Tugas Anstruk 3 - Cover & No 1

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TUGAS ANALISA STRUKTUR Nama Dosen Pengajar : Ir. F. X. Ferry Munaf MT. Nama Ma!as"s#a : Ase$ Su%ra NPM : &'( &'( )**+ PR,GRAM K-LAS R-GUL-R K 

description

ANALISA STRUKTUR

Transcript of Tugas Anstruk 3 - Cover & No 1

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TUGAS

ANALISA STRUKTUR

Nama Dosen Pengajar :Ir. F. X. Ferry Munaf MT.

Nama Ma!as"s#a : Ase$ Su%ra

NPM : &'( &'( )**+

PR,GRAM K-LAS R-GUL-R K 

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FAKULTAS T-KNIK SIPIL

S-M-ST-R GASAL TAUN AKAD-MI

UNI1-RSITAS PAN2ASIL

AKARTA

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  3

 

a%

 

USUS

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K '*(& / '*(0

 

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1. Suatu rangka batang statis tertentu dibebani muatan terpusat dengan ketentuan

 sebagai berikut :

P = 250 kg

a = 3.00 m

h= 2.00 m

Ditanyakan : Hitung besarnya gaya batang dengan menggunakan metode fe!ibiitasP P

C 2 D 3 B

1 " # $ % 2.00

A & E 5 F

P P& m & m 3 m

Penyeesaian:

sin ' = 0.55%"

' (os ' = 0.#321

1) . Gaya P = 1 di titik C, D, E & F

! y )

C 2 D 3 B

1 " # $ % 2

A & E 5 F

! y )

& m & m 3 m

a. *eseimbangan +uar

, ! = 0 0 - /

0 500.00 - /

0 500.00 - /

b. *eseimbangan daam : - (ara keseimbangan titik /

S1 sin ' S1

, = 0

0

' S&   S1 = -901.39 kg (Tekan)

A S1 (os '

4

H =, 6

4=

 =

, 6=

4 =

 7 8itik

 9 S1 sin ' =

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, = 0

S& 9 S1 (os ' = 0

  S = !"0.00 kg (Ta#ik)

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P = 250

!

C S2 7 4atang S2 di titik

D1 S" 2 m 0

d  S$ = -11$".00

A S& E

! ! 7 4atang S& di titik ;

& m

0

d = 5."2 m  S = !"0.00

7 4atang S" di titik D

. 3<2 ! P. ! S& .h S" d =

 S! = $$.11

P = 250

y

C S2 D

S# 2 m

S5

A & E y F

P = 250

! 1<2 !

& m 3 m

7 4atang S5 di titik D

0

S" = 11$".00 kg (Ta#ik)

7 4atang S# di titik >

0

S% = 0.00 kg

7 4atang S2 di titik

0

 7 Potongan

, 6 = 0

 . ! P . 1<2! 9 S2 h =

, 6 = 0

 .1<2! S& h =

, 6 = 0

 7 Potongan

, 6 = 0

 . 3<2! P . ! P 1<2! S5 h =

, 6 = 0

 . 2! P 3<2! P .! 9 S2. h9 S#. d =

, 6 = 0

 . ! P. 1<2! 9 S2 . h=

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S$ = -11$".00 kg (Tekan)

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P = 250 P = 250

C D ) S3 B

S$ 2 m

S5

A E ) F

P = 250

& m & m 3 m

7 4atang S3 di titik >

0

S3 = -!"0.00 kg (Tekan)

7 4atang S$ di titik 4

0

S$ = 2&2.11 kg -8ekan/

S3 S% (os ' B'

2 m

S% S% sin '

, = 0

0

  S = 901.39 kg (Tekan)

, = 0

S3 S% (os ' = 0

  S3 = -!"0.00 kg (Ta#ik)

