Cooper Jacob Rizki Sahputra Ok

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Data-data: Debit tetap , Q = 1080 m3/hari 200 m DATA t (menit) log t 0.00 0.00 - 1.00 0.15 0.0000 2.00 0.40 0.3010 3.00 0.68 0.4771 4.00 0.78 0.6021 5.00 1.02 0.6990 6.00 1.08 0.7782 8.00 1.30 0.9031 10.00 1.42 1.0000 12.00 1.52 1.0792 15.00 1.65 1.1761 18.00 1.76 1.2553 21.00 1.82 1.3222 24.00 1.88 1.3802 27.00 1.92 1.4314 30.00 1.98 1.4771 35.00 2.04 1.5441 40.00 2.06 1.6021 45.00 2.09 1.6532 50.00 2.15 1.6990 60.00 2.21 1.7782 80.00 2.32 1.9031 100.00 2.36 2.0000 120.00 2.45 2.0792 150.00 2.52 2.1761 180.00 2.58 2.2553 240.00 2.61 2.3802 300.00 2.68 2.4771 360.00 2.70 2.5563 Gradien garis , m = 1.0308 Titik potong , b = 0.3184 Menentukan nilai m dan b dengan rumus regresi x y xy 0.0000 0.15 0 0.0000 39.9856 b = 0.318383 0.3010 0.40 0.120412 0.0906 Σy = 50.13 m = 1.030753 0.4771 0.68 0.32444245 0.2276 Σxy = 84.2986 0.6021 0.78 0.46960679 0.3625 69.4326 0.6990 1.02 0.7129494 0.4886 0.7782 1.08 0.84040335 0.6055 0.9031 1.30 1.17401698 0.8156 1.0000 1.42 1.42 1.0000 1.0792 1.52 1.64035549 1.1646 1.1761 1.65 1.94055058 1.3832 1.2553 1.76 2.20927961 1.5757 1.3222 1.82 2.40643912 1.7483 1.3802 1.88 2.59479713 1.9050 1.4314 1.92 2.74821843 2.0488 1.4771 1.98 2.92470008 2.1819 1.5441 2.04 3.14989881 2.3841 1.6021 2.06 3.30024358 2.5666 1.6532 2.09 3.45521415 2.7331 1.6990 2.15 3.65278551 2.8865 1.7782 2.21 3.92971426 3.1618 1.9031 2.32 4.41516877 3.6218 2.0000 2.36 4.72 4.0000 2.0792 2.45 5.09399405 4.3230 2.1761 2.52 5.48374997 4.7354 2.2553 2.58 5.81860306 5.0863 2.3802 2.61 6.21235134 5.6654 2.4771 2.68 6.63868496 6.1361 2.5563 2.70 6.90201675 6.5347 Menentukan nilai T dan S Persamaan garis data = 1,0308 log t + 0,3184 -0.3089 10^(-0,3089) 0.4910 menit Δs = 1.0308 m T = = = 191.687 S = = = 3.68E-06 Jarak dari sumur pompa , r = Hitungan awal Penurunan muka air , s (m) Σx = Σx² = Pada saat s = 0 , t = t0 ; sehingga 0 = 1,0308*log t0 + 0,3184 Jadi log t0 = -0,3184/1,0308 = sehingga t0 = t0 = m²/hari 0.10 1.00 10.00 100.00 1000.00 0.00 0.50 1.00 1.50 2.00 2.50 3.00 Kurva s(t) waktu pemompaan t, menit drawdown s, meter 0.00 0.50 1.00 1.50 2.00 2.50 3.00 0.00 0.50 1.00 1.50 2.00 2.50 3.00 f(x) = 1.03075254970003 x + 0.318383055163965 Kurva s vs log t log t s 2,3× /(4 ×∆ ) 2,3×1080/ (4 ×1,0308) 2,25× × _0/ ^2 2,25×[191,687/(24×60)]×0,491/ 200 ^2

