Perencanaan-Balok-Crane1

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    Perencanaan Balok Crane

    60cm

    90cm

    80cm

    20mm

    10mm

    20cm 20cm38 cm

    10mm 10mm

    IV

    II III

    I

    55,87cm

    34,13cm

    x=40cm

    Sb Y

    Sb X

    Y=

    FI = 60 x 1 = 60 cm 2

    FII = 1 x 87 = 87 cm 2

    FIII = 1 x 87 = 87 cm 2

    FIV = 80 x 2 = 160 cm 2

    * Garis Berat Penampang

    = 1 1 + 2 2 + 3 3 + 4 4 =

    600,5 + 8744,5 + 8744,5 + (16089)

    394

    =30+3871,5+3871,5+14.240

    394= 55,7 cm

    = 55,87 cm

    X = 40 cm

    Luas Penampang

    A = A1 + A2 + A3 + A4

    = (60x1) + (1x87) + (1x87) + (80x2)

    = 60 + 87 + 87 + 160

    = 394 cm 2

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    Momen Inersia arah-x (sumbu kuat penampang)

    Ix = Ix 1 + Ix 2 + Ix 3 + Ix 4

    Ix1 =1

    12 b h3 + F a2 =

    1

    12 60 13

    + 60 (55,87 0,5)2

    =1

    12 60 1 + 6 0 (3.065,84) = 183.955,4 cm 4

    Ix2 =1

    12 1 87 3 + 87 (55,87 12 8 7 + 1 ) 2 =

    1

    12 1 87 3 + 87 (11,37) 2 =

    1

    12 1 658.503 + 87 129,28 = 66.122,61 cm 4

    Ix3 = Ix 2

    Ix4 =1

    12 80 23 + 160 (34,13 1) 2 =

    1

    12 80 8+160 1.097,60 = 175.669,3 cm 4

    Ix = Ix 1 + Ix 2 + Ix 3 + Ix 4

    = 183.955,4 + 66.122,61 + 66.122,61 + 175.669,3

    = 491.869,92 cm 4

    Momen inersia arah-y (sumbu lemah penampang)

    Iy =1

    12 60 3 1 + 112 80 3 2 + 112 87 13 2 + 87 1 19,5 2 2 = 18.000 + 85.333,33 + 14,5 + 66.163,5

    = 169.511,33 cm 4

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    P (Beban Bergerak) = 10 ton = 10.000 kg

    Q bs (profil) = = 0,394 2 7,850 3 = 3,10 / = 3,0929 t/m

    = 3,10 t/m

    Q bs (crane) = 200 kg

    Tegangan tarik pada web sebesar :

    f t =P

    7t w<

    =(10.000+200)

    71

    0,75 (10.200 kg )

    2400 kg / 2= 3,19 cm 2

    tf > 1,79 cm 2

    ambil t f = 2 cm = 20 mm

    f b =0,75 P

    t f 2<

    =0,75 (10.000+200)

    2 2 <

    = 1.912,5 < y = 2400 kg/cm 2

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    Pembebanan Balok Crane

    4,5m'

    9m'

    5 ton 5 ton

    ? = 1,20 m'

    = 1,20 m (Lihat Tabel Hoist Crane Single Girder)

    < 0,586 L

    < 0,586 . 9

    < 5,274 m

    Mmax

    =5

    2(9) (9

    1,20

    2) 2

    = 19,6 tm x 1,15 (ambil impact factor = 15 %)

    = 22,54 tm

    V = P ( 2 al )= 5 ( 2 1,209 ) = 9,33 ton

    10 ton + 0,2 ton

    9m'

    Q bs (profil) = 3,10 t/m Q footwalk = 0,40 t/m +

    Q total = 3,50 t/m

    = 1,20 m

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    Wy =Iyx

    =136.429,58

    20 = 6.821,479 cm 3

    y = Mywy =6,427 10 5 kg cm

    6.821,479 cm 3

    = 94,22 kg/cm 2

    = x 2 + y 2 + xy = 663,69 2 + 94,22 2 + 663,69 x 94,22 = 715,47 kg/cm 2 < s = = 24001,5 = 1.600 kg/cm 2

    Profil balok crane yang dipakai aman digunakan...................