Rekayasa Pondasi(3)

12
Rekayasa Pondasi Diketahui konstruksi tembok penahan tipe Gravity wall dengan data-data sebagai berkut : - Beban merata permukaan q = t/m 2 - Tinggi tembok penahan H = m - Tebal lapisan tanah 1 H 1 = m - Kedalaman muka air dari puncak H a = m - Tinggi tanah didepan tembok H 2 = m - Sudut kemiringan permukaan tembok b = o - Sudut gesek antara tembok dengan tanah d = o - Berat isi tanah lapisan 1 g 1 = t/m 3 - Berat isi tanah terendam lapisan 1 g' 1 = t/m 3 - Berat isi tanah terendam lapisan 2 g' 2 = t/m 3 - Sudut gesek dalam tanah lapisan 1 f' 1 = o - Sudut gesek dalam tanah lapisan 2 f' 2 = o - Berat isi pasangan batu g' p = t/m 3 - Berat isi beton bertulang g' b = t/m 3 1. Merencanakan dimensi pondasi sesuai persyaratan yang ada 2.50 2.20 1.76 0.85 0.89 20.00 PENYELESAIAN III. Tembok Penahan 3.00 5.00 3.50 1.50 2.50 5.55 25.00 29.00 H H 2 H 1 H a 2 2 3 3 1 1 B Created by ANCHA 08

Transcript of Rekayasa Pondasi(3)

Page 1: Rekayasa Pondasi(3)

Rekayasa Pondasi

Diketahui konstruksi tembok penahan tipe Gravity wall dengan data-data sebagai berkut :

- Beban merata permukaan q = t/m2

- Tinggi tembok penahan H = m

- Tebal lapisan tanah 1 H1 = m

- Kedalaman muka air dari puncak Ha = m

- Tinggi tanah didepan tembok H2 = m

- Sudut kemiringan permukaan tembok b = o

- Sudut gesek antara tembok dengan tanah d = o

- Berat isi tanah lapisan 1 g1 = t/m3

- Berat isi tanah terendam lapisan 1 g'1 = t/m3

- Berat isi tanah terendam lapisan 2 g'2 = t/m3

- Sudut gesek dalam tanah lapisan 1 f'1 = o

- Sudut gesek dalam tanah lapisan 2 f'2 = o

- Berat isi pasangan batu g'p = t/m3

- Berat isi beton bertulang g'b = t/m3

1. Merencanakan dimensi pondasi sesuai persyaratan yang ada

2.50

2.20

1.76

0.85

0.89

20.00

PENYELESAIAN

III. Tembok Penahan

3.00

5.00

3.50

1.50

2.50

5.55

25.00

29.00

H

H2

H1

Ha

2 2

3

3 1

1

B

Created by ANCHA 08

Page 2: Rekayasa Pondasi(3)

Rekayasa Pondasi

b = o

a = o

d = o

g1 = t/m3

g'1 = t/m3

g'2 = t/m3

f'1 = o

f'2 = o

g'b = t/m3

Keterangan :