' Batang Ta#ik - Tekan

1 S1 $01.3$

2 S2 1125.00

3 S3 "50.00

% S% $01.3$

 7 Potongan ? ?

, 6 = 0

 . 2! P . 3<2! P . ! P . 1<2! 9 S3 h =

, 6 = 0

 . 5<2! P . 2! P . ! P . 1<2! S5 h S$ . d=

4

4  S% sin ' =

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5 S5 1125.00

& S& "50.00

" S" 2&2.11

# S# 0.00

$ S$ 2&2.11

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m

m

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kg (Tekan)

kg (Ta#ik)

0

kg (Ta#ik)

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$) . Pe*+e#ian gaya P = 1 atan di titik C

P = 1 atan

! y )

C 2 D 3 B

1 " # $ % 1.#

A & E 5 F

! y )

3.# m 3.# m 1.$ m

a. *eseimbangan +uar

, ! = 0 0 - /0 0.#0 - /

0 0.20 - /

b. *eseimbangan daam : - (ara keseimbangan titik /

S1 sin ' S1

, = 0

0

' S&   S1 = -1.1 kg (Tekan)

A S1 (os '

, = 0

S& 9 S1 (os ' = 0

  S = 0.% kg (Ta#ik)

4

H =, 6

4=

 =

, 6=

4 =

 7 8itik

 9 S1 sin ' =

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P = 1 satuan

!

C S2 7 4atang S2 di titik

D1 S" 1.# m 0

d  S$ = -0.3

A S& E

! ! 7 4atang S& di titik ;

3.#m

0

d = 3.5" m  S = 0.%

7 4atang S" di titik D

. 3<2 ! P. ! S& .h S" d =

 S! = -0.$1

P = 1 satuan

y

C S2 D

S# 1.# m

A & E S5 F

y

! 1<2 !

3.# m 1.$ m

7 4atang S5 di titik D

0

S" = 0.$$$$$$$$$ kg (Ta#ik)

7 4atang S# di titik >

0

S% = 0.$1 kg (Ta#ik)

7 4atang S2 di titik

0

 7 Potongan

, 6 = 0

 . ! P . 1<2! 9 S2 h =

, 6 = 0

 .1<2! S& h =

, 6 = 0

 7 Potongan

, 6 = 0

 . 3<2! P . ! S5 h =

, 6 = 0

 . 2! P 3<2! 9 S2. h9 S#. d =

, 6 = 0

 . ! P. 1<2! 9 S2 . h=

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S$ = -0.3 kg (Tekan)

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P = 1 satuan

)

C D S3 B

S$ 1.# m

S5

A E F

)

3.# m 3.# m 1.$ m

7 4atang S3 di titik >

0

S3 = -0.$1 kg (Tekan)

7 4atang S$ di titik 4

0

S9 = -0.$1 kg (Tekan)

S3 S% (os ' B'

1.#m

S% S% sin '

, = 0

0

  S = 0.$9 kg (Tekan)

, = 0

S3 S% (os ' = 0

  S3 = -0.$1 kg (Ta#ik)

@o 4atang 9 8arik 8ekan

1 S1 1.1&

2 S2 0.&3

3 S3 0.21

% S% 0.2$

 7 Potongan ? ?

, 6 = 0

 . 2! P . 3<2! 9 S3 h =

, 6 = 0

 . 5<2! P . 2! S5 h S$ . d=

4

4  S% sin ' =

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5 S5 0.%222222222

& S& 0.#%

" S" 0.21

# S# 0.21

$ S$ 0.21

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m

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kg (Tekan)

kg (Ta#ik)

0

kg (Tekan)

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3) . Pe*+e#ian gaya P = 1 atan di titik D

P= 1 atan

! y )

C 2 D 3 B

1 " # $ % 1.#

A & E 5 F

! y )

3.# m 3.# m 1.$ m

a. *eseimbangan +uar

, ! = 0 0 - /

0 0.%0 - /

0 0.&0 - /

b. *eseimbangan daam : - (ara keseimbangan titik /

S1 sin ' S1

, = 0

0

' S&   S1 = -0."% kg (Tekan)

A S1 (os '

, = 0

S& 9 S1 (os ' = 0

  S = 0.$ kg (Ta#ik)

4

H =

, 64=  =, 6

=

4 =

 7 8itik

 9 S1 sin ' =

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!

