Bab 6 kls xii

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Induksi Elektromagnetik 131 memformulasikan konsep induksi Faraday dan arus bolak-balik, keterkaitannya, serta aplikasinya. Setelah mempelajari bab ini, Anda harus mampu: menerapkan konsep kelistrikan dan kemagnetan dalam berbagai penyelesaian masalah dan produk teknologi. Hasil yang harus Anda capai: Induksi Elektromagnetik A. Gejala Induksi Elektromagnetik B. Aplikasi Induksi Elektromagnetik Faraday C. Arus dan Tegangan Listrik Bolak-balik )141 12 >41 C5<18 [email protected]<1:1A9 =541> =17>5C G1>7 49C9=2D<;1> ?<58 ;1F1C 25A1ADB <9BCA9; 5:1<1 9>9 C5<18 491=1C9 ?<58 *. $-%./%* "-./"! @141 -18D;18 >41 218F1 @5AD2181> =541> =17>5C [email protected] =5>9=2D<;1> 1ADB <9BCA9; 5:1<1 9>9 49=1>611C;1> D>CD; =5>781B9<;1> <9BCA9; G1>7 497D>1;1> D>CD; 25A21719 ;[email protected]<D1> ,521719 3?>C?8 [email protected] [email protected]; @141 71=21A B52D18 75>5A1C?A A1;B1B1 497D>1;1> B521719 BD=25A <9BCA9; 5>5A1C?A 9>9 =5=1>611C;1> 75:1<1 9>4D;B9 5<5;CA?=17>5C9; @1;18 9>4D;B9 5<5;CA?=17>5C9; 9CD 41;18 @5=1>611C1> <19> 41A9 9>4D;B9 5<5;CA?=17 >5C9; B5<19> 75>5A1C?A 5B1A1>25B1A1> [email protected] B1:1 G1>7 C5A<921C 41<1= 9>4D;B9 5<5;CA?=17>5C9; #1F121> 1C1B @5AC1>G11>@5AC1>G11> C5AB52DC [email protected] >41 C5=D;1> 41<1= 212 9>9 (<58 ;1A5>1 9CD @5<1:1A9<18 212 9>9 45>71> 219; 131 Generator listrik mampu mengubah energi kinetik menjadi energi listrik melalui proses induksi elektromagnetik. Bab 6 Sumber: Physics Today, 1989

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1. Generator listrik mampu mengubah energi kinetik menjadi energi listrikmelalui proses induksi elektromagnetik.Induksi Elektromagnetik 131Bab6InduksiElektromagnetikHasil yang harus Anda capai:menerapkan konsep kelistrikan dan kemagnetan dalam berbagai penyelesaianmasalah dan produk teknologi.Setelah mempelajari bab ini, Anda harus mampu:memformulasikan konsep induksi Faraday dan arus bolak-balik, keterkaitannya,serta aplikasinya.A. Gejala InduksiElektromagnetikB. Aplikasi InduksiElektromagnetikFaradayC. Arus dan TeganganListrik Bolak-balik)[email protected]:1A9=541=175CG1749C9=2D;1?58 ;1F1C 25A1ADB 9BCA9;5:11 99 C518 491=1C9 ?58 *. $-%./%*-./! @141-18D;18 41 218F1 @5AD2181 =541 [email protected] =59=2D;1 1ADB 9BCA9; 5:11 99 49=1611C;1 DCD; =5781B9;1 9BCA9; G17 497D1;1DCD; 25A21719 ;[email protected] ,521719 3?C?8 [email protected] [email protected]; @141 71=21AB52D18 755A1C?A A1;B1B1 497D1;1 B521719 BD=25A 9BCA9;55A1C?A99 =5=1611C;1 75:11 94D;B9 55;CA?=175C9; @1;18 94D;B955;CA?=175C9; 9CD 41;18 @5=1611C1 19 41A9 94D;B9 55;CA?=175C9; B519 755A1C?A 5B1A125B1A1 [email protected] B1:1 G17 C5A921C 411=94D;B9 55;CA?=175C9; #1F121 1C1B @[email protected] [email protected] 41 C5=D;1 411= 212 99 (58 ;1A51 9CD @51:1A918 212 994571 219;Sumber: Physics Today, 1989 2. Tes Kompetensi Awal(0))),(-%'+*.,*!0'.%('/-+)#*/%''-'*($.+(.+(-%'0/!()0'0(/%$* )141=1C5A9212B525D=G141C518=5751(5ABC54 4571 @55=D1G1 C5C17 1ADB 9BCA9;1719=11;18 81B9 5;[email protected]=5G1 D7;9;1865?=51 ;5219;1G1 C5A:149 ,[email protected];18 G17=5=2D;C9;1G1 3. 5DADC 41 [email protected] CA1B6?A=1C?A B51D 498D2D7;145711ADB2?1;219;@1G171;1132 Mudah dan Aktif Belajar Fisika untuk Kelas XIIC5A:149 :9;1 CA1B6?A=1C?A 498D2D7;1 @141 1ADBB51A18-18D;18 41 141 [email protected] :59B CA1B6?A=1C?A 25A41B1A;16D7B9G1 @1;[email protected];[email protected]?A4194D;C?A25A41B1A;1:[email protected]=51D9G1A. Gejala Induksi Elektromagnetik1. Pengertian Induksi Elektromagnetik*. $-%./%* -./! C518 25A81B9 =5=2D;C9;1 218F1 1ADB9BCA9; [email protected] =59=2D;1 =541 =175C9; D1 251B C18D ;5=D491B5C518 @55=D1 (5ABC54 B5?A17 189 69B9;1 25A1=1 % $( [email protected] =51D9B5A17;1915;[email protected]=5G17491;D;1G125A81B9=55=D;161;C1;5219;1G1218F1'('!(-#%*-'(#'.%(+.,#,-+#% 5:1199491=1;1 #(.%,#%-+)'!(-#%1C1D#',%-+)'!(-#% 1C1D B5A97 @D1 49B52DC #(.%,# 4. +2 )5A81C9;1)-)-=5D:D;;1 @5A11C1 B545A811 [email protected] G17 497D1;1 ?58 % $( -!2 $5C9;1 21C17 =175C 4975A1;;1 =5D:D;[email protected] 41 =5:1D89 ;[email protected] :1AD= 71E1?=5C5A 25A75A1;[email protected] AC9G1 411= ;1F1C @5781C1A =5719A 1ADB 9BCA9;5A41B1A;1 61;C1 C5AB52DC [email protected] [email protected];1 218F1 $#% ,.%.'*+( '(!'# *+.( $.' !+#,!+#, !2 '!(-#%.%,'!(-#% * .$.(!.$.(! %0- %.'*+( -#'. !2 !+% #,-+#% !!#9;1 D:D7D:D7 ;[email protected] 99 498D2D7;1 4571 A17;191 [email protected]@141 A17;191 C5AB52DC 1;1 =5719A 1ADB 9BCA9; ADB G17 =5719AC5AB52DC 491=1;1 1ADB 94D;B9 [email protected] 77 @141 D:D7D:D7 ;1F1C49B52DC 77 94D;B9Gambar 6.1Induksi elektromagnetik(a) ketika magnet diam, jarumgalvanometer juga diam, (b) ketikamagnet dimasukkan ke dalamkumparan, jarum galvanometerbergerak ke kanan, dan (c) ketikamagnet dikeluarkan dari dalamkumparan, jarum galvanometerbergerak ke kiri.123Aktivitas Fisika 6.1Induksi ElektromagnetikTujuan PercobaanMengamati arus induksiAlat-Alat Percobaan1. Kumparan2. Galvanometer3. Magnet batangLangkah-Langkah Percobaan1. Susunlah peralatan seperti gambar berikut.magnet kumparangalvanometer 5. TokohMichael Faraday(17911867)Sumber: www.allbiographies.comMichael Faraday adalah seorang ahliFisika, ahli Kimia, dan ahli Filsafatberkebangsaan Inggris, tepatnyalahir di Newington Butts, Surey, padatahun 1971. Ia bersama-sama denganJoseph Henry menemukanfenomena induksi elektromagnetik.Penemuan ini merupakan kebalikandari penemuan Oersted, yaitu darimedan listrik dapat menghasilkanarus listrik. Induksi Elektromagnetik 1332. Siapkan magnet batang, kemudian dekatkan pada kumparan, dan diamkan.Catat hasil pengamatan Anda.3. Gerakkan magnet mendekati kumparan atau masukkan ke dalam kumparan.Amati jarum galvanometer dan catat hasil pengamatannya.4. Diamkan magnet batang di dalam kumparan. Amati jarum galvanometer dancatat hasil pengamatannya.5. Gerakkan magnet batang dengan arah menjauhi kumparan atau keluarkumparan, amati jarum galvanometer, dan catat hasil pengamatannya.6. Balikkan polaritas magnet batang, lakukan lagi percobaan langkah 2 danlangkah 5. Catat hasil pengamatannya.7. Tulis kesimpulan Anda tentang kegiatan ini.2. Hukum Faraday 7 94D;B9 4981B9;1 41A9 @A?B5B 94D;B9 55;CA?=175C9;794D;B9 C9=2D :9;1 141 @5AD2181 6D;B =541 =175C49 411=;[email protected] 94D;B9 9918 G17=5G5212;1=5719AG1 1ADB 9BCA9;94D;B9 @141 BD1CD A17;191 [email protected];B925A71CD7;[email protected];C?A61;C?AB52171925A9;DC1 $. *+.(.%, '( '!(- ' %.'*+( ,5=1;9 25B1A1:D @5AD2181G1 B5=1;9 25B1A @D1 77 G17 4981B9;12 .' ##-( %.'*+( ,5=1;9 21G1; :D=18 99C1 ;[email protected]=1;9 25B1A @D1 77 G17 4981B9;15A41B1A;181B95;[email protected]=5G17491;D;1G1-!2=5GDBD!D;D= 1A141G !D;D= 99 G17 =5G1C1;1 218F1 !2 !+% #,-+#%#(.%,# ,(#(! (!( $. *+.(.%, '( '!(- 2(! -+$# #' %.'*+( )5AG1C11!D;D= 1A141G 99 [email protected] 49G1C1;1 411=25CD; @5AB1=11 B521719 25A9;DC- J$5C5A17177 94D;B9 /-B517F1;CD [email protected] 6D;B =175C9; 02:D=18 99C1(58;1A513?B-.)* [email protected];[email protected]=11 25A9;DC 3?B -J 6. $5C5A171 ;D1C =541 =175C9; 02= 7. D1B 29417 ;[email protected] = 8. BD4DC 1C1A1 1A18 94D;B9 =175C9; 41 1A18 ?A=1 29417;[email protected];1 -.)*3 [email protected] [email protected]=9 218F1 77 94D;B91C1D 1ADB 94D;B9 [email protected] C5A:149 1;921C1 @5AD2181 ;D1C =541 =175C9;2 @5AD2181D1B29417;[email protected]=2DB?58=541=175C9;Gambar 6.2Garis-garis gaya magnetik yangmembentuk sudut terhadapgaris normal.BAgarisnormalI 9. Tantanganuntuk AndaBagaimana pengaruh perubahanlilitan terhadap ggl induksi?Contoh 6.1,52D18=175C4975A1;;1=5:1D89;[email protected]=F1;CDB6D;B=175C9;G17=55=2DB;[email protected];DA1741A9K J02=5:149 10. K [email protected];B9;[email protected]:D7D:D7;[email protected];5C18D999C1- B 11. K J02JK J02JK J02 02- 12. / B #14977G174994D;B9;114118 13. /3. Ggl Induksi karena Perubahan Luas Bidang Kumparan,5BD19 4571 !D;D= 1A141G [email protected] ;19 BD1CD 21C17 ;?4D;C?A25A75A1; 411= =541 =175C9; 89771 =5=?C?7 71A9B71A9B 71G1=175C9; 1;1 C9=2D 77 94D;B97 94D;B9 [email protected] C5A:149 1;[email protected] D1B 29417 ;[email protected] G17 49C5=2DB ?58 =541 =175C9;)5A81C9;1)[email protected] 41C571;DADB=1BD;29417;5AC1B#9;[email protected])*4975A1;;1 ;5 ;11 4571 ;[email protected] / B5:1D8 1 1;1 C5A:149 @5AD2181 71A9B71G1 G17 4997;[email protected] ?58 21C17 ;?4D;C?A )* 4571 A17;191 ;1F1C. )5AD2181 D1B @5A B1CD1 F1;CD 1;921C @5A75B5A1 21C17 ;?4D;C?A)* =5=5D89 @5AB1=11 25A9;DCBv134 Mudah dan Aktif Belajar Fisika untuk Kelas XII1 1/ - - -571 45=9;91 77 94D;B9 =5=5D89 @5AB1=11 25A9;DC /- - - J -141 571C96 =5D:D;;1 1A18 94D;B9 55;CA?