H = Tinggi tembok penahan = m

Ha = Kedalaman muka air dari puncak = m

H1 = Tebal lapisan tanah 1 = m

H2 = Tinggi tanah didepan tembok = m

Hb = H1 - Ha = m

B = = m

d = = m

Hc = H - H1 - d = m

a = = m

x = ( H - d ) . tan a = m

k = d = m

e = B - ( x + a + k ) = m

H0 = ( e + x ) . tan b = m

g = Ha . tan a = m

i = ( H1 - Ha ) . tan a = m

j = Hb . tan a = m

2. Menghitung tekanan tanah secara analitis

0.83

1.35

2/3 . H

1/6 . H

2.00

0.42

0.36

0.67

0.17

0.13

0.17

0.06

20.00

29.00

2.20

1/12 . H

5.00

1.50

3.50

2.50

3.33

0.83

5.55

25.00

1.76

0.85

5.00

0.89H

H2

H1

Ha

d

B

k x a x e

Ho

Hc

g i j

Hb

Created by ANCHA 08

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Rekayasa Pondasi

a. Menghitung koefisien tekanan tanah

1. Koefisien tekanan tanah aktif

- Untuk lapisan 1

Diketahui : a = o

f1 = o

d = o

b = o

- Untuk lapisan 2

Pada bagian yang miring

Diketahui : a = o

f2 = o

d = o

b = o

Pada bagian yang tegak

Diketahui : a = o

f2 = o

d = o

b = o

Ka2 =

Ka1 =

25.00

5.55

5.55

5.00

25.00

29.00

5.00

20.00

25.000.5335

5.55

0.4102

0.00

29.00Ka3 = 0.3782

H

H2

H1

Ha

d

B

Ho

Hc

Hb

Pa1

Pa2

Pa3

Pa4

Pa5

Pa6 Pa7

Pa8 Pa9

Pp

22

2

a

)cos().cos(

)sin().sin(1).cos(.cos

)(cosK

bada

bfdfdaa

af

Created by ANCHA 08

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Rekayasa Pondasi

2. Koefisien tekanan tanah pasif

Diketahui : a = o

f2 = o

d = o

b = o

b. Menghitung tekanan tanah aktif

akibat pengaruh beban (q) terhadap tanah setinggi H0

s1 =

s1 = t/m2

- Akibat beban (q) terhadap tanah setinggi Ha

s2 =

s2 = t/m2

- Akibat tanah setinggi Ha

s3 =

s3 = t/m2

- Akibat beban (q) dan tanah setinggi Ha terhadap tanah setinggi Hb

s4 =

s4 = t/m2

- Akibat tanah setinggi Hb

s5 = g'1 . Hb . Ka1 + gw . Hb

s5 = t/m2

- Akibat beban (q), tanah setinggi ha, tanah setinggi Hb terhadap tanah

setinggi Hc

s6 = ( q + g1 . Ha + g'1 . Hb ) . Ka2

s6 = t/m2

- Akibat tanah setinggi Hc

s7 = g'2 . Hc . Ka2 + gw . Hc

s7 = t/m2

0.907

3.0109

0.2434

1.6006

g1 . Ha . Ka1

1.4085

Kp =

3.0091

( q + g1 . Ha ) . Ka1

q . Ka1

0.00

29.00

0.00

q . Ka1

1.6006

8.243525.00

22

2

)cos().cos(

)sin().sin(1).cos(.cos

)(cosKp

bada

bfdfdaa

af

Created by ANCHA 08

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- Akibat beban (q), tanah setinggi ha, tanah setinggi Hb, tanah setinggi Hc

terhadap tanah setinggi d

s8 = ( q + g1 . Ha + g'1 . Hb + g'2 . Hc ) . Ka3

s8 = t/m2

- Akibat tanah setinggi d

s9 = g'2 . d . Ka3 + gw . d

s9 = t/m2

b. Menghitung tekanan tanah pasif

sp = g'2. H2 . Kp

sp = t/m2

c. Menghitung gaya tekanan tanah aktif

Pa1= 0,5 x s1 x H0 Pa1= t/m

Pa2= s2 x Ha Pa2= t/m

Pa3= 0,5 x s3 x Ha Pa3= t/m

Pa4= s4 x Hb Pa4= t/m

Pa5= 0,5 x s5 x Hb Pa5= t/m

Pa6= s6 x Hc Pa6= t/m

Pa7= 0,5 x s7 x Hc Pa7= t/m

Pa8= s8 x d Pa8= t/m

Pa9= 0,5 x s9 x d Pa9= t/m

d. Menghitung gaya tekanan tanah pasif

Pp = 0,5 x sp x H2 Pp = t/m

e. Menghitung lengan momen tekanan tanah aktif

za1= (1/3) . H0 + H = m

za2= (1/2) . Ha + Hb + Hc + d = m

za3= (1/3) . Ha + Hb + Hc + d = m

za4= (1/2) . Hb + Hc + d = m

za5= (1/3) . Hb + Hc + d = m

za6= (1/2) . Hc + d = m

za7= (1/3) . Hc + d = m

za8= (1/2) . d = m

za9= (1/3) . d = m

3.0003

0.2805

6.0182

0.907

2.0073

0.0811

18.342

0.1337

2.4009

1.0564

4.250

4.000

2.500

2.167

2.5003

0.1169

22.927

5.056

0.417

0.278

1.167

1.056

Created by ANCHA 08

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f. Menghitung lengan momen tekanan tanah pasif

