Barokat Zainul Alam_5113413021

8/16/2019 Barokat Zainul Alam_5113413021

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Nama : Barokat zainul alam

Nim : 5113413021

42. At a point where an irrigation canal having a rectangular cross section is 1.5

m wi!e an! 3."5 m !eep# the water $lows at 2.50 cm%s. At a point !ownstream#

&ut on the same level# the canal is 1'.5 m wi!e# &ut the water $lows at 11.0

cm%s. (ow !eep is the canal at this point)

Diket : l1 : 18,5 m

h1 : 3,75 m

v1 : 2,5 cm/s = 25 x 10-3 m/s

l2 : 16,5 m

v2 :11 cm/s = 11 x 10-2 m/s

ditanya : h2 ....

di!a"a# :

$1 = $2

%1 . v1 = %2 . v2

l1 . h1 . v1 = l2 . h2 . v2

18,5 . 3,75 . 25 x 10 -3 = 16,5 . h2 . 11 x 10-2

1,73&375 = h2 . 1,815

h2 = 1,73&375 / 1,815

h2 = 0,'55 m

44. *ater is $lowing in a c+lin!rical pipe o$ var+ing circular crosssectional area#

an! at all points the water completel+ $ills the pipe.

,a- At one point in the pipe# the ra!ius is 0.150 m. *hat is the spee! o$

the water at this point i$ the volume $low rate in the pipe is 1.20 m3%s)

,&- At a secon! point in the pipe# the waters pee! is 3.0 m%s. *hat is

the ra!ius o$ the pipe at this point)

Diket : (1 = 0,15 m

$ = 1,20 m3/s

) = 3,80 m/s

(2 =



*a"a# :a. $1 = %.)

1,20 = π r 2

.v1

)1 =1,20

π r2

=1,20

3,14. 0,152

=1,20

0,07

= 17,1& m/s

#. $1 = $2

1,20 = %2.v2

1,20 = %2.3,80

%2 = 1,20/3,801,20

3,380

= 0,315 m2

%2 = π r 2

2

0,315 =

π r 2

2

(2 = √ x

π

= √0,315

3,14

= √ 0,1

(2 = 0,31 m



4'. ou/re hol!ing a hose at waist height an! spra+ing water horizontall+ with it.

he hose nozzle has a !iameter o$ 1.0 cm# an! the water splashes on the

groun! a !istance o$ 0.50 m horizontall+ $rom the nozzle. uppose +ou now

constrict the nozzle to a !iameter o$ 0."50 cm how $ar horizontall+ $rom the

nozzle will the water travel &e$ore hitting the groun!) ,gnore air resistance.-

iket :

!1 6 1# cm 6 1. 1073

81 6 0#5 m

!2 6 0#"5 cm 6 "5. 1074

it :

82 6 . . . . . . . ))

3 :

1

4 9 . ,!1-2/x2

61

4 9 . ,!2-2/x1

1

4 9 . ,!1-2. x1

61

4 9 . ,!2-2.x2

,1.1073-2.5.1072 6 ,"5.1074-2. 82

82 6 12.107' . 5.1072%"52.107.

6 12 .5 .107% "52.107

6 30"0%5'25

6 5#4"2 m

4. A seale! tank containing seawater to a height o$ 11.0 m also contains air

a&ove the water at a gauge pressure o$ 3.00 atm. *ater $lows out $rom the

&ottom through a small hole. alculate the spee! with which the water comes

out o$ the tank.

;awa& :

iketahui :

< 6 3.00 atm

h1 6 0

h2 6 11 meter

itan+a:

v 6 . . . . . . . ))



3 :

v 6 √ 2.g .∆h

;awa&

v 6 √ 2.9,8.(11−0)

v 6 √ 215,6

v 614.'m%s

Barokat Zainul Alam_5113413021

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