=175C9; 25A1F114571 1A18 @5G5212 C5A25CD;G1 94D;B9 .CD; @[email protected] B5A97;19 C141 571C96 C941; 49CD9B .CD; ;[email protected] G17C5A49A9 1C1B B1CD [email protected]=11G1 =5:149 / J(58 ;1A51 ;1F1C 25A25CD; . 41 21C17 ;?4D;C?A )*=5=25CD; A17;191 [email protected] @141 ;1F1C C5AB52DC 1;1 =5719A 1ADB94D;B9A18 1ADB 94D;B9 G17 [email protected];1 @141 )- [email protected];1 4571 [email protected];1 !D;D= %5H G17 =5G1C1;1 218F1:9;1 1A18 94D;B9 =175C =5D:D ;5 411= 29417 ;5AC1B 41 1A18 /Gambar 6.3Penghantar PQ digerakkandengan kecepatan v di dalammedan magnet homogen B.RPQvxIGambar 6.4Gerak elektron dalam batangkonduktor bergerak di atasmedan magnet.Fve 14. Informasiuntuk AndaInformation for YouInduksi Elektromagnetik 135;5 ;11 =D1C1 571C96 @141 21C17 ;?4D;C?A )* 1;1 [email protected] ;5 21F18 A18 1ADB 9BCA9; B5BD19 4571 1A18 =D1C1 @?B9C96B589771 1A18 1ADB 94D;B9 411= 21C17 ;?4D;C?A 14118 41A9 * ;5 )(58 ;1A51 1A18 1ADB 94D;B9 411= 21C17 ;?4D;C?A 41A9 * ;5 )B5417;1 1A18 94D;B9=175C9; ;5 411= 29417 ;5AC1B 1;1 C9=2D71G1 =175C9; 15. G17 1A18G1 ;5 ;9A9 41 [email protected] =5=2D;C9;1G1=577D1;1 ;19418 C171 ;11 5B1AG1 71G1 =175C9; C5AB52DC=5=5D89 @5AB1=11 16. J41 @5A81C9;1 ;5=219 )-11= ;1F1C . =5719A1ADB 9BCA9; 1;921C 141G1 2541 @?C5B91 49 1C1A1 C9C9;)41* 5B1AG1 2541 @?C5B91 C5AB52DC B1=1 4571 25B1AG1 77 94D;[email protected] 21C17 ;?4D;C?A5A41B1A;1 !D;D= (8= 25B1AG1 ;D1C 1ADB 9BCA9; G17 [email protected] ;1F1C . 14118 B521719 25A9;DC /J5DADC !D;D= $5;5;11 5A79 55A79 G17 497D1;1 DCD;=5=9418;1 =D1C1 49 411= 21C17 ;?4D;C?A )* B1=1 457155A79G17497D1;1DCD;=5=9418;[email protected];1F1C.(58;1A51 9CD ;D1C 1ADB G17 =5719A 411= ;1F1C . B1=1 4571 ;D1C1ADB94D;[email protected];?4D;C?A)*57145=9;91-.)*[email protected] 49BD2BC9CDB9;1 ;5 411= -.)*3 17. B589771 [email protected]?58 @5AB1=11 21AD B521719 25A9;DC 18. / 19. / J$5C5A171 20. 71G1 %?A5CH '/ ;[email protected] =B ;D1C =541 =175C 02= 21. @1:17 @5781C1A =81=21C1 Para teknisi ini sedang memasanggenerator pada instalasi pembangkitlistrik di Meksiko. Bagian yangterlihat di sini adalah stator, yangtidak bergerak. Selanjutnya, ke dalamstator itu dimasukkan rotor. Rotormerupakan sebuah elektromagnetikkuat yang dapat berputar dengankecepatan tinggi. Akibat perputaranrotor, terjadi perubahan medanmagnetik dan membangkitkan aruslistrik pada kumparan di dalam stator.The pisture have shown thetechnician placing generator onelectrical instalation in Mexico. Youcan see a part, called stator. The rotoris put inside it. Rotor is a strongelectromagnetic device that can spinwith cause the velocity. That spin iswhat cause the change of magneticfield and generate electrical elementon coil inside stator.Sumber: The Oxford Childrens Book ofScience, 1995Contoh [email protected])*@1:17G1 22. 3=41=1BB1G1 [email protected];E5AC9;12521B;[email protected];1F1CA17;1919B5;[email protected]=541=175CB525B1A -45711A18;5D1A29417;[email protected][email protected];@14171=21AQPBR0,25Fw = mg v20 cm 23. Tantanganuntuk AndaSebuah penghantar berbentuk Uterletak di dalam daerah berinduksimagnetik homogen B = 4 103 Tberarah menembus bidang kertas.Penghantar PQ sepanjang 40 cmmenempel pada penghantar U dandigerakkan ke kanan dengankecepatan tetap v = 10 m/s. Hitungggl induksi antara ujung-ujung PQ.-5CD;11 1A181ADB411=;[email protected])*2 ;[email protected];?BC1;[email protected]@5781C1A)*B525B1A 24. '!=5G5212;[email protected])*25A75A1;4571;[email protected]/;521F18 5A1;@5781C1A)*G17=5=?C?7C571;DADB =541 =175C =59=2D;1 71G1 %?A5CH 25. G17 1A18G1 ;5 [email protected];[email protected])*[email protected];5C9;125B1A71G1%[email protected])*,5BD194571!D;D=%[email protected];145711CDA1;19418C171;[email protected]@14171=21AA1894D;B9=175C9;;5D1A294171A1871G1%?A5CH;51C1B411A181ADB#@[email protected];5;9A9G19CD41A9*;5)'! ;7=B 26. Informasiuntuk AndaSumber: www.linearmagnetics.comInformation for You136 Mudah dan Aktif Belajar Fisika untuk Kelas XIIarah telapak tanganFarah ibu jari arah jari lainBI2 [email protected] ;?BC1 [email protected] ;5C9;1 71G1 %?A5CH B1=1 4571 71G1 [email protected];5C18D971G1%[email protected])* 3 27. / 28. B5417;171G1 29. '!B589771 30. /'! 31. // 32. 02= 33. = 34. =B#149;[email protected];?BC1;1F1C14118 35. =B4. Induktansi Diri#9;1 B52D18 ;[email protected] 4919A9 1ADB 9BCA9; G17 25B1AG1 25AD218D218 [email protected] F1;CD 1;1 C9=2D 6D;B =175C9;' G17 25B1AG1:[email protected];CD)5AD21816D;B=175C9;B5214974571;D1C 1ADB ,531A1 =1C5=1C9B 49CD9B B521719 25A9;DC' 1C1D'[email protected];1 BD1CD ;?BC1C1 G17 49B52DC 4571 94D;C1B949A9 ;[email protected] C5AB52DC 4D;C1B9 49A9 C571; DADB [email protected] 25CD;75?=5CA9; ;[email protected] ,1CD1 94D;C1B9 9118 85AG ! 5CD;D=D= 949;1C?A [email protected] B?5?941 B531A1 17BD7 94D;C1B9 49A9B?5?941 99 [email protected] 4989CD7 [email protected] 25A9;DC 99 J2 ' Induktor adalah sebuahelektromagnet, yaitu sebuahkumparan kawat dengan atau tanpainti magnetik yang menghasilkanmagnetisme jika arus mengalirmelewatinya.Inductor is an electromagnet, made ofwire coil with or without magneticcore which can produce magnetismwhen electric current through.Sumber: Jendela Iptek, 1997 36. PL I1SSLP2Induksi Elektromagnetik 137(58 ;1A51 6D;B =175C9; DCD;99C1 @141 B?5?941 14118' ( ( 37. =1;194D;C1B949A9B?5?94114118B521719 25A9;DC( 38. J-.)*3 25A1;D :D71 DCD; 94D;C1B9 49A9 @141 @DB1CC?A?941 ;1A51 25B1A 94D;B9 =175C 49 1C1A1 ;54D1G1 B1=1 G19CDB525B1A(#9;[email protected][email protected]?5?9411C1DC?A?941499B9?582181G17=5=99;[email protected]=51299C1B A51C96 + 49=11 @5A=51299C1B 2181 14118+ J 4D;C1B9 49A9 B?5?941 41 C?A?941 4571 2181 C5AB52DC 14118 39. +( J$5C5A17194D;C1B9 49A9 B?5?941 1C1D C?A?941 4571 9C9 2181 ! 94D;C1B9 49A9 B?5?941 1C1D C?A?941 [email protected] 9C9 !Gambar 6.5Sebuah rangkaian tertutup (a) saklar sditutup, lampu menyala dan (b) saklar sdibuka, lampu masih menyala beberapasaat kemudian padam.Contoh [email protected][email protected]= 40. [email protected]:17G1 3==5=99;999C1-5CD;11894D;C1B949A9C?A?941C5AB52DC19;5C18D9 3= 41. K J= 42. 3= = K [email protected]?58 43. 02= = 44. = K J! 45. !#14994D;C1B949A9C?A?94114118!,D1CD A17;191 G17 C5A49A9 1C1B B52D18 ;[email protected] 94D;C?A B52D18 [email protected] ) 41 BD=25A C57171 G17 4957;[email protected] 4571 B52D18B1;[email protected]; @141 )- 46. $5C9;1 B1;1A 498D2D7;1 [email protected]; B575A1 =5G11 =1;B9=D= [email protected] 141 :541 F1;CD B5B11C )141 B11C1ADB [email protected];1 @141 B1;1A @578D2D7 [email protected] C941; B575A1 @[email protected] 141 :541 F1;CD B5B11C )5A81C9;1 )- 47. )5A9BC9F1 99=5D:D;;1 C9=2DG1 1ADB 94D;B9 G17 49B5212;1 ?58 [email protected] 6D;B =175C9; @141 94D;C?A )5AD2181 1ADB @141 B52D18 ;[email protected] [email protected] =59=2D;1 7794D;[email protected]@5AD2181;D1C1ADBG1 ,531A1 =1C5=1C9B @5AG1C11 G17 49;5=D;1;1 @5AC1=1 ;19?58 +.,$ *-2 99 49CD9B;1 B521719 25A9;DC - J 48. Pembahasan SoalKuat arus listrik dalam suaturangkaian tiba-tiba turun dari 10 Amenjadi 2 A dalam waktu 0,1 s.Selama peristiwa ini terjadi, timbulggl induksi sebesar 32 V dalamrangkaian. Induktansi rangkaianadalah ....a. 0,32 Hb. 0,40 Hc. 2,5 Hd. 32 He. 40 HUMPTN 1993Pembahasan:Diketahui:I = 10 A 2 A = 8 A ind = 32 V inddILd32 V =3,2 V8 AsL =3,28s VA= 0,4 HJawaban: e 49. Ia bGambar 6.6Sebuah kawat induktoryang dialiri arus listrik.