C S2 7 4atang S2 di titik

D1 S" 1.# m 0

d  S$ = -0.%

A S& E

! ! 7 4atang S& di titik ;

3.#m

0

d = 3.5" m  S = 0.$

7 4atang S" di titik D

. 3<2 ! S& .h S" d =

 S! = 0.3

y

C S2 D

S# 1.# m

A & E S5 F

y

! 1<2 !

3.# m 1.$ m

7 4atang S5 di titik D

0

S" = 1.$! kg (Ta#ik)

7 4atang S# di titik >

0

S% = -0.3 kg (Tekan)

7 4atang S2 di titik

 7 Potongan

, 6 = 0

 . ! 9 S2 h =

, 6 = 0

 .1<2! S& h =

, 6 = 0

 7 Potongan

, 6 = 0

 . 3<2! S5 h =

, 6 = 0

 . 2! 9 S2. h9 S#. d =

, 6 = 0

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0

S$ = -0.% kg (Tekan)

 . ! 9 S2 . h=

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P = 1 satuan

)

C D S3 B

S$ 1.# m

S5

A E F

)

3.# m 3.# m 1.$ m

7 4atang S3 di titik >

0

S3 = -0.3 kg (Tekan)

7 4atang S$ di titik 4

0

S9 = -0. kg (Tekan)

S3 S% (os ' B'

1.#m

S% S% sin '

, = 0

0

  S = 0.%! kg (Ta#ik)

, = 0

S3 S% (os ' = 0

  S3 = -0.3 kg (Tekan)

@o 4atang 9 8arik 8ekan

1 S1 0.5#

2 S2 0.#%

3 S3 0.&3

% S% 0.#"

 7 Potongan ? ?

, 6 = 0

 . 2! P . 1<2! 9 S3 h =

, 6 = 0

 . 5<2! P . ! S5 h S$ . d=

4

4  S% sin ' =

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5 S5 1.2&&&&&&&&"

& S& 0.%2

" S" 0.%3

# S# 0.%3

$ S$ 0.&%

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m

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kg (Tekan)

kg (Ta#ik)

0

kg (Ta#ik)

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) . Pe*+e#ian gaya P = 1 atan di titik F

! y )

C 2 D 3 B

1 " # $ % 1.#

A & E 5 F

! y ) P= 1

3.# m 3.# m 1.$ m

a. *eseimbangan +uar

, ! = 0 0 - /

0 0.20 - /

0 0.#0 - /

b. *eseimbangan daam : - (ara keseimbangan titik /

S1 sin ' S1

, = 0

0

' S&   S1 = -0.$9 kg (Tekan)

A S1 (os '

, = 0

S& 9 S1 (os ' = 0

  S = 0.$1 kg (Ta#ik)

4

H =

, 64=  =, 6

=

4 =

 7 8itik

 9 S1 sin ' =

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!

C S2 7 4atang S2 di titik

D1 S" 1.# m 0

d  S$ = -0.$

A S& E

! ! 7 4atang S& di titik ;

3.#m

0

d = 3.5" m  S = 0.$1

7 4atang S" di titik D

. 3<2 ! S& .h S" d =

 S! = 0.$1

y

C S2 D

S# 1.# m

A & E S5 F

y

! 1<2 !

3.# m 1.$ m

7 4atang S5 di titik D

0

S" = 0.333333333 kg (Ta#ik)

7 4atang S# di titik >

0

S% = -0.$1 kg (Tekan)

7 4atang S2 di titik

 7 Potongan

, 6 = 0

 . ! 9 S2 h =

, 6 = 0

 .1<2! S& h =

, 6 = 0

 7 Potongan

, 6 = 0

 . 3<2! S5 h =

, 6 = 0

 . 2! 9 S2. h9 S#. d =

, 6 = 0

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0

S$ = -0.$ kg (Tekan)

 . ! 9 S2 . h=

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)

C D S3 B

S$ 1.# m

S5

A E F

)

3.# m 3.# m 1.$ m

7 4atang S3 di titik >

0

S3 = -0.% kg (Tekan)

