr190401:

Corr190401:

05.01-5+x2 ]

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(c) 05.01-5

05.01-6

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,ayq'sirr fi-dir".tinl l-rygyses fkc siJ t r i t4|.e J . S O

05.01-7

Route I:

(d)

(*)

(*) Note: After shrinking HQ to zero, the -vectors on the"flattened" paraboloid, P(HQ), are pointing in the (+z)-direction, i.e., into the volumeV, as shown in the drawing above. But the surface Q is required to have its -vectors pointing out of the volumeV. That's why the -vectors on surface Q must be reversed relative to the -vectorson the flattened P(HQ)-surface.

V

V

RouteII:Wewillusetheresultsforparameterizationofacirculardiskshowninthethein-classexamplefile,postedontheHWProblemspageofthecoursewebsite:

hw05R_P3900_SurfaceIntgr+Stokes_Pt1_CircDisk_V01.pdf.Pleasereviewthisexampleand,inparticular,payattentiontothefiguresshowninthisexample.Inthefollowing,wewillrefertothisfile,andtheexampleshowntherein,asโ€œCDโ€,forshort.

ThesurfaceQisacirculardiskofradiusRinthex-y-planecenteredatthecoordinateorigin,i.e.,withacenter๐‘ = ๐‘#๐‘%๐‘& = [000].TheparameterizationfunctionforthisdisksurfacegiveninCDis:

๐‘Ÿ ๐‘ , ๐œ™ = ๐‘ฅ ๐‘ , ๐œ™ , ๐‘ฆ ๐‘ , ๐œ™ ,๐‘ง ๐‘ , ๐œ™ = ๐‘  cos ๐œ™ ,๐‘  sin ๐œ™ ,0 ,withintegrationintervals

0 โ‰ค ๐‘  โ‰ค ๐‘…and0 โ‰ค ๐œ™ < 2๐œ‹.

Theinfinitesimalincrementvectorsof๐‘Ÿ ๐‘ , ๐œ™ aregiveninCDas๐‘‘<๐‘Ÿ = ๐œ•<๐‘Ÿ ๐‘ , ๐œ™ ๐‘‘๐‘  = cos ๐œ™ ,sin ๐œ™ ,0 ๐‘‘๐‘ 

and๐‘‘>๐‘Ÿ = ๐œ•>๐‘Ÿ ๐‘ , ๐œ™ ๐‘‘๐œ™ = [โˆ’๐‘  sin ๐œ™ ,๐‘  cos ๐œ™ ,0]๐‘‘๐œ™.

Wewanttheareaelementvectors๐‘‘๐‘Žtopointinthe(โˆ’๐‘ง)-direction:thisisthedirectionpointingoutwardfromthevolumeV,enclosedbetweentheparabolicdomesurfacePandthecirculardisksurfaceQ.Therefore,asshownindetailinCD,wemustchoosethecrossproductoftheinfinitesimalincrementvectors(with๐‘‘๐‘  > 0and๐‘‘๐œ™ > 0)as

๐‘‘๐‘Ž = ๐‘‘>๐‘Ÿ ร— ๐‘‘<๐‘Ÿ AsshowninCD,thiswillgiveus

๐‘‘๐‘Ž = 0, 0, โˆ’๐‘  ๐‘‘๐‘ ๐‘‘๐œ™whichdoesindeedpointinthe(โˆ’๐‘ง)-direction,asrequired.This๐‘‘๐‘Žcorrespondstoacrossproductofthepartialderivatives

๐œ•>๐‘Ÿ ๐‘ , ๐œ™ ร— ๐œ•<๐‘Ÿ ๐‘ , ๐œ™ = 0, 0, โˆ’๐‘ whichwewillusebelowtocarryoutthesurfaceintegrationviatheparametrizationequation.

Compoundingthegivenintegrandvectorfield,๐น(๐‘Ÿ),withthetheparameterizationfunction๐‘Ÿ ๐‘ , ๐œ™ ,weget

05.01-8

๐น ๐‘Ÿ ๐‘ , ๐œ™ = ๐‘ฅ ๐‘ , ๐œ™ ๐‘ฆ ๐‘ , ๐œ™ ,๐‘ฆ ๐‘ , ๐œ™ ๐‘ง ๐‘ , ๐œ™ ,๐‘ง ๐‘ , ๐œ™ ๐‘ฅ ๐‘ , ๐œ™ + ๐‘ฅ ๐‘ , ๐œ™ G

= ๐‘ Gsin ๐œ™ cos ๐œ™ ,0,๐‘ GcosG ๐œ™ ,makinguseofthefactthat๐‘ง ๐‘ , ๐œ™ = 0everywhere.

The ๐‘ , ๐œ™ -integrandintheparameterizationequationforthesurfaceintegral(seebelow)isthengivenby

๐‘“ ๐‘ , ๐œ™ โ‰”๐น ๐‘Ÿ ๐‘ , ๐œ™ โˆ™ ๐œ•>๐‘Ÿ ๐‘ , ๐œ™ ร— ๐œ•<๐‘Ÿ ๐‘ , ๐œ™

= ๐น& ๐‘Ÿ ๐‘ , ๐œ™ ๐œ•>๐‘Ÿ ๐‘ , ๐œ™ ร— ๐œ•<๐‘Ÿ ๐‘ , ๐œ™&

= ๐‘ GcosG ๐œ™ โˆ’๐‘ = โˆ’๐‘ KcosG ๐œ™ .

Notethatthevectorfieldcomponents๐น# ๐‘Ÿ ๐‘ , ๐œ™ and๐น% ๐‘Ÿ ๐‘ , ๐œ™ donotcontributetotheintegrand๐‘“ ๐‘ , ๐œ™ ,nortoitsintegral,sincethe๐‘ฅ-and๐‘ฆ-componentsofthepartialderivativecrossproductarezero.

Bytheparameterizationequationforthesurfaceintegral,wehave๐‘‘๐‘Ž โˆ™ ๐น(๐‘Ÿ)

L = ๐‘‘๐‘ MN ๐‘‘๐œ™GO

N ๐น ๐‘Ÿ ๐‘ , ๐œ™ โˆ™ ๐œ•>๐‘Ÿ ๐‘ , ๐œ™ ร— ๐œ•<๐‘Ÿ ๐‘ , ๐œ™

= ๐‘‘๐‘ MN ๐‘‘๐œ™GO

N ๐‘“ ๐‘ , ๐œ™ =โˆ’ ๐‘‘๐‘ M

N ๐‘ K ๐‘‘๐œ™GON cosG ๐œ™

Usinganintegraltable,wefind๐‘‘๐œ™GO

N cosG ๐œ™ = ๐œ‹.Hence,

๐‘‘๐‘Ž โˆ™ ๐น(๐‘Ÿ)L = โˆ’๐œ‹ ๐‘‘๐‘ M

N ๐‘ K

=โˆ’๐œ‹ PQ๐‘ Q

N

M

= โˆ’OQ๐‘…Q

05.01-9

(e) Integral over the entire closed surface S 05.01-10

By given Concatenation Theorem for surface integrals:

Insert results for P- and Q-integral from parts (c) and (d):

q.e.d.

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05.0205.02-1

the

This is illustrated in the two figures on the next page: Please review and make sure you understand them!

is again perpendicular to the F -plane, just as for the

are just concentric circles around the z-axis; and so are lines of constant s and constant z in the volume V.

. This is due to the fact that lines of constant s on the P-surface

05.02-2

05.02-3

05.02-2

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05.02-4

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Substitute: u := s/R, -> s = Ru, ds = Rdu

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see HWP5.01 (e)

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