-141 571C96 [email protected];1 @5G5BD191 4571 !D;D= %5H #9;11:D @5AD2181 ;D1C 1ADB --138 Mudah dan Aktif Belajar Fisika untuk Kelas XII -;?BC1 =1;1 -.)*3 [email protected];1 B521719 25A9;DC 50. - - -J $5C5A171 ;D1C 1ADB 9BCA9; @141 ;51411 1F1 51. ;D1C 1ADB 9BCA9; @141 ;51411 1;89A -- 52. J - B517 F1;CD @5AD2181 ;D1C 1ADB 9BCA9; BContoh 6.4,52D18;[email protected];C1B949A9!4919A91ADBB5217196D7B9F1;CDJ- 53. [email protected]=B5;?-5CD;17794D;B949A9G17C5A:149B11C- 54. B19;5C18D9 ! J- 55. 571=577D1;1-.)* [email protected]?58 56. J!J-JJ 57. /#1497794D;[email protected] 58. 14118/5. Energi yang Tersimpan dalam Induktor4D;[email protected][email protected][email protected]=25CD; =541 =175C )5A81C9;1 )-#9;1 B52D18 94D;C?A 4919A91ADB9BCA9; [email protected];CD25B1AG1C571711C1A1 C9C9;4114118J-B589771 25B1AG1 41G1 G17 4925A9;1 @141 94D;C?A 14118 - - J5A79 G17 4925A9;1 @141 94D;C?A [email protected]?58 4571 =579C57A1B9;1 41G1 @141 94D;C?A B589771 [email protected]?58 @5AB1=11 - -- 59. Induksi Elektromagnetik 139 60. J 61. 6. Rapat Energi dalam Bentuk Medan Magnetik-518 49;5C18D9 25B1AG1 94D;B9 =175C9; 49 @DB1C B?5?941=5=5D89 @5AB1=11 25A9;DC ( 1C1D ([email protected] 94D;C1B9 49A9 @141 B?5?941 14118( 62. #9;1 91941 919 94D;C1B941 BD2BC9CDB9;1 ;5 411= -.)*3 1;1 [email protected]?58 @5AB1=11 63. ( J( 64. 571 E?D=5 B?5?941C?A?941 14118 #9;1 [email protected] 55A791C1D 55A79 @5A B1CD1 E?D=5 ;9C1 4925A9 ?C1B925A1;D 8D2D71 65. J 66. Contoh 6.5,52D18 B?5?941 =5=99;9 :D=18 99C1 B521G1;2D18 @1:17 41 [email protected][email protected]?5?941141183=41 67. 3= 68. !9CD7181 94D;C1B949A9B?5?9412 55A79G174981B9;[email protected]?5?941:9;11ADB9BCA9;G17=5719AB525B1A 3 25B1A7794D;B949A9G17C5A:149:9;1411=F1;CDB;D1C1ADB25AD218=5:149 69. 19;5C18D9 99C1 70. 3= 71. K J= 72. 3=K J 73. = 1 4D;C1B949A9B?5?94114118 74. 02= 75. = 76. ! =2 5A79G174981B9;[email protected] 77. !# 78. 3 5B1A%94D;B949A9:9;11ADB25AD218=5:149 79. 14118 80. ! 81. /B - Tantanganuntuk AndaSebuah kumparan (solenoida)memiliki induktansi 500 mH.Hitunglah besar induksi ggl yangdibangkitkan dalam kumparan itujika ada perubahan arus listrik dari100 mA menjadi 40 mA dalam waktu0,01 s secara beraturan. 82. Gambar 6.8IPerubahan arus pada kumparan1 akan memengaruhi arus padakumparan 2.Kata Kunci gaya gelak listrik (ggl) induksi elektromagnetik Hukum Faraday fluks medan magnetik Hukum Lenz gaya Lorentz ggl induksi diri kumparan primer kumparan sekunder induktansi silang8. Induktansi Silang)5A81C9;1 )- [email protected]; 4D1 2D18 ;[email protected] G19CD;[email protected]@A9=5A)41;[email protected];D45A,G1725A45;[email protected]@A9=5A)498D2D7;[email protected];D45A,498D2D7;14571B52D1871E1?=5C5A #9;1 @141 ;[email protected] @A9=5A C5A:149 @5AD2181 ;D1C 1ADB 4571=57D218D21881=21C11;1C5A:[email protected];B=175C9;@141;[email protected] @A9=5A 571 45=9;91 6D;B =175C9; G17 4997;[email protected];[email protected] B5;D45A @D 1;1 25AD218 @D1 )5AD2181 6D;B =175C9;C5AB52DC 1;1 =59=2D;1 77 @141 ;[email protected] B5;D45A [email protected];[email protected]@[email protected];[email protected];D45A49B52DC #(.%-(,# ,#(! 1C1D #(.%-(,# -#' #% 5B1AG1 77 94D;B9G17 C9=2D @141 ;[email protected] B5;D45A ;1A51 @571AD8 @5AD2181 6D;B=175C9; 411= F1;CD - =5=5D89 @5AB1=11140 Mudah dan Aktif Belajar Fisika untuk Kelas XII 83. - - J 84. - -J 85. #9;1 -.)*3 49C9:1D 5298 1:DC [email protected]?58 86. 1C1D- -571 =5C?45 9C57A1B9 1;1 [email protected]?58 87. J 88. 571 =577D1;1 @511A1 G17 B1=1 =1;1 41A9 -.)* 3 1;1 [email protected]?58 89. J 90. 5B1A 6D;B =175C9;G17 49C9=2D;1 ?58 1ADB 9BCA9; 4571:D=1899C114118 #9;1919 49BD2BC9CDB9;1 ;5 411= -.)*3 [email protected]?58 @5AB1=11 25A9;DC 91. J 92. $5C5A171 ;D1C 1ADB 9BCA9; ;[email protected] @A9=5A 94D;C1B9 B917 ! 93. :D=18 99C1 ;[email protected] B5;D45A:D=18 99C1 ;[email protected] @A9=5A 94. 6D;B =175C9; G17 4997;[email protected] ?58 ;[email protected] B5;D45A G17 49C9=2D;1 ?58 ;[email protected] @A9=5A 02Gambar 6.7Induktor silang antaradua buah kumparan.RP SG 95. R = 0,5 v = 20 m/sBInduksi Elektromagnetik 141Contoh 6.6,52D18B?5?941;[email protected]=5=99;[email protected]:17 [email protected][email protected] J = 96. 4121G1;99C1 97. 99C19B5;[email protected]?5?9414999C;1;[email protected] 98. 457121G1;99C1 99. 99C1-5CD;11 94D;C1B9B917;54D1;[email protected] [email protected];[email protected] 100. :9;[email protected];[email protected]=5719A1ADBB525B1A 101. G1725A219;1A18411=F1;CD B11 571 =577D1;1 -.)*325B1A 94D;C1B9 B917 [email protected];1B52171925A9;DC 102. 02= 103. == 104. K J 105. !2 )141;[email protected];B517F1;CD- B;D1C1ADB 106. 25A219;1A18B589771 # J 107. J 108. J5B1A7794D;[email protected];[email protected] 109. [email protected]@5A?58B52171925A9;DC2 - 110. ! 111. /BTes Kompetensi Subbab A-'*($!()0'0(/%$* #9;[email protected]=154975A1;;1=5=1BD;9;[email protected];[email protected][email protected]=5C5A11CD;DA1ADB :1AD= [email protected]=5C5A 1;1 [email protected] 41A9;54D4D;1 B5C9=217G1 5B1A1 [email protected];18 G17=5G5212;1 C9=2DG1 @[email protected] [email protected];18G17C5A:[email protected]:[email protected]=5C5A:9;11 21C17=175C491=411=;[email protected] 21C17=175C4975A1;;[email protected] 21C17=175C4975A1;;1;5D1A41A9;[email protected] 112. D;B =175C9; G17 =5=?C?7 BD1CD ;[email protected];DA1741A902=5:149 02411=F1;CD B#9;1;[email protected];177G174981B9;1)141B52D1894D;C?A4571 99C1=5719A1ADB9BCA9;[email protected];CDG19CDB11= F1;CD G17 B1=1 =59=2D;1 @5AD21816D;B=175CG174997;[email protected];11 94D;B949A9;[email protected] 7794D;B949D:D7D:D7;[email protected] ,[email protected]?C?7;1F1C25A75A1;=5=?C?7=541=175C9;8?=?75G1725B1AG1 113. -41=5=25CD;BD4DC I#9;1D1B6D;[email protected]?C?7 = 114. 411=F1;CD BC5CD;17794D;B9G17C9=2D $1F1C )* [email protected]:17 115. 3= 4975A1;;1 ;5 ;114571;[email protected] 116. =B41=5=?C?7C571;DADB94D;B9=175C9; K J 117. [email protected]@14171=21A-5CD;125B1A71G1%[email protected];1F1C)*411A181ADBG1PQ 11=B52D18;[email protected]@[email protected];D1C1ADBB525B1AG17 =59=2D;1 @5AD2181 6D;B=175C9; 118. [email protected];[email protected];54D1G17C5A5C1;49D1A;[email protected]@5AC1=1-5CD;194D;C1B9B917;54D1;[email protected]:9;1;[email protected];54D1=5=99;9 99C1 119. B. Aplikasi Induksi Elektromagnetik [email protected];1B9 94D;B9 55;CA?=175C9; 1A141G 411= ;[email protected] B581A981A9 1C1A1 19 B521719 25A9;DC1. Generator)5A18;18 41 25A;D:D7 ;5 [email protected] )5=217;9C %9BCA9; -51719A G17 141 49 #1C9D8DA #1F1 1A1C 9 B11 [email protected] 11C 9BCA9; G17491=1;1 !(+-)+55A1C?A 14118 11C G17 25A6D7B9 =57D21855A79 ;95C9; =5:149 55A79 9BCA9;55A1C?A 25;5A:1 25A41B1A;[email protected]@ 94D;B9 55;CA?=175C9; [email protected] 4D1 :59B 755A1C?A G19CD755A1C?A 1ADB 2?1;219; 41 755A1C?A 1ADB B51A18a. Generator Arus Bolak-Balik)- =5D:D;;1 B;5=1 755A1C?A 1ADB 2?1;219; 1A1;5A:1 755A1C?A C5AB52DC 14118 B521719 25A9;DC [email protected] G17 495C1;;1 411= =541 =175C9; [email protected] [email protected]:D=1871A9B71G1=175C9;;921CG1C5A:14977 94D;B9 G17 [email protected] =5781B9;1 1ADB 9BCA9; ADB 9BCA9; G174981B9;1G1 [email protected] 1ADB 2?1;219;1C1D -+(-#(! .++(-;1A51 [email protected] ;1A2? 1;1 [email protected];1 @?1A9C1B 77 94D;B9 G1725AD218D218 ;DCD2 @?B9C96 41 ;DCD2 571C96 B531A1 25A71C91 120. .CD;=5G1DA;11ADB9BCA9;[email protected]?58;54D1D:D7;[email protected]@1B179 3939 G17 [email protected] 41 [email protected];1 @141 B9;1C ;1A2?G17 498D2D7;1 4571 ;125 @5G1DA142 Mudah dan Aktif Belajar Fisika untuk Kelas XIIsikatkarboncincinkumparanarah putaran luncurb. Generator Arus Searah)[email protected]@;5A:[email protected]@;5A:1 755A1C?A 1ADB 2?1;219; )5A25411G1 @141 755A1C?A 1ADBB51A18 [email protected] %)'.