7 4atang S$ di titik 4

0

S9 = 0.$1 kg (Ta#ik)

S3 S% (os ' B'

1.#m

S% S% sin '

, = 0

0

  S = 1.1 kg (Ta#ik)

, = 0

S3 S% (os ' = 0

  S3 = -0.% kg (Tekan)

@o 4atang 9 8arik 8ekan

1 S1 0.2$

2 S2 0.%2

3 S3 0.#%

% S% 1.1&

 7 Potongan ? ?

, 6 = 0

 . 2! 9 S3 h =

, 6 = 0

 . 5<2! S5 h S$ . d=

4

4  S% sin ' =

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5 S5 0.&333333333

& S& 0.21

" S" 0.21

# S# 0.21

$ S$ 0.21

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m

atan

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kg (Tekan)

kg (Ta#ik)

0

kg (Ta#ik)

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") . Pe*+e#ian gaya P = 1 atan di titik E

! y )

C 2 D 3 B

1 " # $ % 1.#

A & E 5 F

! y )

P= 1 atan

3.# m 3.# m 1.$ m

a. *eseimbangan +uar

, ! = 0 0 - /

0 0.&0 - /

0 0.%0 - /

b. *eseimbangan daam : - (ara keseimbangan titik /

S1 sin ' S1

, = 0

0

' S&   S1 = -0.%! kg (Tekan)

A S1 (os '

, = 0

S& 9 S1 (os ' = 0

  S = 0.3 kg (Ta#ik)

4

H =

, 64=  =, 6

=

4 =

 7 8itik

 9 S1 sin ' =

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!

C S2 7 4atang S2 di titik

D1 S" 1.# m 0

d  S$ = -1.$!

A S& E

! ! 7 4atang S& di titik ;

3.#m

0

d = 3.5" m  S = 0.3

7 4atang S" di titik D

. 3<2 ! S& .h S" d =

 S! = 0.

y

C S2 D

S# 1.# m

A & E S5 F

y

P = 1 satuan

! 1<2 !

3.# m 1.$ m

7 4atang S5 di titik D

0

S" = 0.% kg (Ta#ik)

7 4atang S# di titik >

0

S% = 0.3 kg (Ta#ik)

7 4atang S2 di titik

 7 Potongan

, 6 = 0

 . ! 9 S2 h =

, 6 = 0

 .1<2! S& h =

, 6 = 0

 7 Potongan

, 6 = 0

 . 3<2! P .1<2 ! S5 h =

, 6 = 0

 . 2! P.! 9 S2. h9 S#. d =

, 6 = 0

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0

S$ = -1.$! kg (Tekan)

 . ! 9 S2 . h=

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)

C D S3 B

S$ 1.# m

S5

A E F

)

P = 1 satuan

3.# m 3.# m 1.$ m

7 4atang S3 di titik >

0

S3 = -0.$ kg (Tekan)

7 4atang S$ di titik 4

0

S9 = -0.3 kg (Tekan)

S3 S% (os ' B'

1.#m

S% S% sin '

, = 0

0

  S = 0."% kg (Ta#ik)

, = 0

S3 S% (os ' = 0

  S3 = -0.$ kg (Tekan)

' Batang Ta#ik - Tekan

1 S1 0.#"

2 S2 1.2"

3 S3 0.%2

% S% 0.5#

 7 Potongan ? ?

, 6 = 0

 . 2! P . ! 9 S3 h =

, 6 = 0

 . 5<2! P . 3<2! S5 h S$ . d=

4

4  S% sin ' =

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5 S5 0.#%%%%%%%%%

& S& 0.&3

" S" 0.&%

# S# 0.%3

$ S$ 0.%3

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m

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kg (Tekan)

kg (Ta#ik)

0

kg (Ta#ik)

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Page 57 of 62

' BatangBe+an a# (P = 1)