zp = (1/3) . H2 = m

4. Menghitung berat tanah dan konstruksi

a. Menghitung luas irisan

F1 = (1/2) . H0 . ( x + e ) = m2

F2 = Ha . ( i + j + e ) = m2

F3 = (1/2) . Ha . g = m2

F4 = Hb . ( j + e ) = m2

F5 = (1/2) . Hb . i = m2

F6 = Hc . e = m2

F7 = (1/2) . Hc . j = m2

F8 = ( H - d ) . a = m2

F9 = (1/2) . ( H - d ) . x = m2

F10= F9 = m2

F11= B . d = m2

b. Menghitung berat irisan

0.759

0.759

2.778

0.175

0.903

0.8333

0.144

2.381

0.019

1.736

0.098

2.825

H

H2

H1

Ha

d

B

k x a x e

Ho

Hc

g i j

Hb

1

2

4

6

11

8

9 10

3

5

7

12

A

Created by ANCHA 08

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Rekayasa Pondasi

G1 = F1 . g1 = t/m G7 = F7 . g'2 = t/m

G2 = F2 . g1 = t/m G8 = F8 . gb = t/m

G3 = F3 . g1 = t/m G9 = F9 . gb = t/m

G4 = F4 . g'1 = t/m G10= F10 . gb = t/m

G5 = F5 . g'1 = t/m G11= F11 . gb = t/m

G6 = F6 . g'2 = t/m G12= q . ( x + e ) . sec b = t/m

c. Menghitung lengan momen berat tanah dan konstruksi

x1 = (2/3) . ( x + e ) + a + x + k = m

x2 = (1/2) . ( i + j + e ) + g + a + x + k = m

x3 = (2/3) . g + a + x + k = m

x4 = (1/2) . ( j + e ) + i + g + a + x + k = m

x5 = (2/3) . i + g + a + x + k = m

x6 = (1/2) . e + 2x + a + k = m

x7 = (2/3) . j + i + g + a + x + k = m

x8 = (1/2) . a + x + k = m

x9 = (1/3) . x + a + x + k = m

x10= (2/3) . x + k = m

x11= (1/2) . B = m

x12= (1/2) . ( e + x ) + a + x + k = m

5. Menghitung momen akibat tekanan tanah

Mpa1 = = tm' Mpa6 = = tm'

Mpa2 = = tm' Mpa7 = = tm'

Mpa3 = = tm' Mpa8 = = tm'

Mpa4 = = tm' Mpa9 = = tm'

Mpa5 = = tm' Mpp = = tm'

- = tm'

6. Menghitung momen akibat berat tanah dan konstruksi

Mg1 = = tm' Mg7 = = tm'

Mg2 = = tm' Mg8 = = tm'

Mg3 = = tm' Mg9 = = tm'

Mg4 = = tm' Mg10 = = tm'

Mg5 = = tm' Mg11 = = tm'

Mg6 = = tm' Mg12 = = tm'

tm'

10.185

12.817

S Mg = 53.461

0.295

6.309

G9 . x9

G10 . x10

2.901

1.798

0.034

5.371

0.697

10.644

G7 . x7

G8 . x8

G1 . x1

G2 . x2

G3 . x3

G4 . x4

G11 . x11

G12 . x12

G5 . x5

G6 . x6

0.277

2.134

19.106

2.342

S Mp = S Mpa - S Mpp = 35.617 19.106 16.511

Pp . zp

0.676 Pa6 . za6

Pa7 . za7 0.086

1.042

0.032

10.204

4.226

15.045

Pa2 . za2

Pa3 . za3

Pa4 . za4

Pa8 . za8

Pa9 . za9

Pa5 . za5 1.965

1.406

1.736

1.076

1.667

2.474

Pa1 . za1

2.540

1.702

2.627

1.862

2.656

1.950

6.111

5.181

4.191

0.173

2.401

2.760

0.149

1.671

0.253

0.804

0.017

3.819

1.671

Created by ANCHA 08

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Rekayasa Pondasi

7. Menghitung kestabilan konstruksi

a. Kontrol terhadap guling

b. Kontrol terhadap geser

c. Kontrol terhadap eksentrisitas

e' = (1/6) . B = 0.6

< 0.6 (OK!!!)

d. Kontrol terhadap daya dukung tanah

smax = t/m2

smin = t/m2

qult

Sf

=

D

B

dg = 1.0

( SG + Pa sinb ).tand

S Pa cos b

(OK!!!)

4.0884

0.2692

s ijin tanah =qult = cNcscdcic + qNqsqdqiq + 0,5gBNgsgdgig

( diambil Sf = 3 )

Ng = ( Ng - 1 ) . tan ( 1,4 . f )

e < e'

= 0.2692

2.3162

smax < sijin tanah

11.776

35.257

15.222

> 1.5

(OK!!!)

> 1.5

> 1.5

3.2378 > 1.5

> 1.5

S Mg

S Mp

> 1.553.461

16.511

16.443 ( untuk f = f'2 )

13.237

dq = 1 + 2 tan f(1 - sin f)2 = 1.0676

G

MM

2

Be

pg

S

SS

Ss

B

e.61

B

G

f f

245taneN 2tan

g

Created by ANCHA 08

Page 9: Rekayasa Pondasi(3)

Rekayasa Pondasi

= t/m2

< (OK!!!)

