Pertemuan6 Diode Aplc

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    Clippers & Clampers

    Zener diode application

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    Clippers

    Clippers or diode limiting is a diode network that have the ability to

    clip off a portion on the i/p signal without distorting the remaining part

    of the alternating waveform.

    Clippers are used to eliminate amplitude noise or to fabricate new

    waveforms from an existing signal.

    2 general of clippers:

    a) Series clippers

    b) Parallel clippers

    Series Clippers

    The series configuration is defined as one where the diode is in series

    with the load.

    A half-wave rectifier is the simplest form of diode clipper-one resistorand diode.

    +

    -

    ViR

    L Vo

    -

    +

    2

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    The diode clips any voltage that does not put it in forward

    bias. That would be a reverse biasing polarity and a voltage less

    than 0.7V for a silicon diode.

    Clipper Diode Circuit

    3

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    VmVi

    t0 T/2 T

    +

    -Vi

    V

    RL Vo

    -

    +

    The half-wave rectifier with addition of dc supply is shown infollowing figure. The cct known as biased series clipper. The dcsupply have pronounced effect on the o/p of a clipper.

    Our initial discussion will be limited to ideal diode.

    Biased series clipper

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    +ve region turn the diode ON.

    -ve region turn the diode OFF.

    Vi > V to turn ON the diode

    In general diode is open cct (OFF state) and short cct (ON state)

    For Vi > V the Vo = ViV

    For Vi = V the Vo= 0 V

    The complete cct shown above

    Vm

    Vi

    t0 T/2 T

    +

    -

    Vi=Vm

    V

    RL Vo

    -

    +

    + -

    T/20

    Vo

    tT

    Vm-V

    Vi=V (diodes change state)

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    Determine the o/p waveform for the network below:

    Solution:

    Example: Variations of the Clipper Circuit

    6

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    More Example:

    Repeat previous example for the square-wave i/p.

    +

    -

    Vi

    V=5 V

    RL Vo

    -

    +

    +-Vi

    t0 T/2 T

    -10

    20

    7

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    Parallel Clippers The diode connection is in parallel configuration

    with the o/p. Diode is ideal

    +

    RL

    V

    -

    +

    -

    Vi

    8

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    By taking the output across the diode, the output is now thevoltage when the diode is not conducting.

    A DC source can also be added to change the diodes required

    forward bias voltage.

    Changing Output Perspective

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    Example :

    Determine the Vo and sketch the o/p waveform for

    the below network

    +

    V=4 V

    RL

    Vo

    -

    +

    -

    Vi

    10

    t0 T/2 T

    Vi

    16

    -16

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    V=VoON4

    Vi=VoOFF5

    Vi=VoOFF6

    Vi=VoOFF7

    Vi=VoOFF16

    V=VoON3

    V=VoON2

    V=VoON1

    VoDiode stateVi

    +

    V=4 V

    RL

    Vo

    -

    +

    -

    Vi

    +

    V=4 V

    RL

    Vo

    -

    +

    -

    Vi

    t0 T/2

    Vo

    16

    4

    Solution:

    + ve region

    t0 T/2 T

    Vi

    16

    -16

    11

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    Solution (continued):

    - ve region

    +V=4 V

    VRL=0A

    Vo

    -

    +-Vi id=0A

    V=VoON-4

    V=VoON-5

    V=VoON-6

    V=VoON-7

    V=VoON-16

    V=VoON-3

    V=VoON-2

    V=VoON-1

    VoDiode stateVi

    t0 T/2

    Vo

    16

    4

    T

    t0 T/2 T

    Vi

    16

    -16

    12

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    Example :

    Repeat the previous example using a silicon diode with VD=0.7 V

    +

    V=4 V

    RL

    Vo

    -

    +

    -Vi

    VD=0.7 V

    id=0A

    V3.3

    7.04

    VVVi

    0VVVi

    D

    D

    Solution:

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    Solution (continued):

    For i/p voltages greater than 3.3 V the diode open cct and Vo=Vi.

    For i/p voltages less than 3.3 V the diode short cct and the network result

    as/;

    +V=4 V

    RL

    Vo

    -

    +

    -

    Vi

    VD=0.7 V

    id=0AV3.3

    7.04Vo

    t0 T/2

    Vo16

    3.3

    T

    The resulting o/p waveform

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    Clipper Circuits Summary

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    Clipper Circuits Summary

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    Clampers

    The clamping network is to clamp a signal to a different dc level. Also

    known as dc restorers. The clamping cct is often used in TV receivers as adc restorer.

    The network consists of:

    a) Capacitor

    b) Diode

    c) Resistive elementd) Independent dc supply (option)

    The magnitude of R and C must be chosen such that the time constant

    = RC is large enough to ensure that the voltage across the capacitor does

    not discharge significantly during the interval the diode is nonconducting.

    Our analysis basis that all capacitor is fully charge and discharge in 5

    time constant.