P = 1 Sat

C D

Ta#ik - Tekan Ta#ik - Tekan Ta#ik - Tekan

1 S1 0.00 $01.3$ 0.00 1.1& 0.00 0.5#

2 S2 0.00 1125.00 0.00 0.&3 0.00 0.#%

3 S3 0.00 "50.00 0.00 0.21 0.00 0.&3

% S% $01.3$ 0.00 0.2$ 0.00 0.#" 0.00

5 S5 1125.00 0.00 0.%2 0.00 1.2" 0.00

& S& "50.00 0.00 0.#% 0.00 0.%2 0.00

" S" 2&2.11 0.00 0.00 0.21 0.%3 0.00

# S# 0.00 0.00 0.21 0.00 0.00 0.%3

$ S$ 0.00 2&2.11 0.00 0.21 0.00 0.&%

Aaya batang disusun daam bentuk matri! statis B PC

/P/ = 1.1& 0.5# 0.2$ 0.#" S1

0.&3 0.#% 0.%2 1.2" S2

0.21 0.&3 0.#% 0.%2 S3

0.2$ 0.#" 1.1& 0.5# S%

0.%2 1.2" 0.&3 0.#% S5

0.#% 0.%2 0.21 0.&3 S&

0.21 0.%3 0.21 0.&% S"

0.21 0.%3 0.21 0.%3 S#

0.21 0.&% 0.21 0.%3 $ ! % S$

; D >

= 1.1& 0.&3 0.21 0.2$ 0.%2 0.#%

0.5# 0.#% 0.&3 0.#" 1.2" 0.%2

0.2$ 0.%2 0.#% 1.1& 0.&3 0.21

0.#" 1.2" 0.%2 0.5# 0.#% 0.&3

// =   0.02 0 0 0 0 0

0 0.03 0 0 0 00 0 0.03 0 0 0

0 0 0 0.02 0 0

0 0 0 0 0.03 0

0 0 0 0 0 0.03

0 0 0 0 0 0

0 0 0 0 0 0

0 0 0 0 0 0

= 0.021 0.01$ 0.00& 0.005 0.013 0.0250.010 0.025 0.01$ 0.01& 0.03# 0.013

0.005 0.013 0.025 0.021 0.01$ 0.00&

/PT/

/P/T

 //

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0.01& 0.03# 0.013 0.010 0.025 0.01$

/F/ = // /P/

0.0&# 0.0&3 0.03& 0.0"&

0.0&3 0.121 0.0"& 0.105

0.03& 0.0"& 0.0&# 0.0&30.0"& 0.105 0.0&3 0.121 % ! %

/P/T

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2 = 1.2

1.2

1.2

1.2 % 1

D = /F/ 2

0.2$ - /

0.%% - /

0.2$ - /

0.%% - /

Aaya 4atang BHC

/4/ = /P/ 2

3.%$

3.#0 =

2.53

3.%$

= 3.#0 8on

2.53

1.2#

0.00

1.2#

H1

D1

H2

D2

H3

D3

H%

D%

H5

H&

H"

H#

H$

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  an di Titik

Tta5F E

Ta#ik - Tekan Ta#ik - Tekan

0.00 0.2$ 0.00 0.#" 2.$1

0.00 0.%2 0.00 1.2" 3.1"

0.00 0.#% 0.00 0.%2 2.11

1.1& 0.00 0.5# 0.00 2.$1

0.&3 0.00 0.#% 0.00 3.1"

0.21 0.00 0.&3 0.00 2.11

0.21 0.00 0.&% 0.00 1.0"

0.00 0.21 0.%3 0.00 0.00

0.21 0.00 0.00 0.%3 1.0"

0.21 0.21 0.21

0.%3 0.%3 0.&%

0.21 0.21 0.21

0.&% 0.%3 0.%3 % ! $

0 0 0

0 0 00 0 0

0 0 0

0 0 0

0 0 0

  0.02 0 0

0 0.02 0

0 0 0.02 $ ! $

0.00% 0.00% 0.00%0.00# 0.00# 0.012

0.00% 0.00% 0.00%

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0.012 0.00# 0.00# % ! $

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0.2$ - /

0.%% - / (m

0.2$ - /

0.%% - /