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Transcript of Cooper Jacob Rizki Sahputra Ok

Page 1: Cooper Jacob Rizki Sahputra Ok

Data-data:Debit tetap , Q = 1080 m3/hari

200 m

DATA

t (menit) log t

0.00 0.00 -1.00 0.15 0.00002.00 0.40 0.30103.00 0.68 0.47714.00 0.78 0.60215.00 1.02 0.69906.00 1.08 0.77828.00 1.30 0.9031

10.00 1.42 1.000012.00 1.52 1.079215.00 1.65 1.176118.00 1.76 1.255321.00 1.82 1.322224.00 1.88 1.380227.00 1.92 1.431430.00 1.98 1.477135.00 2.04 1.544140.00 2.06 1.602145.00 2.09 1.653250.00 2.15 1.699060.00 2.21 1.778280.00 2.32 1.9031

100.00 2.36 2.0000120.00 2.45 2.0792150.00 2.52 2.1761180.00 2.58 2.2553240.00 2.61 2.3802300.00 2.68 2.4771360.00 2.70 2.5563

Gradien garis , m = 1.0308Titik potong , b = 0.3184

Menentukan nilai m dan b dengan rumus regresi

x y xy0.0000 0.15 0 0.0000 39.9856 b = 0.3183830.3010 0.40 0.120411998 0.0906 Σy = 50.13 m = 1.0307530.4771 0.68 0.324442453 0.2276 Σxy = 84.29860.6021 0.78 0.469606793 0.3625 69.43260.6990 1.02 0.712949404 0.48860.7782 1.08 0.84040335 0.60550.9031 1.30 1.174016983 0.81561.0000 1.42 1.42 1.00001.0792 1.52 1.640355494 1.16461.1761 1.65 1.940550577 1.38321.2553 1.76 2.209279609 1.57571.3222 1.82 2.406439116 1.74831.3802 1.88 2.594797134 1.90501.4314 1.92 2.748218427 2.04881.4771 1.98 2.924700084 2.18191.5441 2.04 3.14989881 2.38411.6021 2.06 3.300243582 2.56661.6532 2.09 3.455214154 2.73311.6990 2.15 3.652785509 2.88651.7782 2.21 3.929714263 3.16181.9031 2.32 4.41516877 3.62182.0000 2.36 4.72 4.00002.0792 2.45 5.093994053 4.32302.1761 2.52 5.483749973 4.73542.2553 2.58 5.818603063 5.08632.3802 2.61 6.212351341 5.66542.4771 2.68 6.638684963 6.13612.5563 2.70 6.902016752 6.5347

Menentukan nilai T dan S

Persamaan garis data = 1,0308 log t + 0,3184

-0.3089

10^(-0,3089)0.4910 menit

Δs = 1.0308 m

T = = = 191.687S = = = 3.68E-06

Jarak dari sumur pompa , r =

Hitungan awal

Penurunan muka air , s (m)

x²Σx =

Σx² =

Pada saat s = 0 , t = t0 ; sehingga 0 = 1,0308*log t0 + 0,3184

Jadi log t0 = -0,3184/1,0308 =

sehingga t0 =t0 =

m²/hari

0.10 1.00 10.00 100.00 1000.000.00

0.50

1.00

1.50

2.00

2.50

3.00

Kurva s(t)

waktu pemompaan t, menit

draw

dow

n s,

met

er

0.00 0.50 1.00 1.50 2.00 2.50 3.000.00

0.50

1.00

1.50

2.00

2.50

3.00f(x) = 1.03075254970003 x + 0.318383055163965

Kurva s vs log t

log t

s

2,3×𝑄/(4𝜋×∆𝑠) 2,3×1080/(4𝜋×1,0308)2,25×𝑇×𝑡_0/𝑟^2 2,25×[191,687/(24×60)]×0,491/〖 200〗 ^2