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    18

    +

    R Vo

    -

    +

    -

    Vi

    Vi

    t0 T/2 T

    V

    -V

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    Operation of clamper+ ve region

    +

    RVo

    -

    +

    -

    Vi

    C 0 - T/2: Diode is ON state (short-cct

    equivalent)

    Assume RC time is small and capacitorcharge to V volts very quickly

    Vo=0 V (ideal diode)

    - ve region T/2 T: Diode is OFF state (open-cctequivalent)

    Both for the stored voltage across

    capacitor and applied signal current

    through cathode to anode KVL: - V- V- Vo = 0 and

    Vo = -2V

    +

    R Vo

    -

    +

    -

    V

    C

    Vo

    -

    +V

    Vi

    t0 T/2 T

    V

    -V

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    Tips : Clamping networkTotal swing o/p signal = the total swing i /p signal

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    Example: Determine Vo for the network below:

    +

    R=100 kohmVo

    -

    +

    -

    Vi

    C= 1 uF

    V= 5 V

    Vi

    -20

    10

    T

    0 t1 t2 t3 t4 t

    f=1000 Hz

    S l ti

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    Solution:

    Step 1:Consider the part of i/p signal that will forward bias the

    diode. From network (t1 -t2:-ve region)+

    R=100 kohm Vo

    -

    +-

    20 V

    Vc

    5 V

    Step 2:During ON state assume capacitor will charge to a voltage level

    determined by the network. Find the store voltage capacitor & obtained

    Vo

    KVL: -20 +Vc5 = 0

    Vc = 25v Vo = 5

    Vi

    -20

    10

    T

    0 t1 t2 t3 t4t

    f=1000 Hz

    S l ti ( td)

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    Solution (cntd):

    Step 3:During OFF state assume capacitor will hold on its established

    voltage level. From network (t2 -t3:+ve region)

    +

    R=100 kohm Vo

    -

    +-

    10 V

    C

    Vc

    5 V

    KVL

    Step 4:Obtained Vo

    ms500ms)5(1005istimedischargetotalThe

    ms100k)(1u)(100RC:by

    determinedisgdischarginofconstantTime

    V35Vo0Vo2510

    0VoVc10:KVL

    Vi

    -20

    10

    T

    0 t1 t2 t3 t4t

    f=1000 Hz

    Solution (cntd):

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    Step 5:Checking!!! total swing o/p signal = total swing i/p signal

    From network (t2 -t3: +ve region)Vo

    35

    0 t1 t2 t3 t4t

    5

    Solution (cntd):

    Vi

    -20

    10

    T

    0 t1 t2 t3 t4t

    f=1000 Hz

    24

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    Example:Repeat the previous

    example using agermanium diode !!!

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    Summary of Clamper Circuits

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    Summary of Clamper Circuits

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    Zener Diodes

    The zener diode is a special type of diodes that is designed to

    work in the reverse breakdown region. But it also can operate in the forward bias region.

    Zener diode is a main component to design voltage regulator

    circuit for DC power supply.

    Zener Diodes Characteristic

    The I-V characteristics of a diode in Fig 3.19 shows that the

    breakdown voltage of a diode is nearly constant over a wide-

    range of reverse-bias currents.

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    Operation region:

    Forward bias-operate same as

    normal diode

    Reverse bias-small current flow

    Breakdown-big current flow. This is

    the region where the voltage zener is

    constant

    For normal diode breakdown voltage is

    capable to destroy the diode but with

    zener diode the current is limited by

    connecting series resistor.

    0

    I

    V

    Forward

    ReverseBreakdown

    -Vz0.7

    Fig. 3.19

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    Zener Diode

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    The Zener is a diode operated in reverse bias at the Zener

    Voltage (Vz).

    Zener Diode

    29

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    Vi and R fixed Fixed DC voltage is applied in network

    below, as is the load resistor.

    The analysis can be determined with 2

    steps.

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    Step 1:

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    p

    Determine the state of zener diode by removing it from

    the network and calculating the voltage across the

    resulting open cct.

    L

    L

    L

    RR

    ViRVV

    LR

    R

    RR

    RVi

    V:OFFdiodeZenerVzV

    Vz-ViV:ONdiodeZenerVzV

    Vz

    Iz+

    - Pzm

    RL

    Vi

    Fig 3.20: Basic zener regulato

    V+

    -

    RL

    Vi

    Fig 3.21: Determining the state othe zener diode

    RV

    L

    +

    -

    31

    Step 2:

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    Subtitute the appropriate equivalent cct and solve for the

    desired unknowns.