9. Menghitung Momen, gaya geser, gaya normal dan tegangan pada potongan

- Potongan 1 - 1

a. Momen lentur

G1 ((2/3). (e+x)+a+x) + G2 ((1/2). (e+x-g)+g+a+x) + G3 ((2/3).g+a+x)

+ G4 ((1/2). (e+j)+i+g+a+x) + G5 ((2/3).i+g+a+x) + G6 ( (1/2).e+2x+a)

+ G7 ( (2/3) . j+i+g+a+x ) + G8 ( (1/2) . a+x ) + G9 ( (1/3) . x+a+x )

+ G10((2/3).x) + G11((1/2).B-k) + G12((1/2).(e+x)+a+x)

tm'M 1 - 1 = 31.427

16.409 t/m2

0.7122

0.597

=

=

smax < sijin tanah 11.776 16.409

M 1 - 1 =

qult = cNcscdcic + qNqsqdqiq + 0,5gBNgsgdgig 49.227

s ijin tanah =49.227

3.0=

H

H2

H1

Ha

d

Ho

Hc

Hb

Pa1

Pa2

Pa3

Pa4

Pa5

Pa6 Pa7

Pa8 Pa9

Pp

2 2

3

3 1

1

G2

G4

G6

G3

G5

G7

G1

G8

G9

G10

G11

G12

B

k x a x e

g i j

5

afq cot.c.AQ

H.5.01i

f

5

af cot.c.AQ

H.7.01i

fg

Created by ANCHA 08

Page 10: Rekayasa Pondasi(3)

Rekayasa Pondasi

b. Gaya geser

D = Pa1 + Pa2 + Pa3 + Pa4 + Pa5 + Pa6 + Pa7 + Pa8 + Pa9 - Pp

D = ton

c. Gaya normal

N = G1 + G2 + G3 + G4 + G5 + G6 + G7 + G8 + G9 + G10 + G11 + G12

N = ton

d. Tegangan lentur

Momen inersia permeter panjang pondasi :

b = 1

h = 12

e. Tegangan geser

f. Tegangan normal

N

A

- Potongan 2 - 2

a. Momen lentur

Pa1 ((1/3).H0 +H1+Hc) + Pa2 ((1/2).Ha+Hb+Hc) + Pa3 ((1/3).Ha+Hb+Hc)

+ Pa4((1/2).Hb+Hc) + Pa5((1/3).Hb+Hc) + Pa6((1/2).Hc) + Pa7((1/3).Hc)

- Pa8( (1/2).d ) - Pa9( (2/3).d ) - Pp( (H2 - d) - (2/3).H2 )

tm'

b. Gaya geser

D = G1 + G2 + G3 + G4 + G5 + G6 + G7 + G8 + G9 + G10 + G12

D = ton

M 2 - 2 =

t = -66.58 t/m2

sN = sN = 31.729

1.00 mIx =

t/m2

t =D . s

b . Ix

m4

s = 271.53 t/m2

b . h3 =

s =M . y

Ix

0.04820.83 m

-7.705

26.441

M 2 - 2 = 22.465

20.330

Created by ANCHA 08

Page 11: Rekayasa Pondasi(3)

Rekayasa Pondasi

c. Gaya normal

N = Pa1 + Pa2 + Pa3 + Pa4 + Pa6 + P7

N = ton

d. Tegangan lentur

Momen inersia permeter panjang pondasi :

b = 1

h = 12

e. Tegangan geser

f. Tegangan normal

N

A

- Potongan 2 - 2

a. Momen lentur

G1 ( (2/3) . (e+x)-x ) + G2 ( (1/2) . (e+x-g)-i-j ) - G3 ( (1/3) . g+i+j )

+ G4 ( (1/2). (e+j)-j ) - G5 ( (1/3).i+j ) + G6 ( (1/2).e ) - G7 ( (1/3).j )

- G8 ((1/2) . a+x) - G9 ((2/3).x) - G10((1/3).x+a+x) - G11((1/2).B-e)

+ G12((1/2).(e+x)-x)

tm'

b. Gaya geser

D = Pa1 + Pa2 + Pa3 + Pa4 + Pa5 + Pa6 + Pa7 + Pa8 + Pa9 - Pp

D = ton

c. Gaya normal

b . h3 = 0.1253

12.605

m4

1.15 m

s =M . y

s = 74.682 t/m2

Ix

1.00 mIx =

t/m2

b . Ix

sN = sN = 11.001 t/m2

t =D . s

t = 67.584

M 3 - 3 =

M 3 - 3 = 1.1331

-7.705

Created by ANCHA 08

Page 12: Rekayasa Pondasi(3)

Rekayasa Pondasi

N = G1 + G2 + G3 + G4 + G5 + G6 + G7 + G8 + G9 + G10 + G11 + G12

N = ton

d. Tegangan lentur

Momen inersia permeter panjang pondasi :

b = 1

h = 12

e. Tegangan geser

f. Tegangan normal

N

A

26.441

1.00 mIx = b . h3 = 0.0482 m4

0.83 m

s =M . y

s = 9.7902 t/m2

Ix

t/m2

b . Ix

sN = sN = 31.729 t/m2

t =D . s

t = -66.58

Created by ANCHA 08