11 lampiran per11 lampiran perhitunganhitungan
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Transcript of 11 lampiran per11 lampiran perhitunganhitungan
![Page 1: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/1.jpg)
Perhitungan persen ( % ) efek gigitan nyamuk :
1. Ekstrak maserasi tapak dara tua:
- 25 % → 311
X 100 = 0,2727 x 100 = 27,27 %
- 50 % → 411
X 100 = 0,3636 x 100 = 36,36 %
- 75 % → 511
X 100 = 0,4545 x 100 = 45,45 %
- 100 % → 611
X 100 = 0,5454 x 100 = 54,54 %
2. Ekstrak maserasi tapak dara muda :
- 25 % → 211
X 100 = 0,1818 x 100 = 18,18 %
- 50% →311
X 100 = 0,2727 x 100 = 27,27 %
- 75% → 511
X 100 = 0,4545 x 100 = 45,45 %
- 100% → 611
X 100 = 0,5454 x 100 = 54,54 %
3. Ektrak infusa tapak dara tua:
- 25 % → 411
X 100 = 0,3636 x 100 = 36,36 %
- 50 % → 511
X 100 = 0,4545 x 100 = 45,45 %
- 75% → 611
X 100 = 0,5454 x 100 = 54,54 %
- 100% → 711
X 100 = 0, 6363 x 100 = 63,63 %
![Page 2: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/2.jpg)
4. Ekstrak infusa tapak dara muda :
- 25% → 311
X 100 = 0,2727x 100 = 27,27
- 50% 4
X 100 = 0,3636x 100 = 36,36
11
- 75 % 5
11 X 100= 0,4545 x 100 = 45,45
- 100% 6
11 X 100 = 0,5454 x 100 = 54,54
Perhitungan exivalensi konsentrasi ekstrak tapak dara :
a. Konsentrasi ekstrak maserasi tapak dara tua
No X Y X2 X.Y
1
2
3
4
0,25
0,50
0,75
1
0,27
0,36
0,45
0,54
0,0625
0,25
0,5625
1
0,0675
0,18
0,3375
0,54
∑ 2,5 1,62 1,875 1,125
b = n ∑x.y - ∑ x . ∑ y n∑ x . y−∑x .∑ y❑
n . ∑x2 - ( ∑ x )2
![Page 3: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/3.jpg)
b = 4 . 1,125 – 2,5 . 1,62
4 . 1,875 – ( 2,5 )2
b = 4,5 – 4,05
7,5 – 6,25
b = 0,45
1,25
b = 0,36
a = ∑ y-b . ∑ x = 1,62 – 0,36 . 2,5 = 0,7875
n 4
y = a + b x
100 = 0,7875 + 0,36 x x = 100,7875 / 0,36
0,36 x = 100 + 0,7875 x = 279,9 %
0,36 x = 100,7875
b. Konsentrasi ekstrak infusa tapak dara tua
No X Y X2 X.Y
1
2
3
4
0,25
0,50
0,75
1
0,36
0,45
0,54
0,63
0,0625
0,25
0,5625
1
0,09
0,225
0,405
0,63
∑ 2,5 1,98 1,875 1,35
b = n ∑x . y - ∑ y
n . ∑ x2 - ( ∑ x )2
![Page 4: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/4.jpg)
b = 4. 1,35 – 2,5 . 1,98
4 . 1,875 – (2,5)2
b = 5,4 – 4,95
7,5- 6,25
b = 0,45
1,25
b = 0,36
a = ∑ y-b . ∑ X
n
a = 1,98 – 0,36 . 2,5 = 1,0125
4
y = a + b . x
100 = 1,0125 + 0,36 x x = 101,0125 / 0,36
0,36 x = 100 + 1,0125 x = 280,5 %
0,36 x = 101,0125
c. Konsentrasi ekstrak infusa tapak dara muda
N
o
X Y X2 X.Y
1
2
3
4
0,25
0,50
0,75
1
0,27
0,36
0,45
0,54
0,0625
0,25
0,5625
1
0,0675
0,18
0,3375
0,54
∑ 2,5 1,62 1,875 1,125
b = n ∑x.y - ∑ x . ∑ y
n . ∑x2 - ( ∑ x )2
![Page 5: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/5.jpg)
b = 4 . 1,125 – 2,5 . 1,62
4 . 1,8745 – ( 2,5 )2
b = 4,5 – 4,05
7,5 – 6,25
b = 0,45
1,25
b = 0,36
a = ∑ y-b . ∑ x = 1,62 – 0,36 . 2,5 = 0,7875
n 4
y = a + b . x
100 = 0,7875 + 0,36 x x = 100,7875 / 0,36
0,36 x = 100 + 0,7875 x = 279,9 %
0,36 x = 100,7875
d. Konsentrasi ekstrak maserasi tapak dara muda
No X Y X2 X.Y
1
2
3
4
0,25
0,50
0,75
1
0,18
0,27
0,45
0,54
0,0625
0,25
0,5625
1
0,045
0.135
0,3375
0,54
∑ 2,5 1,44 1,875 1,0575
![Page 6: 11 lampiran per11 lampiran perhitunganhitungan](https://reader036.fdokumen.com/reader036/viewer/2022082417/55cf8d165503462b1391fb8c/html5/thumbnails/6.jpg)
b = n ∑x.y - ∑ x . ∑ y
n . ∑x2 - ( ∑ x )2
b = 4 . 1,0575 - 2,5. 1,44
4 . 1,875 – ( 2,5 )2
b= 4,23 – 3,6
7,5 – 6,25
b = 0,63
1,25
b = 0,504
a = ∑ . y - b . ∑ x = 1,44 – 0,504 . 2,5 = 0,585
n 4
y = a + b . x
100 = 0,585 + 0,054 x x = 100,585 / 0,504
0,504 x = 100 + 0,585 x = 199,5 %
0,504 x =100,585