Bab 4 Perhitungan Plat

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BAB IV

PELAT LANTAIIV.1. PELAT LANTAI

Diketahui data-data sebagai berikut: fc = 30 MPa ; fy = 240 MPa Tebal pelat = 120 mm (selimut beton = 20 mm)

Digunakan tulangan 10 mm

dx = 120 20 0,5 x 10= 95 mm

dy = 120 20 10 0,5 x 10= 85 mm

IV.2.Idealisasi struktur

Gambar 4.1 Denah Struktur Pelat Lantai 2 & 3

Gambar 4.2 Denah Struktur Pelat AtapIV.3.Pembebanana) Pembebanan Lantai 2-41. Beban mati (qD)Tebal pelat = 120 mmBerat sendiri=288 kg/m2

Berat penutup lantai=16,8 kg/m2

Berat spesi 3 cm=63 kg/m2

Berat ducting=25 kg/m2

Berat plafon + penggantung=18 kg/m2

TOTAL=410,8 kg/m2

2. Beban hidup (qL)

qL = 250 kg/m2 ........................(Berdasarkan PPIUG 1983 Tabel 3.1 hal. 17)3.Beban ultimate (qu)qu = 1,2 qD + 1,6 qL

= 1,2 x 410,8 + 1,6x 250

= 892,96 kg/m2

= 8,93 kN/m2b) Pembebanan Lantai atap

1. Beban mati (qD)Tebal pelat = 100 mmBerat sendiri=240 kg/m2

Berat penutup lantai=16,8 kg/m2

Berat spesi 3 cm=63 kg/m2

Berat ducting=25 kg/m2

Berat plafon + penggantung=18 kg/m2

TOTAL=362,8 kg/m2

2. Beban hidup (qL)

qL = 100 kg/m2 ........................(Berdasarkan PPIUG 1983 Tabel 3.1 hal. 17)

3.Beban ultimate (qu)qu = 1,2 qD + 1,6 qL

= 1,2 x 362,8 + 1,6x 100

= 595,36 kg/m2

= 5,95 kN/m2IV.4.Perhitungan Tulangan Lantai 2 & 3a. Penulangan Pelat D (Skema III CUR IV) (ly/lx=1,0) Mlx = 0,001x 8,93x 62 x 30 = 6,698 kN.m

DMly = 0,001x 8,93x 62 x 30 = 6,698 kN.m

Mtx = -0,001x 8,93x 62 x 68 = -15,181 kN.m

Mty = -0,001x 8,93x 62 x 68 = -15,181 kN.mMtix = mlx = x 6,698 = 3,349 kN.m

Mtiy = mly = x 6,698 = 3,349 kN.m

Mu (kN.m)Mu/bd2As (mm2)tul. terpasang

Mlx6,698742,1050,0039370,5 10 200

Mly6,698926,9900,0049416,5 10 175

Mtx-15,181-1682,1050,0092874 10 75

Mty-15,181-2101,1760,0117994,5 10 75

Mtix3,349371,0530,0019180,5 10 250

Mtiy3,349463,4950,0024204 10 250

Mu/bdx2 = 6,698/ (1 x 0,0952) = 742,105 ( diperoleh 0,0039Asx = x b x dx = 0,0039 x 1000 x 95 = 370,5 mm2

As min = 0,25% x b x t = 0,25% x 1000 x 120 = 300 mm2 Asx > As minTulangan terpasang = 10 200 (Tabel CUR IV hal 15)b. Penulangan Pelat C (Skema VIIB CUR IV) (ly/lx=1,0) Mlx = 0,001x 8,93x 62 x 28 = 6,251 kN.m

