p03 Bkr - 2. Latihan Soal Aljabar Boolean 5.12 (33)

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Transcript of p03 Bkr - 2. Latihan Soal Aljabar Boolean 5.12 (33)

Bambang Krisnarno

Versi 5.12

1. T = ( A + C ) + ( B + D ) 2. T = ( A + B C ) 3. T = ( A + B C ) ( D + E F ) 4. T = A B ( A + B C ) 5. T = A B C + A B ( A C )

6. T = A B C + A B C + A B C

7. T = A C ( A B D ) + A B C D + A B C ( ! )8. T = ( A + B ) ( A + B + D ) D 9. T = A B C + A C D + C D 10. T = A B D + B C D + C D (!) (!)

11. A B C 12. A BD F E G D F E

T

T

C

13. A B C 14. A BD F E G D F E

T

T

C

1. T = ( A + C ) + ( B + D )= ( A C ) + ( B D ) + + =(AC)+(BD)

T=AC+BD

2. T = ( A + B C ) =(A+BC) = A ( B C ) + = A ( B+C ) T = A B+AC

3. T = ( A + B C ) ( D + E F ) = ( A + B C )+( D + E F ) = A ( B C )+D ( E F ) = A ( B+C )+D ( E+F ) = AB+AC + DE+DF

4. T = A B ( A + B C )

=AB(ABC) =AB(B+C) =ABC

5. T = A B C + A B ( A C ) = A B C + A B ( A+C ) =ABC+ABC =BC

6. T = A B C + A B C + A B C ABC+ABC A B (C + C)

AB+ABC+ABCA C (B + B) T = A B+ A C

6. T = A B C + A B C + A B C ABC+ABC A B (C + C)ABC +ABC

A C (B + B) T = A B+ A C

7. T = A C ( A B D ) + A B C D + A B C AC(ABD) =AC(A+B+D) =ABC+ACD T =AB C +AC D +AB C D +AB C +ABCD T=ABC+ACD+ BCD+ABC

8. T = ( A + B ) ( A + B + D ) D = ( A A + AB + AD + AB + BB + BD ) D B =BD

9. T = A B C + A C D + C D C ( A D + D) C ( A + D) ABC+ AC+CD A (BC + C)

A ( B + C)T = AB+AC +CD

9. T = A B C + A C D + C D ABC= ABC AC D = AB C D +AC D CD = ABCD+ACD+CD T= AB + AC +CD

10. T = A B D + B C D + C D D (B C + C) D (B + C) A B D + BD + C D B (AD + D) B ( A + D) T = AB+BD+CD

10. T = A B D + B C D + C D ABD= AB D

B C D = AB C D +B C D CD = ABCD+BCD+CD

T= AB

+BD

+CD

11. A B CD F E

T

T=A(A+BC)CT=ABC

12. A BD

FE G

T

C

T=F+G=ADE+GT=A(AB)C+ABC T=ABC

13. A B CD F E

T

T=D+F+E=A+F+E=A+(D+E)+E T=A+ (A+ B+C)+ABC T=1

14.

A B

DF

EG

T

C T=FG=ADEGT=A(A+B)(ABC)(ABC) T=?