--)+ [email protected] B52D18 3939 2518 D7B9 ;?=DC1C?A99 =571CDA 171A [email protected] B9;1C ;1A2? B51D [email protected];1 @?1A9C1B 7794D;B9 G17 [email protected] B9;1C @5AC1=1 @?B9C96 41 B9;1C 19G1 571C962. Transformator (Trafo)+(, )+'-)+ 14118 11C G17 25A6D7B9 =57D218 =519;;1 1C1D=5DAD;1 C57171 9BCA9; (58 ;1A51 9CD CA1B6?A=1C?A 492179=5:1494D1:59BG19CDCA1B6?A=1C?A,-*.*41CA1B6?A=1C?A,-*)0(Gambar 6.9Skema generator arus bolak-balikGambar 6.10Skema generator arus searahkumparankomutatorsikat karbonarah putaran 121. primerNpInduksi Elektromagnetik 143-A1B6?A=1C?A C5A49A9 1C1B ;[email protected] @A9=5A ;[email protected] B5;D45A 41 9C925B9 ?C?8 CA1B6?A=1C?A 49CD:D;;1 @141 )-a. Transformator Step-up-A1B6?A=1C?A,-*.*25A6D7B9=519;;1C571719BCA9;171B545A811B52D18CA1B6?A=1C?A,-*.*49CD:D;;[email protected])- )[email protected]@:D=1899C1B5;D45A529821G1;[email protected]:D=18 99C1 @A9=5A , *b. Transformator Step-down-A1B6?A=1C?A ,-*)0( 25A6D7B9 =5DAD;1 C57171 9BCA9; 171 B545A811 B52D18 CA1B6?A=1C?A ,-*)0( 49CD:D;;1 @141)-)141 CA1B6?A=1C?A ,-*)0( :D=18 99C1 @A9=5A 529821G1; [email protected] :D=18 99C1 B5;D45A * ,)[email protected] ;5A:1 CA1B6?A=1C?A 14118 B521719 25A9;DC [email protected] @A9=5A 498D2D7;1 4571 C57171 =1BD;1 [email protected] 2?1;219; 25B1A 41 1A18G1 B51D 25AD218D218 122. (58 ;1A51 1ADB G17 25AD218D218 @141 9C9 25B9 C5A:149 @5AD2181:D=18 71A9B 71G1 =175C9; B531A1 C5ADB=55ADB ;921CG1 @141;[email protected];D45AC5A:1497794D;B9411ADB94D;B9B521719;5D1A1).-*.- 41A9 CA1B6?A=1C?A)5A214971 1C1A1 C57171 @A9=5A * 41 C57171 B5;D45A, @141 CA1B6?A=1C?A B1=1 4571 @5A214971 1C1A1 :D=18 [email protected]=5A * 41 99C1 B5;D45A , ,531A1 =1C5=1C9B [email protected] 49CD9BB521719 25A9;DC* * J 123. , ,$5C5A171*C57171 @A9=5A /*:D=18 99C1 @A9=5A,C57171 B5;D45A /,:D=18 99C1 B5;D45A#9;1 @141 CA1B6?A=1C?A [email protected] C941; 141 55A79 9BCA9; G17 25AD218 =5:149 55A79 25CD; 19 CA16? 9451 25A1;D 8D2D71 B52171925A9;DC41G1 @A9=5A41G1 B5;[email protected]@ @B B J 124. $5C5A171*41G1 @A9=5A 0,41G1 B5;D45A 0 *1ADB @A9=5A,1ADB B5;D45A Gambar 6.11TransformatorGambar 6.12Bagan transformator step-upsekunderNsGambar 6.13Bagan transformator step-downSumber: PHYWE, 1989primerNpsekunderNs 125. *144 Mudah dan Aktif Belajar Fisika untuk Kelas XIIAktivitas Fisika 6.2Membuat TransformatorTujuan PercobaanMembuat transformator step-up.Alat-Alat Percobaankumparan1. Kawat tembaga kira-kira 1 m2. Sumber tegangan 12 V (AC)Langkah-Langkah Percobaan1. Susunlah peralatan seperti gambar berikut.2. Lilitkan 10 lilitan kawat pada bagian kiri inti besi, sebagai kumparan primer.Kemudian, sebanyak 20 lilitan pada bagian karena inti besi yang lain, sebagaikumparan sekunder. Hubungkan dengan sumber tegangan.3. Catat besar tegangan yang terbaca pada voltmeter.4. Teruskan menambah 10 lilitan pada kumparan sekunder hingga menjadi 50lilitan. Amati dan catat besar tegangan yang terbaca pada voltmeter.5. Masukkan data hasil pengamatan Anda pada tabel. Kemudian, buatlah grafiktegangan sekunder terhadap jumlah lilitan sekunder.6. Berikan kesimpulan Anda dari kegiatan ini.inti besivoltmeterNo1.2.3.4.Jumlah Lilitan Sekunder20304050Data PercobaanBesar Tegangan Sekunder................Contoh 6.7,[email protected]?F1;1497D1;1DCD;=5G11;1A149? 126. /41A9BD=25A)%' 127. /-5CD;11 @[email protected]=5A41B5;D45ACA16?C5AB52DC2 :[email protected]=5A:9;199C1B5;D45AG199C13 1ADBG17497D1;1A149?:9;149;[email protected]@[email protected] 19;5C18D9* 128. /,99C1, 129. / * 1 )[email protected]:D=1899C1 130. / 131. /* * *, , ,#[email protected]*B 2 5A41B1A;[email protected]=1;1* #149:[email protected]=5A 99C13 .CD;=5789CD71ADB9BCA9;[email protected];[email protected]=11*,1C1D* *, , 132. / 133. /* ,,, * , #1491ADBG17497D1;1A149?14118Tantanganuntuk AndaAnda memiliki walkman yangmenggunakan baterai 3 V.Bagaimana caranya agarwalkman tersebut dapatmenggunakan listrik dari PLNyang besarnya 220 V? 134. Ingatlahkumparanarus pusar inti besi12Induksi Elektromagnetik 145)141;5G1C11G1C941;141CA1B6?A=1C?AG179451,52179155A799BCA9; 25AD218 =5:149 25CD; 55A79 19 411= CA1B6?A=1C?A =9B1G155A79 @11B #149 DCD; CA1B6?A=1C?A C941; 9451 B51D 25A1;D 41G1B5;D45A 5298 ;539 [email protected] 41G1 @A9=5A ,* B589771 569B95B9G15298 ;539 41A9 69B95B9 B52D18 CA1B6?A=1C?A 4945699B9;1 B521719 81B9 2179 41G19BCA9; B5;D45A 4571 41G1 9BCA9; @A9=5A 69B95B9 CA1B6?A=1C?A49G1C1;1 411= @5AB5 B531A1 =1C5=1C9B 49CD9B, * J 135. $5C5A171569B95B9 CA1B6?A=1C?A,41G1 9BCA9; B5;D45A*41G1 9BCA9; @A9=5AContoh 6.8Tidak ada transformator yangefisiensinya 100% karena sebagianenergi listrik berubah menjadibentuk energi lain.,[email protected]=57D218C5717141A9 136. /=5:149/#D=1899C1B5;D45AG1 99C1C5AG1C1;[email protected]? #9;1569B95B9CA1B6?A=1C?AC5AB52DC C5CD;11 ;D1C1ADB9BCA9;@141;[email protected]@A9=5A2 [email protected]=5A4141G1B5;D45A19;5C18D9* 137. /, 99C1,/ , 1 -A1B6?A=1C?AC941;25AB961C9451=1;125A1;D, , ,* * * / 138. / **#149;D1C1ADB9BCA9;@141;[email protected]@A9=5A14118 139. 2 .CD;[email protected]@;[email protected]@1C497D1;[email protected]=11* * * 140. / 141. 0#[email protected]=5AG1141180, , ,/0#14941G1B5;D45AG114118 0c. Arus Pusar pada Transformator)5A81C9;121C17;?4D;C?A1C1A14D1=D;1;DCD255;CA?=175C9;[email protected] G17 49CD:D;;1 @141 )- #9;1 =541 =175C9;1C1A1 =D;1 ;DCD2 9CD 25AD218 [email protected] F1;CD 6D;B G17 =51D9B5=21A17 [email protected] [email protected] 411= 21C17 1;1 25AD218 :D71 B589771C9=2D 1ADB ADB 99 491=1;1 4571 +., 2 1C1D 1ADB @DB1AADB @DB1A G17 C5A:149 @141 9C9 CA16? =5AD79;1 B5212 CA16?;589171 55A79 1C1D 41G1G1 =5:149 @11B #9;1 @11B 99 3D;[email protected] CA16? [email protected] C5A21;1A B589771 ADB1;.CD; =535718 ;5AD791 41G1 21C17 ;?4D;C?A CA1B6?A=1C?A492D1C [email protected]@9B [email protected] @141 )- 9 1C1A1 [email protected]@51C ?71= 4925A9 9B?1B9 %+ B589771 97;1A1 1ADB @DB1A =5:149Gambar 6.14(a) Trafo dengan inti besi.(b) Trafo dengan inti besiberupa lempengan yangterpisahkan oleh laker. 142. ;539 571 31A1 [email protected] 99 ;5AD791 41G1 1;921C 1ADB @DB1A [email protected];DA179-941; B5=D1 1ADB @DB1A 25AB961C=5AD79;1 @141 [email protected] @5A11C1G17 =577D1;1 @[email protected] 94D;B9 55;CA?=175C9; 1ADB @DB1A G17C9=2D [email protected] =57DCD7;1 [email protected] @141 A5= =175C9; CD7;D 9BCA9;41 B5CA9;1 9BCA9;3. Transmisi Daya Listrik Jarak Jauh-A1B=9B9 41G1 9BCA9; :1A1; :1D8 [email protected];1 @A?B5B @5G1DA1 41G19BCA9;;[email protected]:D1C5AC5CDG17:1A1;G1:[email protected]@5=217;9C9BCA9; %9BCA9; G17 [email protected] 49 AD=18AD=18 @54D4D; 14118 81B9CA1B=9B9 41G1 9BCA9; :1A1; :1D841 4D1 31A1 =5CA1B=9B9;1 41G1 9BCA9; :1A1; :1D8 G19CD 4571 ;D1C 1ADB 9BCA9; 25B1A G17 4981B9;1 ?58 755A1C?A 143. 4571 C57171 G17 5298 C9779 41A9 C57171 G17 4981B9;1?58 755A1C?A)141D=D=G1CA1B=9B941G19BCA9;:1A1;:1D8=577D1;1C57171 C9779 $5DCD71 G17 [email protected]?58 4571 =577D1;1 CA1B=9B9C57171 C9779 14118 1ADB 9BCA9; G17 =5719A =51D9 ;1F1C A51C96;539 B589771 D;DA1 ;1F1C CA1B=9B9 G17 ;539 :D71 [email protected] =5=25A9;11771A1291G1:1D852985;??=9B4141G19BCA9;[email protected]:17;1F1C CA1B=9B9 :1D8 5298 ;539 B589771 [email protected]?58 569B95B9 41G1 9BCA9;G17 25B1A)[email protected]?B5BCA1B=9B941G19BCA9;:1A1;:1D8497D1;[email protected]@ G17 [email protected] 49 @DB1C @5=217;9C G17 =519;;1 [email protected];9C1A/$5=D49141G19BCA9;49CA1B=9B9;1;5 ;?C1;?C1 CD:D1 9 ;?C1;?C1 CD:D1 497D1;1 CA1B6?A=1C?A [email protected]?F G17 [email protected] 49 71A4D71A4D 9BCA9; B589771 C57171 9BCA9; [email protected];1 @141 C57171 B5;9C1A 144. /Gambar 6.15Bagan transmisi daya listrikjarak jauhtransmisi tegangan tinggigeneratortransformator transformator gardu listrik 145. 0146 Mudah dan Aktif Belajar Fisika untuk Kelas XIIrumahpabriktiang listrikpusatpembangkitlistrikContoh 6.9,[email protected]=5781B9;141G19BCA9; 146. 