hitung integral

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    03-Jun-2018
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    ffiffis.

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    k%d,&HaffiHM&ru

    NTE HIT

    UNG GRAL

    ffiffi,ffitr-$*'i.tS-ffi*ffiffiffiffiffiFiHliif,ii:, rii,i.I#:i*ii9rTl,?rWWriFx+,:i::iiisi'r.Bi.{;ii!"{i11,.if.i

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    : .

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    '*i'N #.+,,.:: Am.I.rfi-E*#brl.'t.':&r=:t'rl it4:"

    -.

    utculu*ooi f,1\}

    I'1.,"l.:'"t: ]lttuluu gtutqrruutl'td:j,;

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    HITUNG Drs.Wardiman

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    INT'EGRA!Penerbit: Jln. Tamansiswa PT. HANINDITA Yogyakarta

    101 B- GRAHA 6

    WIDYA .0274l- 8N22,88193Ttta lgtak : T. lran Disein kulit muka : Hanindita

    @ Hak Pengarang dan Penerbit dilindungi oleh Undang-undang.CetakanKetiga, Juli1987axclttolcli :

    PT. HANINDITA OFFSET-

    Yogyakarta lsi diluar tenggung iawab percetakan.

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    UVINV9NSd V.I.VT t]

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    'mq?ilet aPor?w-?Potzut uo*uap lonsas tuot uop 'tolns tuof todutos ouoqtapas tuo{

    uop ,loospos-lrrls lnt uollosqnq uoqnqtad untuoqwaw 1n7unlrlltrl-lulnt

    ! dt

    nto, orror)'l!#T::#r#loosloos totoltd-toluad

    unlmsala(uantuolop lmlotuaw

    un1 ,otutttltly!u! nlng'umlas

    lq uqo1,nlpnlnqtotu8uaytuldwosryluntad uop

    lnun molasWolDlp uotlo,orfpwe\tmuwtralnsatl-uotolnsfil otuomatwolop tw[.tunpl otlow'lottalur lutt

    to;oselelucd qoruot-tlotuoc'otn[ uoluaqrp apota,u-e?opu noro ,yoay1to4tuo{ 'onqwad opodaq Wsorl owydt t1o{.uoq-ryKwq uotldom

    -eol qeto 'Ws-loos uoryosapfuaw

    uqdutouatl opod uolyoq ruorl pteq rfiryuotuep uqueqp tuoi{, uotlopsal-uoqolos?rl uolntaqwed

    rytwn uqwntyp otnl wdop 'olqoqa oilsrsntry-Dttsrsoqowtuo( 'pttatul tuu1t1

    {uxal qoples nlopd-totwed

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    'nqaslet uotulnserl-uotolnsarl'!u!

    Zg6l ,ouolof,SoyslpuaduDnuDIuowrP,toA['aotuoleuau pdop ottlas

    unry olrsrsotry-Dilsrsaqow qep-mlopd uqqn,qwa'tuot'rlotuauey

    umts qofmsrrswP o,,.qsoqoy{-otttsTsoqotu

    uoVu?qwau r?nsouofit?t so1tlt1t

    -o*rlsoqilt-ur, ?potinu-qa[ucut-1oos

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    ISI HVIJVO N

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    u?ur?lBtluvrNvDNad vJ.v) uYrcvotst u Tgvg

    ISnvtlnu*snnnu UVSV(I

    'IVUCATNT 'lnlueuel4qle-6a1u1'ZserEelulsnutu-snunuFos-leos"" ":" "':""

    ":" ' I St t ""lBos-lBos ""' 8z {v8llrsvucarNMooJ,3n0

    Inlueq 'Bp.6.a1ulpup xxP :'q

    le6alul utulsxusocpup{ntueq

    : ,,,sri ures xxp uup

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    u,Elc0gxucesocs:

    x xp 't1u.6e1ul Iuup

    {nlueg ,,9t,xrus03 xu xpfu*xp xu uls *.'u"o, fxp xu soc xur

    6t, '?,;u-Ea1u1

    uutuep uu>;uun8Buatu Isnlqsgns ' 'BEnlllsqnsl$unJ

    JDqBfie ' '" .g....p1embuoEpguuEuapFnlnsqns O, gV'cprEeluJlrep ;sun3 r;eccdl?uors8.r'pprEalul

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    lrep r6un;-r$un; [BuorsuJn 6t Ig.'e. lsuncJsl.toIsBJuBp uls x uBp soc x '

    " ., ....[8os_Fos.....aL Lu

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    BAB III

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    INTEGRASI FUNGSI HIPERBOLIK l.Rumus-rumus dasar fungsi hiperbolik 2.Rumus-rumus dasar integral dari fungsi hiperbolik 3.