CMly = 0,001x 8,93x 62 x 25 = 5,581 kN.m

Mtx = -0,001x 8,93x 62 x 60 = -13,395 kN.m

Mty = -0,001x 8,93x 62 x 54 = -12,056 kN.mMtiy = mlx = x 6,251 = 3,126 kN.m


Mlx6,251692,6320.0036342 10 225

Mly5,581772,4910.0041348,5 10 225

Mtx-13,3951484,2110.0081769,5 10 100

Mty-12,0561668,5810.0091773,5 10 - 100

Mtiy3,126346,3160.0018171 10 - 250

c. Penulangan Pelat E (Skema VIA CUR IV) (ly/lx=1,71) Mlx = 0,001x 8,93x 3,52 x 63,1 = 5,071 kN.m

EMly = 0,001x 8,93x 3,52 x 21,3 = 1,712 kN.m

Mtx = -0,001x 8,93x 3,52 x 108,45 = -8,716 kN.m

Mty = -0,001x 8,93x 3,52 x 77 = -6,188 kN.mMtix = mlx = x 5,071 = 2,536 kN.m

Mtiy = mly = x 1,712 = 0,856 kN.m


Mlx5,071561,9220,0029275,5 10 250

Mly1,712236,9390,0012102 10 250

Mtx-8,716-965,7760,0052494 10 150

Mty-6,188-856,5380,0045382,5 10 200

Mtix2,536280,9610,0014133 10 250

Mtiy0,856118,4690.000651 10 250

d. Penulangan Pelat F (Skema VIIB CUR IV) (ly/lx=1,2)Mlx = 0,001x 8,93x 32 x 28= 1,563 kN.m

Mly = 0,001x 8,93x 32 x 25= 1,395 kN.m

FMtx = -0,001x 8,93x 32 x 60= -3,349 kN.m

Mty = -0,001x 8,93x 32 x 54= -3,014 kN.mMtiy = mlx = x 1,563 = 0,7815 kN.m


Mlx1,563173.1580.000876 10 250

Mly1,395193.1230.000976.5 10 250

Mtx-3,349371.0530.0019180.5 10 250

Mty-3,014417.1450.0023195.5 10 250

Mtiy0,781586,5790.000547.5 10 250

e. Penulangan Pelat Tipe A (Skema VIA CUR IV) (ly/lx=1,2) Mlx = 0,001x 8,93x 32 x 25 = 1,395 kN.m

Mly = 0,001x 8,93x 32 x 28 = 1,563 kN.m

AMtx = -0,001x 8,93x 32 x 54 = -3, 014 kN.m

Mty = -0,001x 8,93x 32 x 60 = -3, 349 kN.mMtiy = mlx = x 1,395= 0,698 kN.m


Mlx1,395193,1230.000985.5 10 250

Mly1,563173,1580.000868 10 250

Mtx-3,014-417,1450.0023218.5 10 250

Mty-3,349-371,0530.0019161.5 10 250

Mtiy0,69877,3030.000438 10 250

f. Penulangan Pelat B (Skema VIIB CUR IV) (ly/lx=2,4)Mlx = 0,001x 8,93x 32 x 58= 3,237 kN.m

BMly = 0,001x 8,93x 32 x 17= 0,949 kN.m

Mtx = -0,001x 8,93x 32 x 83= -4,632 kN.m

Mty = -0,001x 8,93x 32 x 53= -2,958 kN.m

Mtiy = mlx = x 3,237= 1,619 kN.m


Mlx3,237358.6840,0021199.5 10 250

Mly0,949131.3240,000759.5 10 250

Mtx-4,632513.2890,0029275.5 10 250

Mty-2,958409.4200,0024204 10 250

Mtiy1,619179.3420,0011104.5 10 250

IV.5.Perhitungan Tulangan Lantai atap

a. Penulangan Pelat A (Skema III CUR IV) (ly/lx=1,0) Mlx = 0,001x 5,95x 62 x 30 = 4,463 kN.m