049CA1B=9B9;[email protected]=21C1 147. [email protected]=5:149;1?A:9;11 C57171G17497D1;1CA1B=9B9 ;/2 C571714919;;[email protected]@=5:149;/19;5C18D9 148. 0+ 149. 1 )5AB5C1B541G19BCA9;G178917:9;1497D1;1C57171CA1B=9B9 ;/[email protected];DCCA1B=9B9/ Kata Kunci generator Alternating Current komutator transformator/trafo transformator step-up transformator step-down efisiensi transformator arus pusar (arus eddy)Sumber: Jendela IPTEK, 1995 150. Induksi Elektromagnetik 1471G1G178917=5:149;1?A8917141188917 151. 0)5AB5C1B5 89170 152. 02 1G1G178917:9;1C57171CA1B=9B94919;;1=51D9CA16?=5:149;/14118 153. 0CA1B=9B9/ 1G1G178917=5:149;1?A141188917 154. 2008917 ;0#[email protected] 8917 155. 0 ,[email protected]@=5=99;9 [email protected];[email protected]@A9=5AG141 [email protected];[email protected];[email protected]@A9=5A4925A91ADB2?1;219;25AC57171 156. /1 [email protected];[email protected];D45A2 #9;11ADB411=;[email protected];D45A 157. [email protected]=5719A411=;[email protected]@A9=5A3 [email protected] 41G1 =1BD;1 41 41G1 ;5D1A1CA1B6?A=1C?A 158. ,52D18 CA1B6?A=1C?A 498D2D7;1 4571 BD=25AC57171)%' 159. /41;D1C1ADBG1 -5AG1C1C57171;5D1A1G1B525B1A 160. /41;D1C1ADBG1 !9CD71 569B95B9CA1B6?A=1C?A2 @5A214971:[email protected]=5A41B5;D45A,52D18 CA1B6?A=1C?A G17 [email protected] @141 A149?=5=99;9 [email protected];1B9 161. / C5A=91 @A9=5AG1498D2D7;14571BD=25A)%' 162. /#9;1:D=1899C1B5;D45ACA1B6?A=1C?AC5AB52DC99C1411ADBG17=5719A411=A149? C5CD;11 :[email protected]=5A2 ;[email protected];[email protected]@A9=5A3 [email protected]=5A4141G1B5;D45A:9;1569B95B9CA1B6?A=1C?A Tes Kompetensi Subbab B-'*($!()0'0(/%$*C. Arus dan Tegangan Listrik Bolak-balikADB 41 C57171 9BCA9; 2?1;219; =5=99;9 919 G17 B51D25AD218D218 [email protected] F1;CD B531A1 @5A9?49; 219; 25B1A [email protected] 5B1A1 1ADB 41 C57171 2?1;219; 491=217;1 4571 5F1B1 99 [email protected] B5=D1 @5A11C1 AD=18 C1771 [email protected];14571 55A79 9BCA9; 1ADB 2?1;219; ,[email protected] 41 ;5C18D9 @5A25411=541B1A 1C1A1 1ADB 2?1;219; 41 1ADB B51A18 14118 @?1A9C1BG1.CD; =575C18D9 @?1A9C1B 1ADB B51A18 G17 B51D [email protected] 41 1ADB2?1;219; G17 B51D 25AD218 [email protected] 497D1;1 ?B9?B;[email protected] -) 2,#),)* 51D9 11C 99 [email protected] :D71 491=1C9 919 6A5;D5B9 [email protected]@[email protected]=25CD;7A169;[email protected];=57D;DA 919 C57171 565;C96 41 ;D1C 1ADB 9BCA9; 565;C96 [email protected];1 E?C=5C5A41 [email protected]=5C5A 1. Sumber Tegangan Bolak-Balik (AC)5CD; C57171 1ADBG17 C5A2131 @141 =?9C?A ?B9?B;[email protected] B531A1 @5A9?49; =5DADC 6D7B9 B9DB ,118 B1CD BD=25A G19CD 755A1C?A 1ADB11= 755A1C?A 141 ;[email protected] G17 [email protected]@DC1A 2521B 411= =541 =175C 8?=?75 163. V Vm V = Vm sintT 2TI Im I = Im sintT 2TGambar 6.1812Pengukuran arus listrik denganmenggunakan volmeter.)5A81C9;1 )-(B91B9 71G1 75A1; 9BCA9; 41 1ADB 2?1;219; 4981B9;1 41A9 B52D18 ;[email protected] G17 [email protected] 4571 1:D [email protected])14171=21A7A169;[email protected];[email protected]?=217=5D:D;;1;54D4D;1 ;[email protected] [email protected] 25B1A BD4DC G17 [email protected] 77 G17 4981B9;1 41A9 B52D18 755A1C?A G17 [email protected]=5=5D89 @5AB1=11 25A9;DC1C1DDCD; - J1 2J -148 Mudah dan Aktif Belajar Fisika untuk Kelas XII-;1A513?B =1;1 3?B J- 1C1D3?BJ --J 164. #9;1 ;9C1 CDAD;1 -.)*3 [email protected] B9- J 165. C1D [email protected] :D71 49CD9B;1 4571=1;B B9- J 166. 1$1A51 77 94D;B9 B1=1 4571 2541 C57171 49 1C1A1 4D1 ;DCD2 7794D;B9 =1;1 [email protected] 49CD9B=1;BB9- J 167. 2$5C5A171'%, 71G1 75A1; 9BCA9; =1;B9=D= E?C E?C'%,C57171 =1;B9=D= E?C6D;B =175C9; 02:D=18 99C1 ;[email protected] 29417 ;[email protected] = 168. 25B1AG1 94D;B9 =175C9; -6A5;D5B9 BD4DC @DC1A1 ;[email protected] A14B -#9;1 755A1C?A C5AB52DC 498D2D7;1 4571 A17;191 [email protected];1 =5719A 1ADB2. Alat Ukur Tegangan dan Arus Bolak-Balik.CD; =575C18D9 141G1 C57171 9BCA9; @141 BD1CD A17;191B118B1CDG1497D1;1B52D1811CG1749B52DC-,-*()- ;1 C5[email protected] [email protected] C941; [email protected] =575C18D9 25B1AG1 C57171 [email protected];[email protected];=57D;DA919C5717141 ;D1C 1ADB497D1;1 E?C=5C5A41 [email protected]=5C5A'[email protected];DA99=5D:D;;181A71565;C9641A9C5717141 ;D1C 1ADB 51D9 )- 41 [email protected] =5=181=9 [email protected];DA1 1ADB 9BCA9; 411= B52D18 A17;191Gambar 6.16Grafik tegangan dan arus listrikbolak-balik terhadap waktu.bagian atas yangberlogambagian tengahyang transparanlampulogamGambar 6.17Cara pengukuran dengan testpen 169. resistorvoltmeterGambar 6.19Pengukuran tegangan padasebuah rangkaianInduksi Elektromagnetik 149Contoh [email protected]=1C1=51D9?B9?B;[email protected]=2DE5AC9;[email protected] /3=Gambar 6.20kWh meter yang ada di rumahdigunakan untuk mengukurdaya listrik yang terpakai.)141 )- C5A=91 ;DCD2 @?B9C96 498D2D7;1 45711ADB=1;B9=D= @[email protected]=5C5AC5A21319191ADB B5417;1)- [email protected]?B9C96498D2D7;145711ADB=1;B9=1 C5AG1C1C5A21319191ADB 170. )57D;DA199=5D:D;;1218F117;1 G17 C5A2131 @141 11C D;DA 14118 919 565;C96G1 5=9;[email protected] 411= =57D;DA C57171 B52D18 A17;191 [email protected] )-$5C9;1 1ADB =5719A :1AD= @5D:D; E?C=5C5A =D19 25AD218 '919G17C5A2131=5D:D;;181A71565;C96C57171A17;1919BCA9;[email protected] :D71 =57D;DA ;D1C 1ADB C57171 41 81=21C1 9BCA9; 219;[email protected] 1ADB4571 =577D1;1 [email protected]=5C5A /?C=5C5A 41 (8==5C5A 41 ?B9?B;[email protected];1B517F1;CD=5D:D;;1=B3=,;[email protected];?C1;=5=99;9D;DA13=K3=-5CD;11 C57171=1;B9=D=2 6A5;D5B9BD=25A19;5C18D9** /3=1 )[email protected];**141183=;1A51B;11E5AC9;1 /3==1;1**3=K /3=E?C#149C57171=1;B9=D=G114118'%, 171. ** 172. //2 )5A9?45411=7A169;3=,;118?A9H?C1=B3==1;13=K=B3= 173. =B 174. B#1496A5;D5B9BD=25A 175. 3. Nilai Efektif Tegangan dan Kuat Arus AC1C D;DA G17 497D1;1 DCD; =575C18D9 :D=18 41G1 [email protected];19 @141 ;52DCD81 55A79 9BCA9; 49 AD=18 14118 ;08 =5C5A5A5C1 17;1 =5D:D;;1 25B1A 55A79 9BCA9; G17 [email protected];19)5A81C9;1 )- [email protected]; :51B 17;1 G17 =5D:D;;125B1A 55A79 9BCA9; G17 [email protected];19 411= B1CD1 ;08 %#) -- )[email protected]?5841A991941 !1A71565;C961ADB1C1DC571712?1;219; 14118 ;D1C 1ADB 1C1D C57171 2?1;219; G17 [email protected]=5781B9;1:D=18;1?AG17 B1=1 ;5C9;1 =51D9 BD1CD @5781C1A 411= F1;CD G17 B1=1RA B IImIeft,[email protected]@5AC9)- =5=99;981=21C1411=F1;CD 176. -5B1A55A79;1?AG174981B9;1?581ADB565;C96G114118Gambar 6.21(a) Sebuah rangkaian denganhambatan R;1 2(b) Grafik hubungan I dengan t.12tsin m t 177. !H 178. Contoh 6.11150 Mudah dan Aktif Belajar Fisika untuk Kelas XII 179. - J 5A79;1?AG174981B9;1411=A17;1911ADB=5=99;9919G17 B51D 25AD218 B531A1 @5A9?49; 411= F1;CD 180. 41 [email protected]=11 181. - - J -.)* 3 41-.)* 3 =5=99;9919G17B1=1B589771 [email protected] [email protected]?58 25B1A 1ADB 565;C96G1 182. 56 183. - 184. - 185. - 186. 56 187. - 188. =1;B 189. - J 190. 4571 =577D1;1 31A1=1C5=1C9;1 [email protected]?58 1ADB 565;C96B52171925A9;DC =1;B 191. J57131A1G17B1=1C57171565;C96 1;[email protected][email protected]=11=1;B 192. J ,52D18A17;191G17498D2D7;14571BD=25A9BCA9;2?1;219;49D;DA4571E?C=5C5A41=5D:D;;117;1 193. [email protected];1881A71=1;B9=D=C571712?1;219;BD=25A41CD9B;[email protected]=11G1:9;16A5;D5B9G1 !H19;5C18D9 194. / !H1 '919C57171=1;B9=D==1;B4989CD74571=577D1;1-.)* 3 [email protected]?58=1;B 195. /2 )[email protected]?584571=577D1;1-.)* 3G19CD =1;BB9 - 196. B9 197. -Tantanganuntuk AndaApakah yang menyebabkansengatan listrik, arus listrik, atautegangan listrik? 198. IImaksIrGambar 6.22Grafik hubungan I dan tImaks = kuat arus maksimumIr = kuat arus rata-rata.tInduksi Elektromagnetik 151Contoh 6.12+74F3:[email protected]=3;[email protected]=43;=?7?;;=;:[email protected]@D74393;[email protected];H3=EFJ3;EF 199. D;@ .!;[email protected]:3 [email protected]@?3=D;?F?