    Substitusi fungsi hiperbolikSoal-Soal BAB IV

    RUMUS_RUMUS REDUKSIl.Rumus reduksi untuk Binomial DifferensialSoal-Soal2. Rurn us red87E788 9l949797100102105r06160lvtuk trigonbme tri kdi fferensialSoal-SoalBABVDAFTARuksiunPENYELESAIAN SOAL_SOAL UJIANPUSTAKA

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    IgVSNSNWNU.SNruNU UVSVO ]VHSSINI '1

    ]vu9:IrNt)tvt nrNlrHt )trNHrcNt wucsrNt (BIE6J

    (x) etlg tnqasTp .r (x) ntens alyu (1erta1u1 TrBp J nfuatrlrrp'(x) 1stun3 tuepasEued; @ (x) ledunduau nere lngesTp 1erta1u1 alTfe^1rap 'ueffii rtet '5 rd (x) - I '(x) nruCiiJr ) -

    TrapuT 1arta1u1 {Bl -raf r,r.rerl,r.ft+*P,Ltr*)nfensE*= -5 lstunJ T

    qafppe x)+ Eue(lertatuT t/InqBtaITp IBpTt 1et8un1 t

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    letaqas>1e1ntuafralTrpP J=_(x) qoluoc.'r*

    : ' -tleTo = I$ )(Drx1- (5=e Z*ertegl'

    ferta1ul IB? -ra?

    nluofTr?p J (x) _ E ZxledepslTnlTp B;rcas umumex

    + D tupfsuoc) Jo (uoltertaluT Inf,uOueqele(uau lertaluy:1e1nfualral TrBp J tue{ . Buerslp O -Tp 'tuerequae (x),

    eTTni}p uetuap {nluaq : ,t(x)xP 'D+rx=*PZ,: Tpaf

    rsvucSrNt snnnu-snwnu .z.t;'l";T'tr .T

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    v( eJC+(x1J=xP(x)t,

    'xp { (,,rf(n+xp = *on] (

    )* (_ xedeltas

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    4.

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    5.6.7.8.9.10.11.tr:13.t4.15.L6.t7.18.19.

    * ,l;'=

    #T + c,m

    I -r' F ="'lul*' fuou=#*"+c,a;'o,1

    ) [.'ou=.u*..f"t"udu=-cosu=c.["."udu=slnu+c. frr"du=rnl"""ul*..

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    f".,,du =ln lsln u[ * ..(""" Iu du =ln.tse.1"o"..u + tg Uf r-ctg1"""'U dU = 1r, |"o"""Uu du = cs u + c.1"."""'udu=-crsu+c.t"..,tg U dU = sec U +C.("o"."(du1u )Uctg

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    );z;;r lffi ('duU dU = - cosec U* -;

    arcts- {

    c' = arc"in!+Il.Cul*C.C.C.

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    3+ 'oz

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    fr(TB3Iscas 0 B'TZ:Jz'-TfrNP="1'o.[=+1".

    e+zn z B+ xA NP=+nl"r

    B+z{l5,,B+2frNP=l"r

    n * .,2 ,"ll-.rn

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    *Z"\

    rr"

    "rBfi + '3.SZ+

    _e4

    l(. l"t 0 + *l ', '92

    -zr\nf"r+

    *f ', qoguoc-

    rlotuoCuepese;aluad leos-leos ^*(', e)

    xp= L* I+ b+'c

    /t'e + '3 \, 3_Jt

    -xP'-t=

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    "EIZ-=c*!l\=xP t/1e e/r*'3+

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    *t, ,.\

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    5x*3)dx =\rr*'ro*-.1,=T

    x+ *2*3*.'*cio*u.! ,, - *)\l?o-=! *LtZ d*-\*t''u* =tr*''',.!,r*+ t6) dx = 3*3 +dx

    -Z 5L2*2+5x(*3 * 2)\ *2

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    dx*512*c.

    + a)2 o-=t(e*2+-24x*16x+C.

    ' ,C.+4, u. =l(x +5- 4*-21 d*=kx+-' lL x+c.e. Illtunglah: ," .t k3 +z)23*2'd*;iul

    \2.-dx;( 'c)');{;r}

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    (a*2a*;ta>.xPenyelesalan:Untuk mempermudahpenyelesaian, dlmlsalkar, , *3 + 2 =

    U, oaka dffferen- slal

    darlU adalah :dU = 3 *2d*.(").((*3*z)2

    t*2 d* =(u' )- )( )

    4*3 *2ur=+u3 J *.=i,*' J+

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    213+ c-"r.l(*1 ,",.t#+ z)\ *20*=;=tfut u, =3u''2*c=i

    I(*3*z>-3.3 *2 d* =i

    r*'*z:ttz ru-3 au*c.=i , -r"u-') * c=33*z>2

    +c. (x,., .,

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    \/T*2 d* =+\ (*3 +z)-r/4.3*2 d* = +\"-Ll4ilJ-+,u3to)*C=

    t_ 9(*3 +

    zt3l.4+c.