    The ON state will obtained the equivalent cct in

    Fig below

    LZR III:KCL LRZ III

    Vi

    R

    VIdan

    R

    VIwhere

    R

    R

    L

    L

    L

    devicefor thespecifiedPPzwhich

    VzIzPzzenerbydissipatedPower

    ZM

    VZ

    +

    -

    RLVi

    Fig 3.22

    R

    VL

    +

    -

    IR

    PZM

    IZ

    IL

    32

    E l

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    33

    Example:

    a) Determine VL, VR, IZ and PZ in the network below.

    b) Repeat part (a) with RL=3 k

    VZ=10 V+

    -

    RL

    Vi R=1 k ohmVL

    +

    -PZM=30 mW

    IZ

    1.2 kohm

    VR+ -

    Solution:

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    So ut o :

    Step 1: Remove zener diode & obtained the zener state

    W0VzIzPz

    0AIz

    7.27V8.73-16V-ViV

    8.73VVV

    cct)(openstateOFFisdiodeVzV

    V73.8k2.1k1

    16k2.1

    RR

    ViRV

    LR

    L

    L

    L

    V

    +

    -

    RL

    Vi=16 V

    R=1 k ohm

    VL

    +

    -

    IZ

    1.2 kohm

    IR

    0

    I

    V

    Forward

    ReverseBreakdown

    -Vz0.7

    Fig. 3.19

    8.73

    10

    Resulting operating point

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    Repeat part (a) with RL=3 k

    35

    Fixed Vi Variable R

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    Fixed Vi, Variable RL For an offset Vz a specific range of resistor values need

    to be choose to ensure zener diode is ON state.

    Too small a load resistance will cause VL < Vz - diode is

    OFF state.

    Thus the minimum load resistance in previous example

    need to be calculate. This can be expressed by the

    equation below:

    VzVi

    RVzRminL

    RL > RLmin zener diode is ON state diode canreplaced by Vz source equivalent

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    With R changes the I also changes The table below

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    With RL changes the IL also changes. The table belowdescribed relationship between RL ,IL,IR

    minL

    maxL

    R

    VzI

    maxL

    minL

    R

    VzI

    zminLmaxR III

    zmaxLminR III

    Notes: Izmax = Izm

    37

    Example:

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    p

    a) For the network below, determine the range of RL and IL

    that will result in VRL being maintained at 10 V.

    b) Determine the maximum wattage rating of the diode.

    RLVi=50 V

    R=1 k ohm IZ

    IR

    +

    -

    Vz=10 VIzm = 32 mA

    IL

    38

    Solution:(a)

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    k1.25R250:rangeRThe

    k1.25m8

    10

    I

    Vz

    R

    mA8m32-m40I-II

    mA40k1

    40RVI

    25040

    k10

    1050

    10k1

    Vz-Vi

    RVzR

    LL

    LminLmax

    RLmin

    RR

    Lmin

    zmax

    Solution: (b)

    320m3210VzIP zmaxzmax

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    Fixed RL Variable Vi

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    Fixed RL, Variable Vi For a fixed values of RL in the network below, Vi must

    be sufficiently LARGE to turn zener diode ON. The minimum turn-ON voltage Vi=Vimin is expressed

    by :

    Vz

    Iz+

    - Pzm

    RL

    Vi

    R

    L

    L

    L

    LL

    R

    VzRRVimin

    RR

    ViRVzV

    40

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    The maximum value of Vi is limited by the maximumzener current, Izmax, thus

    LIII zmaxRmax

    RImaxVi maxR

    IL is fixed at Vz/RL and Izmax is the maximum value sothe maximum value of Vi is expressed below:

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    Example:

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    Determine the range of values of Vi that will maintain the

    zener diode of network below:

    RL=1.2k ohmVi

    R=220 ohm IZ

    IR

    +

    -

    Vz=20 V

    Izm = 60 mA

    IL

    VL

    +

    -

    42

    Solution:

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    V36.87ViV23.67:ViofrangeThe

    V87.3620220m67.76VzRIVimax

    mA76.6716.67m60mIIzmaxI

    mA16.671200

    20

    R

    Vz

    R

    VI

    V23.671200

    202201200

    R

    VzRRVimin

    maxR

    LRMax

    LL

    LL

    L

    L

    RL=1.2k ohmVi

    R=220 ohm IZ

    IR

    +

    -Vz=20 V

    Izm = 60 mA

    IL

    VL

    +

    -

    Equivalent cct in the ON state

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    Practical Applications of Diode Circuits

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    pp

    Rectifier CircuitsConversions of AC to DC for DC operated circuits

    Battery Charging Circuits

    Simple Diode Circuits

    Protective Circuits against OvercurrentPolarity Reversal Currents caused by an inductive kick

    in a relay circuit

    Zener Circuits

    Overvoltage Protection

    Setting Reference Voltages

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    References:

    1. Thomas L. Floyd, Electronic Devices, Eighth Edition, Prentice Hall, 2002.

    2. Robert Boylestad, Electronic Devices and Circuit Theory, Seventh edition,Prentice Hall, 2002.

    3. Puspa Inayat Khalid, Rubita Sudirman, Siti Hawa Ruslan,ModulPengajaran Elektronik 1, UTM, 2002.

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