%#*4 [email protected]@[email protected][email protected]=((5 [email protected]@787=E;8 6 [email protected];[email protected] B7C;A678 [email protected]; 9 [email protected]@D7E73:+ [email protected]#7#[email protected]@[email protected][email protected][email protected]@[email protected]@96;=7E3:F;E7C:363B'34#/##0 200. 9?3=36;B7CA7:D;@+ 201. D;@ +%63C;[email protected];B7CA7: 202. [email protected] C36D3 203. .%4 204. . 205. .((%5 206. %.. 207. 6C36D7 208. D 209. 8 210. !K9 211. D;@ + 212. D;@ .12t4. Harga Kuat Arus dan Tegangan Rata-Rata!3C93 =F3E 3CFD 4A3=43;= C3E3C3E3 3633: =F3E 3CFD 4A3=43;[email protected] @;3;@J3 D7E3C3 [email protected]@ =F3E 3CFD D73C3: [email protected]= ?7?;@63:[email protected][email protected] ;DEC;= [email protected] D3?3 633? H3=EF [email protected] D3?3 )7C:3E;[email protected] 9C38;=D;@FDA;63 63C; 3CFDD73?3 213. [email protected] #/$#3 214. [email protected]= 3CFD D73C3: D7E73: 215. D7[email protected]: B7C;A67 [email protected] [email protected];3F;@J3 [email protected]:; [email protected]) 216. N [email protected] F?3: [email protected] [email protected] 6;3F; 3CFD 4A3=43;= 633? [email protected]=3;[email protected]: 217. %#* D;@++ N 218. Tugas AndaArus listrik bolak-balik dapatdiamati menggunakan osiloskop.Bersama kelompok belajar Anda,gunakan osiloskop yang ada dilaboratorium sekolah Anda untukmempelajari penggunaanosiloskop tersebut. Catatlah hal-halyang Anda anggap penting.Mintalah bimbingan guru FisikaAnda untuk melakukan tugas ini.3C; '34#/##0 219. 9 [email protected] '34#/##0 220. 9 221. [email protected] 6;B7CA7: [email protected] 3CFD C3E3C3E3 D74393; 47C;=FEContoh 6.13 222. %#* ImVmtRa b152 Mudah dan Aktif Belajar Fisika untuk Kelas XII) 223. %#* D;@++ [email protected]@ [email protected]@[email protected] 53C3 ?3E7?3E;=3 6;B7CA7:) 224. %#* N [email protected]@ [email protected]@ [email protected] D3?3 [email protected] 6;B7CA7: [email protected] [email protected]@C3E3C3E3 [email protected]= 3CFDD747D3C) 225. %#* N [email protected]@)[email protected]@ C3E3C3E3 .%#*[email protected]@ ?3=D;?F? .)[email protected]@[email protected]=43;[email protected]=3;[email protected];DEC;[email protected]:;[email protected] D;@.,[email protected][email protected]@[email protected]@96;:3D;[email protected]?47CE7CD74FE#7#$;=7E3:F; D;@.%#* [email protected]@[email protected]@[email protected]'34#/##0 226. 96;B7CA7:) 227. . 228. .5. Diagram [email protected]= ?7?B7C?F63: [email protected]@3;D;D 3C3: [email protected]@ [email protected] =F3E 3CFD6;[email protected][email protected]?7EA676;39C3?83DAC3DAC(!*-#+')3633:[email protected]@96;F=;[email protected];[email protected]@J3E7C:363BDF?4F:AC;[email protected] [email protected]@ DF6FE [email protected] + 3DAC DF3EFG7=EAC47CBFE3C [email protected]@ 3C3: 3CF? 3? [email protected]@ [email protected] DF6FEE7E3B6;[email protected] A7: D74F3: [email protected]= [email protected]: [email protected]= [email protected][email protected] [email protected]@ [email protected]=F3E 3CFD 63C; DF3EF [email protected]=3;[email protected] ;DEC;= )363 #/$#3 229. 63B3E @63B7C:3E;[email protected] 6;39C3? 83DAC 63C; [email protected]@ [email protected] 3CFD 4A3=43;=+F?4F :AC;[email protected] B363 #/$#3 230. 3633: [email protected]= [email protected]@[email protected]@J3 DF6FE 83D7 [email protected] 6;F=FC 633? [email protected] 67C33E 3E3F C36;[email protected]@[email protected] DF?4F G7CE;=3 [email protected]= [email protected]@[email protected] @;3; [email protected]@ [email protected] =F3E3CFD [email protected] [email protected] [email protected] D=33C [email protected] G7=EAC 73F; ?7EA676;39C3? 83DAC ;@; 6;:[email protected] @63 63B3E ?7?3:3?; 3C3: 83D7 [email protected]@ ?F63:6. Resistor pada Rangkaian Arus Bolak-Balik)363#/$#3 231. D74F3:C7D;[email protected];6;[email protected][email protected]=3;[email protected]=43;= C38;[email protected]@[email protected];83ED;@FDA;[email protected] [email protected]:3D;[email protected] 3CFD [email protected] F93 47CD;83E D;@FDA;63Gambar 6.23Grafik fasor I dan VGambar 6.24Rangkaian arus AC denganhambatan murni R.IV = Vmsint 232. rotasi VmimV = Vm sinti = im sint2 2 332Gambar 6.25Grafik kuat arus I dan tegangan Vpada rangkaian hambatan murni,arus I, dan tegangan V sefase.LI = Im V sint mim22V = Vm sin ( t )Induksi Elektromagnetik 153)[email protected] [email protected]@ 4A3=43;= [email protected] [email protected]@9 C7D;DEAC [email protected]; 3633:%D;@+ N [email protected]@?7?7C:3E;[email protected]/*/ [email protected][email protected][email protected]:[email protected][email protected];C ?7?;;=;:[email protected]@[email protected]@% % ?3=347D3C3CFD 4A3=43;= [email protected] [email protected];C ?73F; [email protected]=3;[email protected] [email protected]:; [email protected]%D;@+ N)7C:3E;[email protected] #/$#3 233. [email protected] '34#/##0 234. [email protected]'34#/##0 235. 93CFD ?3=D;?F? [email protected] [email protected]@ ?3=D;?F? ?7?;;=;[email protected]?3CE;@J3=7E;=3BAD;D;[email protected][email protected];[email protected]@[email protected]@9?73F;[email protected]=3;[email protected][email protected];@;3;?;@;?F?%74;:[email protected] @63 B7C:3E;[email protected] #/$#3 236. ;39C3? 83DAC 63C; =F3E [email protected] [email protected]@@J3 ?7?;;=; 3C3: [email protected] D3?3 tImaks VmaksGambar 6.26Diagram fasor arus I dantegangan V memiliki arahyang sama.Gambar 6.27Rangkaian arus bolak-balikdipasang seri dengan sebuahinduktor murni.52tMari Mencari Tahu*7D;[email protected]:[email protected]@;DEC;[email protected];@96;[email protected][email protected]+7E;3BC7D;[email protected];F36;[email protected]?7?;;=;@;3;C7D;[email protected];[email protected],[email protected]:[email protected]@3;[email protected];[email protected];8;=3D;@;3;D74F3:C7D;DEAC+7E73:?7?4F3EC7DF?7;@;6;:[email protected]@[email protected]@3;C7D;[email protected][email protected]@[email protected]@;3;C7D;[email protected];@J363C;5;C;5;C;[email protected];?;;=;C7D;DEACE7CD74FE93C74;:[email protected];[email protected]?43C?353??353?C7D;DEAC633?EF;[email protected]@63a bI = Im sint7. Induktor Murni pada Rangkaian Arus Bolak-Balik)7C:3E;[email protected] #/$#3 237. +74F3: ;@6F=EAC [email protected]; ?7?;;=; ;@[email protected];6;C;)363D33E3CFD;DEC;[email protected];[email protected]=3;[email protected][email protected];?4F93J3 97C3= ;DEC;= ;@6F=D; 99 6; [email protected] [email protected] ;@6F=EAC [email protected] [email protected]: [email protected] 4763 [email protected]@ [email protected] [email protected]@9 [email protected] D74393; [email protected];H3=EF 3633:%D;@+ N 238. #;=3 @63 B7C:3E;[email protected] [email protected]=3;[email protected] 3CFD 4A3=43;= 633? #/$#3 239. [email protected]=3;[email protected] E7CD74FE [email protected] [email protected]=3;[email protected] E7CEFEFB [email protected] 47C3=F !F=F? $;C5:A88 !F=F?$;C5:A88 [email protected][email protected] 43:H3 (7: [email protected] 633? [email protected]=3;[email protected] E7CD74FE C7D;DEAC [email protected]; E;63= 363 J3;[email protected];3; ?3=3 6;B7CA7: [email protected] =F3E 3CFD D74393; 47C;=FE 240. *,%) 241. ,#+') %D;@+N + + % D;@+Gambar 6.28Grafik kuat arus I dan tegangan Vpada rangkaian induktif murni.Tegangan V mendahului arus Isekitar 90.t 242. [email protected]!F=F?(:[email protected]@;3;:3?43E;@6F=EAC154 Mudah dan Aktif Belajar Fisika untuk Kelas XII % D;@ + +% N 5AD + % D;@+ 243. D;@ N 244. %+N [email protected]@ ?7?7C:3E;[email protected] [email protected]@[email protected] '34#/##0 245. 9 6;=7E3:F; 43:H3%% [email protected] 6;D74FE [email protected]; ;@6F=E;8D7:;@993 63B3E 6;EF;D3E3F 246. [email protected]@[email protected]; ;@6F=E;[email protected] DF6FE C36D;@[email protected]; 6;C; ! [email protected]; [email protected]@ [email protected]?3E; :[email protected]@ '34#/##0 247. [email protected] '34#/##0 248. 