AMly = 0,001x 5,95x 62 x 30 = 4,463 kN.m

Mtx = -0,001x 5,95x 62 x 68 = -10,115 kN.m

Mty = -0,001x 5,95x 62 x 68 = -10,115 kN.mMtix = mlx = x 4,463 = 2,231 kN.m

Mtiy = mly = x 4,463 = 2,231 kN.m


Mlx4,463494,4600,0025237,5 10 250

Mly4,463617,6470,0032272 10 250

Mtx-10,115-1120,7760,0060570 10 125

Mty-10,115-14000,0076646 10 100

Mtix2,231247,2300,0012114 10 250

Mtiy2,231308,8240,0016136 10 250

Mu/bdx2 = 4,463/ (1 x 0,0952) = 464,460 ( diperoleh 0,0025Asx = x b x dx = 0,0025 x 1000 x 95 = 237,5 mm2

As min = 0,25% x b x t = 0,25% x 1000 x 120 = 300 mm2 Asx > As minTulangan terpasang = 10 250 (Tabel CUR IV hal 15)

b. Penulangan Pelat B (Skema VIIB CUR IV) (ly/lx=1,0) Mlx = 0,001x 5,95x 62 x 28 = 4,165 kN.m

Mly = 0,001x 5,95x 62 x 25 = 3,719 kN.m

BMtx = -0,001x 5,95x 62 x 60 = -8,925 kN.m

Mty = -0,001x 5,95x 62 x 54 = -8,033 kN.mMtiy = mlx = x 4,165 = 2,083 kN.m


Mlx4,165461,4960.0024228 10 250

Mly3,719514,7060.0026221 10 250

Mtx-8,925988,9200.0053503,5 10 150

Mty-8,0331111,7650.0059501,5 10 - 150

Mtiy2,083230,7480.0012114 10 - 250

c. Penulangan Pelat C (Skema VIA CUR IV) (ly/lx=1,71) Mlx = 0,001x 5,95x 3,52 x 63,1 = 3,379 kN.m

Mly = 0,001x 5,95x 3,52 x 21,3 = 1,141 kN.m

CMtx = -0,001x 5,95x 3,52 x 108,45 = -5,807 kN.m

Mty = -0,001x 5,95x 3,52 x 77 = -4,123 kN.mMtix = mlx = x 3,379 = 1,690 kN.m

Mtiy = mly = x 1,141 = 0,570 kN.m


Mlx3,379374,4050,0019180,5 10 250

Mly1,141157,8710,000759,5 10 250

Mtx-5,807-643,4900,0034323 10 225

Mty-4,123-570,7060,0030255 10 250

Mtix1,690187,2020,000985,5 10 250

Mtiy0,57078,9350.0025212,5 10 250

d. Penulangan Pelat D (Skema II CUR IV) (ly/lx=1,0)Mlx = 0,001x 5,95x 62 x 25= 3,719 kN.m

DMly = 0,001x 5,95x 62 x 25= 3,719 kN.m

Mtx = -0,001x 5,95x 62 x 51= -7,586 kN.m

Mty = -0,001x 5,95x 62 x 51= -7,586 kN.m

Besar Mtix dan Mtiy tidak diperhitungkan karena momen tak terduga sebesar 0.5 Mlx memiliki besar yang sangat kecil sehingga disamakan dengan momen tumpuan.


Mlx3,719412,0500,0021199,5 10 250

Mly3,719514,7060,0027229,5 10 250

Mtx-7,586-840,5820,0045427,5 10 175

Mty-7,586-10500,0056476 10 - 150

e. Penulangan Pelat Penutup (Skema I CUR IV) (ly/lx=2,5) Mlx = 0,001x 5,95x 2.52 x 110 = 2,618 kN.m

Mly = 0,001x 5,95x 2.52 x 24 = 0,571 kN.m

Mtix = mlx = x 2,618 = 1,309 kN.m

Mtiy = mly = x 0,571 = 0,285 kN.m


Mlx2,618290,0830.0015142,5 10 250

Mly0,57179,0580.0025212,5 10 250

Mtix1,309145,0410.000766,5 10 250

Mtiy0,28539,5290.0025212,5 10 250

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Bab 4 Perhitungan Plat

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