9 6;=7E3:F; [email protected] 83D7 [email protected] [email protected]@ [email protected] =F3E 3CFD [email protected]?73F; [email protected]=3;[email protected] ;@6F=E;8 E7CD74FE D747D3C 249. [email protected]@ DF6FE 83D7 3CFDE7CE;@993 3633: 250. C3663C; [email protected]@@63 [email protected] 74;: ?7?3:3?; ;=3 ?7?7C:3E;[email protected] 9C38;= [email protected]@D;@FDA;63 [email protected] 9C38;= 3CFD D;@FDA;63 E7C:363B H3=EF ?73F; #/$#3 251. #;=3 [email protected]@ B363 [email protected]@9 [email protected]=3;[email protected] ?3=D;?F? @;3; [email protected]=3;[email protected][email protected]?;@;?F? +743;[email protected];[email protected]@[email protected];3;?;@;?F? 3CFD [email protected] ?73F; [email protected]=3;[email protected] [email protected] ?3=D;?F? %#*Gambar 6.29Diagram fasor arus I dantegangan V. Teganganmendahului 90.VL90 I)363D74F3:[email protected]=3;[email protected]=43;[email protected]@[email protected];!K6;[email protected];@6F=EACD747D3C 252. !*[email protected]=3;[email protected];@;[email protected]:3D;[email protected]?3=D;?F? 253. !;[email protected]@[email protected]?3=D;?F?;@6F=EACE7CD74FE#7#$;=7E3:F;[email protected]; Contoh 6.143CFD?3=D;?F?% 254. ;@[email protected];;@6F=EAC 255. !,[email protected]@?3=D;?F?63B3E6;:;[email protected]@[email protected][email protected]% % 256. % 257. !K 258. ! 259. . 260. Ca bV = VmsintGambar 6.30Rangkaian kapasitorViV = Vm sin t2 i = im sintGambar 6.31Grafik I dan V pada kapasitordalam rangkaian AC.90VIInduksi Elektromagnetik 1558. Kapasitor pada Rangkaian Arus Bolak-Balik)C;@D;B [email protected]@@J3 D3?3 [email protected]@ ;@6F=EAC $3B3D;EAC [email protected]=3;[email protected]=43;=6;[email protected]@EF=?7?B7CA7:[email protected];;DEC;[email protected];: 47D3C CFD ;DEC;= [email protected] ?73F; =3B3D;EAC [email protected] =3B3D;[email protected] D747D3C D73?3 [email protected] [email protected][email protected] =3B3D;EAC 47C;D; [email protected] D747D3C+ [email protected] [email protected] [email protected] E7CD;[email protected] 633? =3B3D;EAC #/$#3 261. 3633:N6; [email protected]%D;@+ N3C;=76F3'34#/##0 262. 9 [email protected]'34#/##0 263. 9 63B3E6;B7CA7: ++ D;@ +% + D;@+%5AD+ %5AD+ %5AD+%D;@ 264. + [email protected]@ ?7?7C:3E;[email protected] [email protected]@[email protected] '34#/##0 265. 96;=7E3:F; 43:H3%% [email protected] !F=F? (:[email protected] @;3; :[email protected]=3B3D;EAC [email protected] 6;D74FE [email protected]; =3B3D;E;8D7:;@993 63B3E 6;EF;D 266. N [email protected]@[email protected]; =3B3D;E;8 =3B3D;E3D =3B3D;[email protected]; DF6FE [email protected]@ [email protected]?3E; :[email protected]@ '34#/##0 267. 9 [email protected] '34#/##0 268. 96;=7E3:F; [email protected] 83D7 [email protected] [email protected]@ [email protected] =F3E 3CFD [email protected]?73F; [email protected]=3;[email protected] =3B3D;E;8 E7CD74FE D747D3C 269. [email protected]@ DF6FE 83D7 [email protected]:FF; 3633: 270. C36 63C; DF6FE 83D7 [email protected]@@63 [email protected] 74;: ?7?3:3?; ;=3 ?7?7C:3E;[email protected] 9C38;= [email protected]@D;@FD;A63 [email protected] 9C38;= 3CFD D;@FD;A63 E7C:363B H3=EF ?73F; #/$#3 271. #;=3 [email protected]@ B363 [email protected]@9 [email protected]=3;[email protected] ?3=D;?F? @;3; 3CFD633? [email protected]=3;[email protected] [email protected] ?3=D;?F? % +743;[email protected] ;=3 [email protected]@[email protected];3; ?3=D;?F? 3CFD [email protected] ?73F; [email protected]=3;[email protected] [email protected] ?;@;?F?Gambar 6.32Diagram fasor I dan V padakapasitor. 272. Tantanganuntuk AndaSebuah kapasitor 100Fdihubungkan dengan sumbertegangan bolak-balik. Arus yangmengalir melalui rangkaianmemenuhi persamaanI = 4 sin 200t A. Tuliskanpersamaan tegangankapasitor itu.!#$'. 273. *[email protected]=3;[email protected]@B363*[email protected]=3;[email protected]=3;=1 #0)-#+#0 '#-5#04++(#5+74F3:=3B3D;[email protected]@ 274. 6;[email protected][email protected]@4A3=43;[email protected]@[email protected]; 156 Mudah dan Aktif Belajar Fisika untuk Kelas XII!K,[email protected]@?3=D;?F?%.D7B7CE;B36393?43C47C;=FEc200F!;[email protected]?3=D;?F?B363=3B3D;EACE7CD74FE#7#$;=7E3:F; 275. O N !K%. 276. C36DC36D 277. (7:[email protected];EF3CFD?3=D;[email protected]:% % 278. Contoh 6.15V = Vmsint'056- '34#/##0 6056-4+0*7D;DEACD783D7 %D;@+ 279. @6F=EAC $ E7CE;@993 %D;@ 280. +D747D3C 281. C36$3B3D;[email protected]:FF; %D;@ 282. +D747D3C 283. C36!#$'. 284. [email protected][email protected] [email protected] 3CFD [email protected] [email protected];C 633?E;3B [email protected]=3;[email protected] #;=3 DF?47C [email protected]@ 4A3=43;= 6;[email protected] D3?3 J3;EF%D;@[email protected]@[email protected]@[email protected];:63:[email protected] =7?F6;[email protected] [email protected] [email protected]@@J3 ;[email protected] 3CFD [email protected] [email protected];C633? E;3B [email protected]=3;[email protected] D3?3 % D;@+ ?3=3 [email protected] 6;63B3E [email protected]@[email protected] B3633 C7D;DEAC%D;@+4 ;@6F=EAC%D;@ 285. + 5 =3B3D;EAC%D;@ 286. + 287. R L CvI = Im sint Gambar 6.34Diagram fasor V, VR, VL, dan VC.Z XXLXLCRXCInduksi Elektromagnetik 1579. R, L, dan C Dipasang Seri dalam Rangkaian Arus Bolak-Balik*[email protected]=3;[email protected] 3CFD ;DEC;= 4A3=43;= [email protected] ?7?;;=; :[email protected] [email protected]; 6;[email protected] D7C; [email protected]@ ;@6F=EACD7CE3 =3B3D;[email protected] [email protected]:3D;[email protected]?43:[email protected] [email protected]; ;DEC;= [email protected] 74;: 47D3C E7E3B; [email protected]=3;[email protected] // D7C; ;@;:[email protected] 63B3E 6;[email protected][email protected] [email protected]= ?7?B7C47D3C 63J3 ;DEC;= [email protected] E7C43E3DCFD?3=D;[email protected]=3;[email protected]?7?;;=;@;3;[email protected]@9D3?3B363D7E;3B [email protected]@ %74;: 73D 63B3E @63 B7C:3E;[email protected] #/$#3 288. #;=3 @63 [email protected] [email protected] 3CFD 633? [email protected]=3;[email protected] D747D3C%D;@ + [email protected];[email protected]@[email protected]@?7?7C:3E;[email protected];39C3?83DAC B363 #/$#3 289. J3;EF? D;@+ ?7?;;=; 83D7 [email protected] D3?3 [email protected]@ 3CFD? D;@ 290. [email protected]:FF; 83D7D747D3C 291. C36? D;@ 292. + E7CE;@993 83D7D747D3C 293. C36)7C:3E;[email protected] [email protected]=3;[email protected] // D7C; B363 #/$#3 294. +7E;3B [email protected]@?7?;;=; [email protected]@ [email protected]+753C3 83DAC [email protected]@[email protected]@ ;@;63B3E 6;F?3:[email protected] D74393; 47C;=FEN (7: [email protected]@D3;@9 E793= FCFD :3C9363B3E 6;[email protected][email protected] [email protected]@ [email protected]@[email protected] :;[email protected] G7=EAC J3;EF 295. [email protected]@ ?7?7C:3E;[email protected] =7?43; #/$#3 296. :[email protected] EAE3 [email protected]=3;[email protected]; NN [email protected] 6;D74FE [email protected]@ ;[email protected]; [email protected]=3;[email protected] . 63B3E 6;:;[email protected]; '34#/##0 297. 9 298. N 299. 33E3F 300. N 301. 4(7:[email protected]?3=D;[email protected][email protected];C6;D7E;[email protected]@[email protected] :[email protected]@ [email protected] [email protected]@ ?3=D;?F? [email protected] 3CFD ?3=D;?F? ;@;[email protected]:;[email protected] 2J3;EF 302. N [email protected]@%[email protected]@ ?3=D;?F?;[email protected]; [email protected]=3;[email protected] [email protected];EAE3Gambar 6.33Resonansi rangkaianRLC seriGambar 6.35Diagram fasor Z, R, XL, dan XC.iL V C VL VVR VC V 303. 763 83D7 [email protected] [email protected]@ [email protected] =F3E 3CFD 63B3E 6;[email protected][email protected] D74393;VVL VabVR I)XL ZR)Contoh 6.16158 Mudah dan Aktif Belajar Fisika untuk Kelas XII NN NI = 40R = 30XLVLVRV = Vmsint47C;[email protected] ND7:;@993 [email protected] [email protected]@@J3 3633: D;@%+B34;3DF6FE 83D7 [email protected];3; BAD;E;8 CE;@J3 [email protected]@[email protected]:FF;[email protected]@9=3;[email protected];83E;@6F=E;8#;=3 DF6FE83D747C@;3; @793E;8 CE;@J3 [email protected]@ E7CE;@993 A7: 3CFD [email protected] [email protected]=3;[email protected];83E =3B3D;E;8 #;=36;B7CA7: [email protected];@[email protected]@?7?;;=;[email protected][email protected]@9=3;[email protected];83EC7D;DE;833?:3 ;@; 6;[email protected] E73: E7C36; [email protected]@D;10. R dan L Dipasang Seri dalam Rangkaian Arus Bolak-Balik)7C:3E;[email protected] #/$#3 304. +7E;3B [email protected]@ ?7?;;=; [email protected]@ [email protected]+753C3 83DAC [email protected]@[email protected]@ ;@; 63B3E 6;F?3:[email protected] D74393;[email protected]@[email protected]@[email protected]:;[email protected]@[email protected]@[email protected] J3;EF 305. [email protected] ;[email protected]; [email protected]=3;[email protected] *N% 6;B7CA7: D7B7CE; 47C;=FE 306. 3E3F 307. N763 83D7 [email protected] [email protected]@ [email protected] =F3E 3CFD 63B3E 6;[email protected][email protected] D74393;47C;[email protected])7C:3E;[email protected] #/$#3 308. E3?B3= 43:H3 [email protected]@ [email protected]:FF; 3CFDD747D3CC36D7:;@993;=3%D;@ + ?3=3%D;@ + a R L bI = ImsintGambar 6.36Rangkaian R dan L dipasang seriGambar 6.37Diagram fasor VL dan VRGambar 6.38Diagram fasor VL dan VRGambar 6.39Grafik tegangan mendahului arusdengan beda fase 0 90.VabtIab+74F3:C7D;DEAC 6;[email protected];[email protected]@;@6F=EAC [email protected]@4A3=43;=.3 !;[email protected];[email protected];[email protected]=3;[email protected]@9=3;[email protected][email protected] ,[email protected][email protected]@E7C:363B=F3E3CFD#7#$;=7E3:F;C7D;[email protected];[email protected];;@[email protected]@DF?47C.V/i 309. R Ca bVI = ImsintInduksi Elektromagnetik 1593 [email protected];6;:;[email protected]?73F;'34#/##0 310. 9 311. 2 312. [email protected]@ 6;:;[email protected]@[email protected]'34#/##0 313. [email protected] M$F3E3CFD . 314. ,[email protected]@ 315. .,[email protected]@;@6F=EAC. 316. .4 [email protected]@[email protected]:FF;D747D3C 317. [email protected]:FF;[email protected]=3;[email protected];6;[email protected];[email protected];[email protected]:;@6F=EAC [email protected]@4A3=43;[email protected]@[email protected] 318. D;@+.,F;[email protected][email protected][email protected]=3;[email protected]#7#$;=7E3:F;A:? 319. D;@+.?3=3% 320. . ! 321. [email protected] MC36#36;[email protected][email protected]:%D;@+ 322. D;@+NContoh 6.1711. R dan C Dipasang Seri dalam Rangkaian Arus Bolak-Balik)7C:3E;[email protected] #/$#3 323. *7D;[email protected] =3B3D;EAC6;[email protected] D7C;633? [email protected]=3;[email protected] 3CFD 4A3=43;= ; [email protected] E;E;[email protected]@[email protected]@[email protected][email protected]@F?3:[email protected]@C7D;[email protected]@[email protected]=3B3D;[email protected]@EAE3E7CD74FE3633: 324. [email protected] ;[email protected]; [email protected]=3;[email protected] N 63B3E 6;:;[email protected] D7B7CE; 47C;=FE 325. N3E3F 326. N Gambar 6.40Rangkaian seri R-C dalamrangkaian arus AC. 327. VRIabVab VRZGambar 6.42Diagram fasor vektorhambatan R terhadap Xc.CXCtGambar 6.43VabGrafik tegangan Vab terhadap arusi763 83D7 [email protected]@ [email protected] =F3E 3CFD 63B3E 6;[email protected][email protected] D74393; 47C;=FEContoh 6.1833? D74F3: [email protected]=3;[email protected] 6;[email protected] D7C; [email protected]@ 328. [email protected] 6;:[email protected][email protected][email protected]@4A3=43;[email protected][email protected];@J3V = Vmsint 329. !K C36D160 Mudah dan Aktif Belajar Fisika untuk Kelas XII !K!;[email protected]:;[email protected];[email protected]=3;[email protected]#7#$;=7E3:F; 330. O N!K 331. C36D 332. [email protected];[email protected]=3;[email protected];:;[email protected]@[email protected][email protected]@[email protected]'34#/##0 333. 9 334. J3;EF 335. [email protected] 336. Gambar 6.41Diagram fasor teganganVab terhadap Vc.*[email protected]=3;[email protected] D7C;[email protected]@ C7D;DEAC [email protected] [email protected]; =3B3D;E;86;:[email protected][email protected][email protected]@ 337. [email protected]@[email protected];!K!;[email protected]:3 ;[email protected];[email protected]=3;[email protected] [email protected][email protected];C5 =3B3D;E3D=3B3D;EAC6 [email protected]@[email protected]@[email protected]:[email protected]@=3B3D;EAC7 [email protected]=3;[email protected] [email protected];[email protected]@[email protected]%D;@+#7#$;=7E3:F; 338. . !KR = 80 V = VmsintIContoh 6.19C60FV/i)363#/$#3 339. E3?B3=43:[email protected]@E7C3?43ED747D3C C3663C;3CFD+753C3?3E7?3E;D63B3E6;D;[email protected];=3%D;@+%D;@+ N 340. aL CVLVVCIInduksi Elektromagnetik 1613 [email protected];[email protected]=3;[email protected];:;[email protected]@[email protected][email protected]@[email protected]'34#/##0 341. 9 342. 4 [email protected]?73F;[email protected]=3;[email protected] 3633: 343. . 344. 5 $3B3D;E3D=3B3D;EAC 345. 6 ,[email protected]@:[email protected]@[email protected]@=3B3D;EAC 346. . 347. .7 [email protected]=3;[email protected]@ N M8 [email protected][email protected]@[email protected]%D;@+?3=3 %D;@+ 348. D;@+ 349. D;@ +N M12. L dan C Dipasang Seri dalam Rangkaian Arus Bolak-Balik;=7E3:F; D74F3: [email protected]=3;[email protected] 3CFD 4A3=43;= 6;[email protected] D74F3:;@[email protected] D74F3: =3B3D;EAC [email protected] 47C=3B3D;E3D$7?F6;[email protected][email protected] 6;:[email protected][email protected] D753C3 D7C; D7B7CE; #/$#3 350. ?3=3 [email protected];[email protected]@[email protected]@;@[email protected]@[email protected]=3B3D;EAC D747D3CC36 [email protected]= ?7?B7C?F63: B7?3:[email protected] 4763 83D7 633? [email protected]@[email protected] 6;[email protected] [email protected] =F3E 3CFD [email protected] [email protected];C 633? [email protected]=3;[email protected]:%D;@+73F;#/$#3 351. E7C435343:[email protected]:FF;3CFDD747D3C 352. [email protected];@993E7C:363BD747D3C 353. C36D7:;@993D7E;3B [email protected]@ [email protected] ?7?;;=; [email protected] D74393; 47C;=FE%D;@ 354. + [email protected][email protected]%D;@ 355. +)7C:3E;[email protected]=7?43;6;39C3?83DACB363 #/$#3 356. +753C3 G7=EAC63B3E 6;F?3:[email protected] D74393; 47C;=FEN N #36;[email protected]@[email protected]=3;[email protected]@[email protected];D;:[email protected]@ Gambar 6.44Rangkaian seri L dan CbI = ImsintGambar 6.45Diagram fasor I, VL, dan VC 357. RZGambar 6.46frGrafik kurva impedansi Z dangrafik linear R.R/ZGambar 6.47Ketika frekuensi resonansiterjadi, harga arus [email protected]= :3C93 [email protected]@ ?3=D;?F? [email protected] 3633: %% N %D7:;@993 [email protected] 6;B7CA7: :3C93 :[email protected] EAE3 D747D3C%%N%%%N%D7:;@993162 Mudah dan Aktif Belajar Fisika untuk Kelas XIIN NC3:[email protected]@[email protected]@[email protected] D747D3C#;=3?3=3M [email protected] [email protected]=3;[email protected] 47CD;83E ;@6F=E;8#;=3?3=3N M [email protected] [email protected]=3;[email protected] 47CD;83E =3B3D;E;8#;=3?3=3 B363 =3DFD ;@; E7C36; B7C;DE;H3 [email protected]@D;13. Resonansi pada Rangkaian RLC*[email protected]@D;[email protected]=3;[email protected]; [email protected] E7C36;=7E;[email protected] ;@; [email protected][email protected] ;[email protected]; [email protected]=3;[email protected]?7?;;=; :3C93 ?;@;[email protected]@;3;[email protected]@:[email protected][email protected];[email protected][email protected]=3;[email protected] [email protected]; ?3=D;?F?3C;D D;@[email protected] [email protected] [email protected] 93C;D;@[email protected] E;E;= E7C36;@J3 [email protected]; [email protected]@D; ; E;E;= [email protected]@;3; ?;@;?F? )7C:3E;[email protected] #/$#3 358. 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